Convert Current date to integer

Question

I want to convert the current date to integer value  By default  it returns long  When I try to convert long to integer  and afterwards I convert the integer value to date  means it shows 1970 s date    int i    int  new Date   getTime     System out println  Integer       i    System out println  Long      new Date   getTime      System out println  Long date       new Date new Date   getTime       System out println  Int Date       new Date i      the output as follows   Integer   1292838124 Long   1345617601771 Long date   Wed Aug 22 12 10 01 IST 2012 Int Date   Fri Jan 16 04 37 18 IST 1970   Any one please help me out  how to convert current date to integer 10 digit number

User · Answer

Simple really create a long variable that represents a default start date for your program Get the date to another long variable  Then deduct the long start date and convert to a integer voila To read and convert back just add  rather than subtract  obviously this is dependant on how large a date range you require

User · Answer

Probably You can not  Long is higher datatype than Integer   or this link might help you  http   www velocityreviews com forums t142373-convert-date-to-integer-and-back html

User · Answer

I ve solved this as is shown below       long year   calendar get Calendar YEAR       long month   calendar get Calendar MONTH    1      long day   calendar get Calendar DAY OF MONTH       long calcDate   year   100   month      calcDate   calcDate   100   day      System out println  int      calcDate

User · Answer

Try This   Calendar currentDay  Calendar getInstance    int currDate  currentDay get Calendar DATE   int currMonth  currentDay get Calendar MONTH   int currYear  currentDay get Calendar YEAR   System out println currDate    -     currMonth    -    currYear     an alternative way using LocalDate   LocalDate today   LocalDate now    int currentDate  today getDayOfMonth    int currentMonth  today getMonthValue    int currentYear  today getYear

User · Answer

Your Problem is because of getTime     it always return following      Returns the number of milliseconds since January 1  1970  00 00 00 GMT represented by this Date object    Because the max integer value is less then the return value by getTime   that why is showing  wrong result

User · Answer

In order to get current date as integer 10 digit number   you need to divide the long returned from new Date   getTime   by 1000   This will be in int range and is good until 18 Jan 2038

User · Answer

Java Date to int conversion    public static final String DATE FORMAT INT    yyyyMMdd    public static String format Date date  String format        return isNull date          null   new SimpleDateFormat format  format date      public static Integer getDateInt Date date        if  isNull date             throw new IllegalArgumentException  Date must not be NULL               return parseInt format date  DATE FORMAT INT

User · Answer

If you need only an integer representing elapsed days since Jan  1  1970  you can try these      magic number     millisec   sec   min   hours    1000   60   60   24   86400000 public static final long MAGIC 86400000L   public int DateToDays  Date date           convert a date to an integer and back again     long currentTime date getTime        currentTime currentTime MAGIC      return  int  currentTime      public Date DaysToDate int days            convert integer back again to a date     long currentTime  long  days MAGIC      return new Date currentTime       Shorter but less readable  slightly faster     public static final long MAGIC 86400000L   public int DateToDays  Date date       return  int   date getTime   MAGIC      public Date DaysToDate int days        return new Date  long  days MAGIC       Hope this helps   EDIT  This could work until Fri Jul 11 01 00 00 CET 5881580

User · Answer

tl dr  Instant now   getEpochSecond       The number of seconds from the Java epoch of 1970-01-01T00 00 00Z    Details  As others stated  a 32-bit integer cannot hold a number big enough for the number of seconds from the epoch  beginning of 1970 in UTC  and now  You need 64-bit integer  a long primitive or Long object     java time  The other answers are using old legacy date-time classes  They have been supplanted by the java time classes   The Instant class represents a moment on the timeline in UTC with a resolution of nanoseconds   Instant now   instant now       You can interrogate for the number of milliseconds since the epoch  Beware this means a loss of data  truncating nanoseconds to milliseconds   long millisecondsSinceEpoch   now toEpochMilli       If you want a count of nanoseconds since epoch  you will need to do a bit of math as the class oddly lacks a toEpochNano method  Note the L appended to the billion to provoke the calculation as 64-bit long integers   long nanosecondsSinceEpoch     instant getEpochSecond     1 000 000 000L     instant getNano       Whole seconds since epoch  But the end of the Question asks for a 10-digit number  I suspect that means a count of whole seconds since the epoch of 1970-01-01T00 00 00  This is commonly referred to as Unix Time or Posix Time   We can interrogate the Instant for this number  Again  this means a loss of data with the truncation of any fraction-of-second this object may hold   long secondsSinceEpoch   now getEpochSecond         The number of seconds from the Java epoch of 1970-01-01T00 00 00Z      About java time  The java time framework is built into Java 8 and later  These classes supplant the troublesome old legacy date-time classes such as java util Date  Calendar   amp  SimpleDateFormat   The Joda-Time project  now in maintenance mode  advises migration to the java time classes   To learn more  see the Oracle Tutorial  And search Stack Overflow for many examples and explanations  Specification is JSR 310   You may exchange java time objects directly with your database  Use a JDBC driver compliant with JDBC 4 2 or later  No need for strings  no need for java sql   classes   Where to obtain the java time classes     Java SE 8  Java SE 9  Java SE 10  Java SE 11  and later  - Part of the standard Java API with a bundled implementation    Java 9 adds some minor features and fixes   Java SE 6 and Java SE 7   Most of the java time functionality is back-ported to Java 6  amp  7 in ThreeTen-Backport   Android   Later versions of Android bundle implementations of the java time classes  For earlier Android   lt 26   the ThreeTenABP project adapts ThreeTen-Backport  mentioned above   See How to use ThreeTenABP        The ThreeTen-Extra project extends java time with additional classes  This project is a proving ground for possible future additions to java time  You may find some useful classes here such as Interval  YearWeek  YearQuarter  and more

User · Answer

Do you need something like this without time    public static Integer toJulianDate Date pDate    if  pDate    null      return null    Calendar lCal   Calendar getInstance    lCal setTime pDate   int lYear   lCal get Calendar YEAR   int lMonth   lCal get Calendar MONTH    1  int lDay   lCal get Calendar DATE   int a    14 - lMonth    12  int y   lYear   4800 - a  int m   lMonth   12   a - 3  return lDay    153   m   2    5   365   y   y   4 - y   100   y   400 - 32045

User · Answer

The issue is that an Integer is not large enough to store a current date  you need to use a Long   The date is stored internally as the number of milliseconds since 1 1 1970   The maximum Integer value is 2147483648  whereas the number of milliseconds since 1970 is currently in the order of 1345618537869  Putting the maximum integer value into a date yields Monday 26th January 1970   Edit  Code to display division by 1000 as per comment below       int i    int   new Date   getTime   1000       System out println  Integer       i       System out println  Long      new Date   getTime         System out println  Long date       new Date new Date   getTime          System out println  Int Date       new Date   long i  1000L     Integer   1345619256 Long   1345619256308 Long date   Wed Aug 22 16 37 36 CST 2012 Int Date   Wed Aug 22 16 37 36 CST 2012

User · Answer

On my Java 7  the output is different   Integer   1293732698 Long   1345618496346 Long date   Wed Aug 22 10 54 56 MSK 2012 Int Date   Fri Jan 16 02 22 12 MSK 1970   which is an expected behavior   It is impossible to display the current date in milliseconds as an integer  10 digit number   because the latest possible date is Sun Apr 26 20 46 39 MSK 1970   Date d   new Date 9999 9999 99L   System out println  Date      d    Date  Sun Apr 26 20 46 39 MSK 1970   You might want to consider displaying it in seconds minutes

[java] Convert Current date to integer

Examples related to java

Examples related to date