[c++] Rules for C++ string literals escape character

\0 will be interpreted as an octal escape sequence if it is followed by other digits, so \00 will be interpreted as a single character. (\0 is technically an octal escape sequence as well, at least in C).

The way you're doing it:

std::string ("0\0" "0", 3)  // String concatenation 

works because this version of the constructor takes a char array; if you try to just pass "0\0" "0" as a const char*, it will treat it as a C string and only copy everything up until the null character.

Here is a list of escape sequences.

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