Replacing instances of a character in a string

Question

This simple code that simply tries to replace semicolons  at i-specified postions  by colons does not work   for i in range 0 len line         if  line i       and i in rightindexarray            line i        It gives the error   line i      TypeError   str  object does not support item assignment   How can I work around this to replace the semicolons by colons  Using replace does not work as that function takes no index- there might be some semicolons I do not want to replace   Example  In the string I might have any number of semicolons  eg  Hei der    Hello there       I know which ones I want to replace  I have their index in the string   Using replace does not work as I m not able to use an index with it

User · Answer

If you are replacing by an index value specified in variable  n   then try the below   def missing char str  n    str str replace str n        return str

User · Answer

Turn the string into a list  then you can change the characters individually  Then you can put it back together with  join   s    a b c d  slist   list s  for i  c in enumerate slist       if slist i         and 0  lt   i  lt   3    only replaces semicolons in the first part of the text         slist i        s      join slist  print s   prints a b c d

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My problem was that I had a list of numbers  and I only want to replace a part of that number  soy I do this  original list     08113    09106    19066    17056    17063    17053      With this part I achieve my goal cves mod      for i in range 0 len res list        cves mod append res list i  replace res list i  2     999    cves mod    Result cves mod   08999    09999    19999    17999    17999    17999

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If you want to replace a single semicolon   for i in range 0 len line     if  line i              line   line  i          line i 1     Havent tested it though

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names     quot Joey Tribbiani quot    quot Monica Geller quot    quot Chandler Bing quot    quot Phoebe Buffay quot    usernames       for i in names      if  quot   quot  in i          i   i replace  quot   quot    quot   quot       print i   Output  Joey Tribbiani Monica Geller Chandler Bing Phoebe Buffay

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Strings in python are immutable  so you cannot treat them as a list and assign to indices   Use  replace   instead   line   line replace             If you need to replace only certain semicolons  you ll need to be more specific  You could use slicing to isolate the section of the string to replace in   line   line  10  replace             line 10     That ll replace all semi-colons in the first 10 characters of the string

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I wrote this method to replace characters or replace strings at a specific instance  instances start at 0  this can easily be changed to 1 if you change the optional inst argument to 1  and test instance variable to 1   def replace instance some word  str to replace  new str     inst 0       return word          char index  test instance   0  0     while char index  lt  len some word           test str   some word char index  char index   len str to replace           if test str    str to replace              if test instance    inst                  return word   some word  char index    new str   some word char index   len str to replace                    break             else                  test instance    1         char index    1     return return word

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You can do this   string    this  is a  sample    python code      your desire string result      for i in range len string        s   string i      if  s        and i in  4  18  20     insert your desire list         s           result   result   s print result

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to use the  replace   method effectively on string without creating a separate list for example take a look at the list username containing string with some white space  we want to replace the white space with an underscore in each of the username string   usernames     Joey Tribbiani    Monica Geller    Chandler Bing    Phoebe Buffay     to replace the white spaces in each username consider using the range function in python   for i in range len usernames        usernames i    usernames i  lower   replace            print usernames

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To replace a character at a specific index  the function is as follows   def replace char s   n   c       n- 1     s   s 0 n    s n n 1  replace s n    c    s n 1       return s   where s is a string  n is index and c is a character

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You cannot simply assign value to a character in the string   Use this method to replace value of a particular character   name    India  result name  replace  d         Output  In ia  Also  if you want to replace say   for all the occurrences of the first character except the first character   eg  string   babble output   ba  le  Code   name    babble  front  name  0 1  fromSecondCharacter   name  1   back fromSecondCharacter replace front      return front back

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You can do the below  to replace any char with a respective char at a given index  if you wish not to use  replace    word    python  index   4 char    i   word   word  index    char   word index   1   print word  o p  pythin

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How about this   sentence    After 1500 years of that thinking surpressed   sentence   sentence lower    def removeLetter text char        result          for c in text          if c    char              result    c     return text replace char      text   removeLetter sentence  a

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This should cover a slightly more general case  but you should be able to customize it for your purpose  def selectiveReplace myStr       answer          for index char in enumerate myStr           if char                     if index 2    1    replace     in even indices with                     answer append                  else                  answer append        replace     in odd indices with             else              answer append char      return    join answer    Hope this helps

[python] Replacing instances of a character in a string

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