I got the following entry in my database:
images/test.jpg
I want to trim the entry so I get: test
So basically, I want everything after /
and before .
How can I solve it?
This question is related to
sql
sql-server
I found Royi Namir's answer useful but expanded upon it to create it as a function. I renamed the variables to what made sense to me but you can translate them back easily enough, if desired.
Also, the code in Royi's answer already handled the case where the character being searched from does not exist (it starts from the beginning of the string), but I wanted to also handle cases where the character that is being searched to does not exist.
In that case it acts in a similar manner by starting from the searched from character and returning the rest of the characters to the end of the string.
CREATE FUNCTION [dbo].[getValueBetweenTwoStrings](@inputString
NVARCHAR(4000), @stringToSearchFrom NVARCHAR(4000), @stringToSearchTo
NVARCHAR(4000))
RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE @retVal NVARCHAR(4000)
DECLARE @stringToSearchFromSearchPattern NVARCHAR(4000) = '%' +
@stringToSearchFrom + '%'
SELECT @retVal = SUBSTRING (
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom),
(CASE
CHARINDEX(
@stringToSearchTo,
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
WHEN
0
THEN
LEN(@inputString) + 1
ELSE
CHARINDEX(
@stringToSearchTo,
@inputString,
PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
END) - (PATINDEX(@stringToSearchFromSearchPattern, @inputString) + LEN(@stringToSearchFrom))
)
RETURN @retVal
END
Usage:
SELECT dbo.getValueBetweenTwoStrings('images/test.jpg','/','.') AS MyResult
Before
SELECT SUBSTRING(ParentBGBU,0,CHARINDEX('/',ParentBGBU,0)) FROM dbo.tblHCMMaster;
After
SELECT SUBSTRING(ParentBGBU,CHARINDEX('-',ParentBGBU)+1,LEN(ParentBGBU)) FROM dbo.tblHCMMaster
use the following function
left(@test, charindex('/', @test) - 1)
SELECT SUBSTRING('[email protected]',1,(CHARINDEX('@','[email protected]')-1)) Before, RIGHT('[email protected]',(CHARINDEX('@','[email protected]')+1)) After
if Input= pg102a-wlc01s.png.intel.com and Output should be pg102a-wlc01s
we can use below query :
select Substring(pc.name,0,charindex('.',pc.name,0)),pc.name from tbl_name pc
----select characters before / including /
select SUBSTRING ('abcde/wxyz',0,CHARINDEX('/','abcde/wxyz')+1)
--select characters after / including /
select SUBSTRING('abcde/wxyz',CHARINDEX('/','abcde/wxyz'),LEN('abcde/wxyz'))
I just did this in one of my reports and it was very simple.
Try this:
=MID(Fields!.Value,8,4)
Note: This worked for me because the value I was trying to get was a constant not sure it what you are trying to get is a constant as well.
I have made a method which is much more general :
so :
DECLARE @a NVARCHAR(MAX)='images/test.jpg';
--Touch here
DECLARE @keysValueToSearch NVARCHAR(4000) = '/'
DECLARE @untilThisCharAppears NVARCHAR(4000) = '.'
DECLARE @keysValueToSearchPattern NVARCHAR(4000) = '%' + @keysValueToSearch + '%'
--Nothing to touch here
SELECT SUBSTRING(
@a,
PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch),
CHARINDEX(
@untilThisCharAppears,
@a,
PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch)
) -(PATINDEX(@keysValueToSearchPattern, @a) + LEN(@keysValueToSearch))
)
I know this has been a while.. but here is an idea
declare @test varchar(25) = 'images/test.jpg'
select
@test as column_name
, parsename(replace(@test,'/','.'),1) as jpg
,parsename(replace(@test,'/','.'),2) as test
,parsename(replace(@test,'/','.'),3) as images
I got some invalid length errors. So i made this function, this should not give any length problems. Also when you do not find the searched text it will return a NULL.
CREATE FUNCTION [FN].[SearchTextGetBetweenStartAndStop](@string varchar(max),@SearchStringToStart varchar(max),@SearchStringToStop varchar(max))
RETURNS varchar(max)
BEGIN
SET @string = CASE
WHEN CHARINDEX(@SearchStringToStart,@string) = 0
OR CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart))) = 0
THEN NULL
ELSE SUBSTRING(@string
,CHARINDEX(@SearchStringToStart,@string) + LEN(@SearchStringToStart) + 1
,(CHARINDEX(@SearchStringToStop,RIGHT(@string,LEN(@string) - CHARINDEX(@SearchStringToStart,@string) + 1 - LEN(@SearchStringToStart)))-2)
)
END
RETURN @string
END
Simply Try With LEFT ,RIGHT ,CHARINDEX
select
LEFT((RIGHT(a.name,((CHARINDEX('/', name))+1))),((CHARINDEX('.', (RIGHT(a.name,
((CHARINDEX('/', name))+1)))))-1)) splitstring,
a.name
from
(select 'images/test.jpg' as name)a
You can try this:
Declare @test varchar(100)='images/test.jpg'
Select REPLACE(RIGHT(@test,charindex('/',reverse(@test))-1),'.jpg','')
Below query gives you data before '-' Ex- W12345A-4S
SELECT SUBSTRING(Column_Name,0, CHARINDEX('-',Column_Name)) as 'new_name'
from [abc].
Output - W12345A
declare @T table
(
Col varchar(20)
)
insert into @T
Select 'images/test1.jpg'
union all
Select 'images/test2.png'
union all
Select 'images/test3.jpg'
union all
Select 'images/test4.jpeg'
union all
Select 'images/test5.jpeg'
Select substring( LEFT(Col,charindex('.',Col)-1),charindex('/',Col)+1,len(LEFT(Col,charindex('.',Col)-1))-1 )
from @T
Inspired by the work of Josien, I wondered about a simplification.
Would this also work? Much shorter:
SELECT SUBSTRING(col, CHARINDEX ('/', col) + 1, CHARINDEX ('.', col) - CHARINDEX ('/', col) - 1);
(I can't test right now because of right issues at my company SQL server, which is a problem in its own right)
Source: Stackoverflow.com