This topic is actually a little more complicated as described in the answers so far. This blogpost by Rob Norris explains it in more detail and gives examples on when using return will actually break your code (or at least have non-obvious effects).
At this point let me just quote the essence of the post. The most important statement is right in the beginning. Print this as a poster and put it to your wall :-)
The
return
keyword is not “optional” or “inferred”; it changes the meaning of your program, and you should never use it.
It gives one example, where it actually breaks something, when you inline a function
// Inline add and addR
def sum(ns: Int*): Int = ns.foldLeft(0)((n, m) => n + m) // inlined add
scala> sum(33, 42, 99)
res2: Int = 174 // alright
def sumR(ns: Int*): Int = ns.foldLeft(0)((n, m) => return n + m) // inlined addR
scala> sumR(33, 42, 99)
res3: Int = 33 // um.
because
A
return
expression, when evaluated, abandons the current computation and returns to the caller of the method in whichreturn
appears.
This is only one of the examples given in the linked post and it's the easiest to understand. There're more and I highly encourage you, to go there, read and understand.
When you come from imperative languages like Java, this might seem odd at first, but once you get used to this style it will make sense. Let me close with another quote:
If you find yourself in a situation where you think you want to return early, you need to re-think the way you have defined your computation.