Why can t I enter a string in Scanner System in when calling nextLine -method

Question

How does this program actually work      import java util Scanner   class string       public static void main String a             int a          String s          Scanner scan   new Scanner System in            System out println  enter a no            a   scan nextInt            System out println  no is    a            System out println  enter a string            s   scan nextLine            System out println  string is   s             The output is   enter the no 1234 no is 1234 enter a string string is            why is it not allowing me to enter a string here

User · Answer

Scanner s buffer full when we take a input string through scan nextLine    so it skips the input next time   So solution is that we can create a new object of Scanner   the name of the object can be same as previous object

User · Answer

This is a common misunderstanding which leads to confusion if you use the same Scanner for nextLine   right after you used nextInt     You can either fix the cursor jumping to the next Line by yourself or just use a different scanner for your Integers   OPTION A  use 2 different scanners  import java util Scanner   class string        public static void main String a         int a      String s      Scanner intscan  new Scanner System in         System out println  enter a no        a intscan nextInt        System out println  no is    a          Scanner textscan new Scanner System in       System out println  enter a string        s textscan nextLine        System out println  string is   s                 OPTION B  just jump to the next Line  class string       public static void main String a             int a          String s          Scanner scan  new Scanner System in            System out println  enter a no            a   scan nextInt            System out println  no is    a           scan nextLine             System out println  enter a string            s   scan nextLine            System out println  string is   s

User · Answer

Don t try to scan text with nextLine    AFTER using nextInt   with the same scanner  It doesn t work well with Java Scanner  and many Java developers opt to just use another Scanner for integers  You can call these scanners scan1 and scan2 if you want

User · Answer

Incase you don t want to use nextint  you can also use buffered reader  where using inputstream and readline function read the string

User · Answer

import java util     public class ScannerExample        public static void main String args              int a          String s          Scanner scan   new Scanner System in            System out println  enter a no            a   scan nextInt            System out println  no is      a            System out println  enter a string            s   scan next            System out println  string is     s

User · Answer

use a temporary scan nextLine    this will consume the   n character

User · Answer

You only need to use scan next   to read a String

User · Answer

Simple solution to consume the  n character   import java util Scanner  class string       public static void main String a             int a          String s          Scanner scan   new Scanner System in            System out println  enter a no            a   scan nextInt            System out println  no is    a            scan nextLine            System out println  enter a string            s   scan nextLine            System out println  string is   s

User · Answer

This is because after the nextInt   finished it s execution  when the nextLine   method is called  it scans the newline character of which was present after the nextInt    You can do this in either of the following ways    You can use another nextLine   method just after the nextInt   to move the scanner past the newline character  You can use different Scanner objects for scanning the integer and string  You can name them scan1 and scan2   You can use the next method on the scanner object as  scan next

User · Answer

s scan nextLine      It returns input was skipped   so you might use    s scan next

User · Answer

nextInt   gets the next int  but doesn t read the new line character  This means that when you ask it to read the  next line   you read til the end of the new line character from the first time    You can insert another  nextLine   after you get the int to fix this  Or  I prefer this way   read the int in as a string  and parse it to an int

User · Answer

if you don t want to use parser    int a  String s  Scanner scan   new Scanner System in    System out println  enter a no    a   scan nextInt    System out println  no is      a   scan nextLine       This line you have to add  It consumes the  n character  System out println  enter a string    s   scan nextLine    System out println  string is     s

[java] Why can't I enter a string in Scanner(System.in), when calling nextLine()-method?

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