After getting feedback, It seems the original solution didn't work. That's why updated the answer as one of the suggestions.
def float_of_2_decimal(float_n)
float_n.to_d.round(2, :truncate).to_f
end
Other answers may work, if you want to have rounded numbers of 2 decimal places. But, If you want to have floating point numbers with first two decimal places without rounding, Those answers won't help.
So, to get a floating point number with first two decimal places, I used this technique. Doesn't work in some cases
def float_of_2_decimal(float_n)
float_n.round(3).to_s[0..3].to_f
end
with 5.666666666666666666666666
, it will return 5.66
instead of rounded 5.67
. Hope it will help someone
(5.65235534).round(2)
#=> 5.65
to truncate a decimal I've used the follow code:
<th><%#= sprintf("%0.01f",prom/total) %><!--1dec,aprox-->
<% if prom == 0 or total == 0 %>
N.E.
<% else %>
<%= Integer((prom/total).to_d*10)*0.1 %><!--1decimal,truncado-->
<% end %>
<%#= prom/total %>
</th>
If you want to truncate to 2 decimals, you should use Integr(a*100)*0.01
sprintf('%.2f', number)
is a cryptic, but very powerful way of formatting numbers. The result is always a string, but since you're rounding I assume you're doing it for presentation purposes anyway. sprintf
can format any number almost any way you like, and lots more.
Full sprintf documentation: http://www.ruby-doc.org/core-2.0.0/Kernel.html#method-i-sprintf
Try this:
module Util
module MyUtil
def self.redondear_up(suma,cantidad, decimales=0)
unless suma.present?
return nil
end
if suma>0
resultado= (suma.to_f/cantidad)
return resultado.round(decimales)
end
return nil
end
end
end
Source: Stackoverflow.com