Removing numbers from string

Question

How can I remove digits from a string

User · Answer

What about this   out string   filter lambda c  not c isdigit    in string

User · Answer

Not sure if your teacher allows you to use filters but     filter lambda x  x isalpha     a1a2a3s3d4f5fg6h     returns-   aaasdffgh    Much more efficient than looping     Example   for i in range 10     a replace str i

User · Answer

Say st is your unformatted string  then run  st nodigits    join i for i in st if i isalpha      as mentioned above  But my guess that you need something very simple  so say s is your string and st res is a string without digits  then here is your code   l     0   1   2   3   4   5   6   7   8   9   st res    for ch in s   if ch not in l    st res  ch

User · Answer

I d love to use regex to accomplish this  but since you can only use lists  loops  functions  etc    here s what I came up with   stringWithNumbers  I have 10 bananas for my 5 monkeys   stringWithoutNumbers    join c if c not in map str range 0 10   else    for c in stringWithNumbers  print stringWithoutNumbers   I have  bananas for my  monkeys

User · Answer

And  just to throw it in the mix  is the oft-forgotten str translate which will work a lot faster than looping regular expressions   For Python 2   from string import digits  s    abc123def456ghi789zero0  res   s translate None  digits     abcdefghizero    For Python 3   from string import digits  s    abc123def456ghi789zero0  remove digits   str maketrans         digits  res   s translate remove digits     abcdefghizero

User · Answer

Just a few  others have suggested some of these   Method 1      join i for i in myStr if not i isdigit      Method 2   def removeDigits s       answer          for char in s          if not char isdigit                answer append char      return    join char    Method 3      join filter lambda x  not x isdigit    mystr     Method 4   nums   set map int  range 10       join i for i in mystr if i not in nums    Method 5      join i for i in mystr if ord i  not in range 48  58

User · Answer

Would this work for your situation     gt  gt  gt  s    12abcd405   gt  gt  gt  result      join  i for i in s if not i isdigit      gt  gt  gt  result  abcd    This makes use of a list comprehension  and what is happening here is similar to this structure   no digits        Iterate through the string  adding non-numbers to the no digits list for i in s      if not i isdigit            no digits append i     Now join all elements of the list with        which puts all of the characters together  result      join no digits    As  AshwiniChaudhary and  KirkStrauser point out  you actually do not need to use the brackets in the one-liner  making the piece inside the parentheses a generator expression  more efficient than a list comprehension   Even if this doesn t fit the requirements for your assignment  it is something you should read about eventually        gt  gt  gt  s    12abcd405   gt  gt  gt  result      join i for i in s if not i isdigit     gt  gt  gt  result  abcd

User · Answer

If i understand your question right  one way to do is break down the string in chars and then check each char in that string using a loop whether it s a string or a number and then if string save it in a variable and then once the loop is finished  display that to the user

[python] Removing numbers from string

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