String to HashMap JAVA

Question

I have a Java Property file and there is a KEY as ORDER  So I retrieve the VALUE of that KEY using the getProperty   method after loading the property file like below    String s   prop getProperty  ORDER      then  s   SALES 0 SALE PRODUCTS 1 EXPENSES 2 EXPENSES ITEMS 3     I need to create a HashMap from above string  SALES SALE PRODUCTS EXPENSES EXPENSES ITEMS should be KEY of HashMap  and 0 1 2 3  should be VALUEs of KEYs   If it s hard corded  it seems like below   Map lt String  Integer gt  myMap    new HashMap lt String  Integer gt     myMap put  SALES   0   myMap put  SALE PRODUCTS   1   myMap put  EXPENSES   2   myMap put  EXPENSES ITEMS   3

User · Answer

USING JAVA 8  Map lt String  String gt  headerMap   Arrays stream header split  quot   quot                         map s - gt  s split  quot   quot                         collect Collectors toMap s - gt  s 0   s - gt  s 1

User · Answer

You can also use JSONObject class from json org to this will convert your HashMap to JSON string which is well formatted  Example   Map lt String Object gt  map   new HashMap lt  gt     map put  myNumber   100   map put  myString    String     JSONObject json  new JSONObject map    String result  json toString     System out print result     result     myNumber  100   myString   String     Your can also get key from it like  System out print json get  myNumber       result   100

User · Answer

I recommend using com fasterxml jackson databind ObjectMapper  Maven repo link  https   mvnrepository com artifact com fasterxml jackson core  like  final ObjectMapper mapper   new ObjectMapper    Map lt String  Object gt  mapFromString   new HashMap lt  gt     try       mapFromString   mapper readValue theStringToParse  new TypeReference lt Map lt String  Object gt  gt                    catch  IOException e        LOG error  Exception launched while trying to parse String to Map    e

User · Answer

You can to use split to do it    String   elements   s split        for String s1  elements         String   keyValue   s1 split            myMap put keyValue 0   keyValue 1         Nevertheless  myself I will go for guava based solution  https   stackoverflow com a 10514513 1356883

User · Answer

Assuming no key contains either     or       Map lt String  Integer gt  map   new HashMap lt String  Integer gt     for final String entry   s split             final String   parts   entry split           assert parts length    2     Invalid entry      entry      map put parts 0   new Integer parts 1

User · Answer

You can do that with Guava s Splitter MapSplitter   Map lt String  String gt  properties   Splitter on      withKeyValueSeparator      split inputString

User · Answer

Use StringTokenizer to parse the string   String s   SALES 0 SALE PRODUCTS 1 EXPENSES 2 EXPENSES ITEMS 3       Map lt String  Integer gt  lMap new HashMap lt String  Integer gt           StringTokenizer st new StringTokenizer s            while st hasMoreTokens                  String    array st nextToken   split               lMap put array 0   Integer valueOf array 1

User · Answer

In one line      HashMap lt String  Integer gt  map    HashMap lt String  Integer gt   Arrays asList str split       stream   map s - gt  s split       collect Collectors toMap e - gt  e 0   e - gt  Integer parseInt e 1        Details   1  Split entry pairs and convert string array to List lt String gt  in order to use java lang Collection Stream API from Java 1 8  Arrays asList str split         2  Map the resulting string list  key value  to a string array with  0  as key and  1  as value  map s - gt  s split         3  Use collect terminal method from stream API to mutate   collect Collector lt   super String  Object  Map lt Object  Object gt  gt  collector    4  Use the Collectors toMap   static method which take two Function to perform mutation from input type to key and value type   toMap Function lt   super T   extends K gt  keyMapper  Function lt   super T   extends U gt  valueMapper    where T is the input type  K the key type and U the value type   5  Following lambda mutate String to String key and String to Integer value  toMap e - gt  e 0   e - gt  Integer parseInt e 1       Enjoy the stream and lambda style with Java 8  No more loops

User · Answer

Use the String split   method with the   separator to get the list of pairs  Iterate the pairs and use split   again with the   separator to get the key and value for each pair   Map lt String  Integer gt  myMap   new HashMap lt String  Integer gt     String s    SALES 0 SALE PRODUCTS 1 EXPENSES 2 EXPENSES ITEMS 3   String   pairs   s split       for  int i 0 i lt pairs length i          String pair   pairs i       String   keyValue   pair split           myMap put keyValue 0   Integer valueOf keyValue 1

User · Answer

try    String s    SALES 0 SALE PRODUCTS 1 EXPENSES 2 EXPENSES ITEMS 3       HashMap lt String Integer gt  hm  new HashMap lt String Integer gt         for String s1 s split               String   s2   s1 split               hm put s2 0   Integer parseInt s2 1

[java] String to HashMap JAVA

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