How to show and update echo on same line

Question

I have the following in Bash  In Linux   for dir in Movies   do    cd   dir   amp  amp  pwd cut -d    -f5 tr -s   n        gt  gt        movielist  amp  amp    exiftool   -t -s3 -ImageSize -FileType tr -s   t       gt  gt        movielist   echo  Movie  movies -  dir ADDED   let movies movies 1 done   But I wish to make it so the  echo  shows the following echo on the next line  Not concatenate with the last echo output but replace it  so to make it look like it is updating  Similar to how a progress bar with percent would show on the same line

User · Answer

This is vary useful please try it and change as required     bin bash for load in   seq 1 100   do     echo -ne  quot  load   downloded     r quot      sleep 1 done echo  quot 100 quot  echo  quot Loaded     quot

User · Answer

You can try this   My own version of it    funcc     while true   do  for i in        -           -     do    echo -n -e   r 1   i    sleep 0 5 done    echo -e   r                                                                                          -f  tmp print-stat    amp  amp  break 2 done    funcc  Checking Kubectl   amp   amp  gt  dev null sleep 5 touch  tmp print-stat echo -e   rPrint Success

User · Answer

I use printf  is shorter as it doesn t need flags to do the work  printf  quot  rMy static  myvars composed text quot

User · Answer

If I have understood well  you can get it replacing your echo with the following line   echo -ne  Movie  movies -  dir ADDED   033 0K r    Here is a small example that you can run to understand its behaviour      bin bash for pc in   seq 1 100   do     echo -ne   pc  033 0K r      sleep 1 done echo

User · Answer

My favorite way is called do the sleep to 50   here i variable need to be used inside echo statements   for i in   seq 1 50   do   echo -ne   i  033 0K r    sleep 50 done echo  ended

User · Answer

Well I did not read correctly the man echo page for this   echo had 2 options that could do this if I added a 3rd escape character   The 2 options are -n and -e   -n will not output the trailing newline  So that saves me from going to a new line each time I echo something   -e will allow me to interpret backslash escape symbols   Guess what escape symbol I want to use for this   r  Yes  carriage return would send me back to the start and it will visually look like I am updating on the same line   So the echo line would look like this   echo -ne  Movie  movies -  dir ADDED    r  I had to escape the escape symbol so Bash would not kill it  that is why you see 2   symbols in there   As mentioned by William  printf can also do similar  and even more extensive  tasks like this

User · Answer

The rest of answers are pretty good  but just wanted to add some extra information in case someone comes here looking for a solution to replace update a multiline echo    So I would like to share an example with you all  The following script was tried on a CentOS system and uses  timedatectl  command which basically prints some  detailed time information of your system   I decided to use that command as its output contains multiple lines and works perfectly for the example below      bin bash while true  do   COMMAND   timedatectl   Save command result in a var    echo   COMMAND   Print command result  including new lines     sleep 3  Keep above s output on screen during 3 seconds before clearing it     Following code clears previously printed lines   LINES   echo   COMMAND    wc -l   Calculate number of lines for the output previously printed   for    i 1  i  lt       LINES    i      do  For each line printed as a result of  timedatectl      tput cuu1  Move cursor up by one line     tput el  Clear the line   done  done   The above will print the result of  timedatectl  forever and will replace the previous echo with updated results   I have to mention that this code is only an example  but maybe not the best solution for you depending on your needs  A similar command that would do almost the same  at least visually  is  watch -n 3 timedatectl     But that s a different story      Hope that helps

[bash] How to show and update echo on same line

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