[python] How do I shut down a python simpleHTTPserver?

So I'm trying to learn d3, and the wiki suggested that

To view the examples locally, you must have a local web server. Any web server will work; for example you can run Python's built-in server:

python -m SimpleHTTPServer 8888 &

Great... only now I have a server running... but at some point I think I should probably shut that down again.

Is there a better way of shutting it down than using kill <pid>? That seems like kind of a big hammer for a little job.

(I'm running Mac OS 10.6.8 (Snow Leopard))

FWIW: ctrl+c gives about 10 lines of traceback, complaining about being interrupted.

kill -3 <pid> gives a Finder warning in a separate window 'Python quit unexpectedly'.

The default kill <pid> and kill -15 <pid> are relatively clean (and simple).

Turns out there is a shutdown, but this must be initiated from another thread.

This solution worked for me: https://stackoverflow.com/a/22533929/573216

When you run a program as a background process (by adding an & after it), e.g.:

python -m SimpleHTTPServer 8888 &

If the terminal window is still open you can do:

jobs

To get a list of all background jobs within the running shell's process.

It could look like this:

$ jobs
[1]+  Running                 python -m SimpleHTTPServer 8888 &

To kill a job, you can either do kill %1 to kill job "[1]", or do fg %1 to put the job in the foreground (fg) and then use ctrl-c to kill it. (Simply entering fg will put the last backgrounded process in the foreground).

With respect to SimpleHTTPServer it seems kill %1 is better than fg + ctrl-c. At least it doesn't protest with the kill command.

The above has been tested in Mac OS, but as far as I can remember it works just the same in Linux.

Update: For this to work, the web server must be started directly from the command line (verbatim the first code snippet). Using a script to start it will put the process out of reach of jobs.

if you have started the server with

python -m SimpleHTTPServer 8888 

then you can press ctrl + c to down the server.

But if you have started the server with

python -m SimpleHTTPServer 8888 &

or

python -m SimpleHTTPServer 8888 & disown

you have to see the list first to kill the process,

run command

ps

or

ps aux | less

it will show you some running process like this ..

PID TTY          TIME CMD
7247 pts/3     00:00:00 python
7360 pts/3     00:00:00 ps
23606 pts/3    00:00:00 bash

you can get the PID from here. and kill that process by running this command..

kill -9 7247

here 7247 is the python id.

Also for some reason if the port still open you can shut down the port with this command

fuser -k 8888/tcp

here 8888 is the tcp port opened by python.

Hope its clear now.

Hitting ctrl + c once(wait for traceback), then hitting ctrl+c again did the trick for me :)

It seems like overkill but you can use supervisor to start and stop your simpleHttpserver, and completely manage it as a service.

Or just run it in the foreground as suggested and kill it with control c

MYPORT=8888; 
kill -9 `ps -ef |grep SimpleHTTPServer |grep $MYPORT |awk '{print $2}'`

That is it!

Explain command line :

• ps -ef : list all process.

• grep SimpleHTTPServer : filter process which belong to "SimpleHTTPServer"

• grep $MYPORT : filter again process belong to "SimpleHTTPServer" where port is MYPORT (.i.e: MYPORT=8888)

• awk '{print $2}' : print second column of result which is the PID (Process ID)

• kill -9 <PID> : Force Kill process with the appropriate PID.

or you can just do kill %1, which will kill the first job put in background