Generate a sequence of numbers in Python

Question

How can I generate the sequence of numbers  1 2 5 6 9 10        and so until 100 in Python  I even need the comma       included  but this is not the main problem   The sequence  every number from 1  100  divisible by 4 with remainder 1 or 2

User · Answer

using numpy and list comprehension you can do the  import numpy as np  num for num in np arange 1 101  if  num 4    1 or num 4    2

User · Answer

Assuming I ve guessed the pattern correctly  alternating increments of 1 and 3   this should produce the desired result   def sequence        res          diff   1     x   1     while x  lt   100          res append x          x    diff         diff   3 if diff    1 else 1     return      join res

User · Answer

Assuming your sequence alternates increments between 1 and 3  numbers    1  while numbers -1   lt  100      numbers append numbers -1    1      numbers append numbers -1    3   print      join map str  numbers     This could be easier to modify if your sequence is different but I think poke or BlaXpirit are nicer answers than mine

User · Answer

gt  gt  gt      join         format i  i   1  for i in range 1  100  4    1 2 5 6 9 10 13 14 17 18 21 22 25 26 29 30 33 34 37 38 41 42 45 46 49 50 53 54 57 58 61 62 65 66 69 70 73 74 77 78 81 82 85 86 89 90 93 94 97 98    That was a quick and quite dirty solution   Now  for a solution that is suitable for different kinds of progression problems   def deltas        while True          yield 1         yield 3 def numbers start  deltas  max       i   start     while i  lt   max          yield i         i    next deltas  print     join str i  for i in numbers 1  deltas    100      And here are similar ideas implemented using itertools   from itertools import cycle  takewhile  accumulate  chain  def numbers start  deltas  max       deltas   cycle deltas      numbers   accumulate chain  start   deltas       return takewhile lambda x  x  lt   max  numbers   print     join str x  for x in numbers 1   1  3   100

User · Answer

In python 3 1 you can produce a list in a way       lst list range 100        for i in range 100          print  lst i      end       In python 2 7 you can do it as        lst range 100       for i in range 100          print lst i

User · Answer

Write a function that takes a number as an argument and prints the Fibonacci series till that number  def Series n         a   0       b   1       print a        print b        S   0       for i in range 0 n             if S  lt   n-1                S   a   b               print S                a   b               b   S

User · Answer

Includes some guessing on the exact sequence you are expecting    gt  gt  gt  l   list range 1  100  4     list range 2  100  4    gt  gt  gt  l sort    gt  gt  gt      join map str  l    1 2 5 6 9 10 13 14 17 18 21 22 25 26 29 30 33 34 37 38 41 42 45 46 49 50 53 54 57 58 61 62 65 66 69 70 73 74 77 78 81 82 85 86 89 90 93 94 97 98    As one-liner    gt  gt  gt      join map str  sorted list range 1  100  4      list range 2  100  4        btw  this is Python 3 compatible

User · Answer

This works by exploiting the   properties of the list rather than the increments   for num in range 1 100       if num   4    1 or num   4   2          n append num          continue     pass

User · Answer

Every number from 1 2 5 6 9 10    is divisible by 4 with remainder 1 or 2    gt  gt  gt      join str i  for i in xrange 100  if i   4 in  1 2    1 2 5 6 9 10 13 14

[python] Generate a sequence of numbers in Python

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