uncaught syntaxerror unexpected token U JSON

Question

I get this error  uncaught syntaxerror unexpected token U  when I run my page in chrome  And in firefox I get   JSON parse  unexpected character   I m returning the json data from a php file and the returning json string is valid  I checked it with http   jsonlint com    Any help would be appreciated    Thanks   Here s the returned JSON string          1   Pan Africa Market     1521 1st Ave  Seattle  WA     47 608941   -122 340145   restaurant          2   The Melting Pot   14 Mercer St  Seattle  WA   47 624562   -122 356442   restaurant          3   Ipanema Grill   1225 1st Ave  Seattle  WA   47 606366   -122 337656   restaurant          4   Sake House   230 1st Ave  Seattle  WA   47 612825   -122 34567   bar          5   Crab Pot   1301 Alaskan Way  Seattle  WA   47 605961   -122 34036   restaurant          6   Mexican Kitchen   2234 2nd Ave  Seattle WA   47 613975   -122 345467   bar          7   Wingdome   1416 E Olive Way  Seattle  WA   47 617215   -122 326584   bar          8   Piroshky Piroshky   1908 Pike pl  Seattle  WA   47 610127   -122 342838   restaurant

User · Answer

That error is normally seen when the value given to JSON parse is actually undefined  So  I would check the code that is trying to parse this - most likely you are not parsing the actual string shown here

User · Answer

I was getting this error  when I was using the same variable for json string and parsed json    var json      1    url   somesite1   poster   1 png   title   site title    2    url   somesite2   poster   2 jpg   title   site 2 title      function usingjson        var json   JSON parse json       I changed function to    function usingjson        var j   JSON parse json       Now this error went away

User · Answer

The parameter for the JSON parse may be returning nothing  i e  the value given for the JSON parse is undefined    It happened to me while I was parsing the Compiled solidity code from an xyz sol file   import web3 from    web3   import xyz from    build xyz json    const i   new web3 eth Contract    JSON parse xyz interface      0x99Fd6eFd4257645a34093E657f69150FEFf7CdF5      export default i    which was misspelled as   JSON parse xyz intereface    which was returning nothing

User · Answer

This answer can be a possible solution from many  This answer is for the people who are facing this error while working with File Upload   We were using middleware for token based encryption - decryption and we encountered same error  Following was our code in route file    router route  quot  uploadVideoMessage quot      post      middleware checkToken      upload single  quot video file quot        videoMessageController uploadVideoMessage       here we were calling middleware before upload function and that was causing the error  So when we changed it to this  it worked  router route  quot  uploadVideoMessage quot      post      upload single  quot video file quot        middleware checkToken      videoMessageController uploadVideoMessage

User · Answer

Most common case of this error happening is using template that is generating the control then changing the way id and or nameare being generated by  overriding  default template with something like    Html TextBoxFor m   gt  m  new  Name   ViewData  Name    id   ViewData  UniqueId        and then forgetting to change ValidationMessageFor to   Html ValidationMessageFor m   gt  m  null  new   data valmsg for   ViewData  Name            Hope this saves you some time

User · Answer

I was getting this message while validating  in MVC project   For me  adding ValidationMessageFor element fixed the issue   To be precise  line number 43 in jquery validate unobtrusive js caused the issue     replace     parseJSON container attr  data-valmsg-replace        false

User · Answer

This is not a difficult task  That problem also occur at my site you should have to shift your js files top ordered  Because at the place where you are using JSON Parsing  this time your JS files are not loaded  EXAMPLE     lt script type  text javaScript  gt             SOME CODE               lt  script gt   lt script src   Url Content    Scripts jquery validate min js    type  text javascript  gt  lt  script gt    change to    lt script src   Url Content    Scripts jquery validate min js    type  text javascript  gt  lt  script gt   lt script type  text javaScript  gt             SOME CODE               lt  script gt

User · Answer

I experienced this error when I ran a find condition on a JSONArray within a for loop  The problem I faced was the result of one of the values in the for loop returning null  Hence  when I tried to access a property on that it failed    So if you are doing anything within JSONArrays where you are not sure of the data source and its integrity I thinks its a good habit to deal with null and undefined exceptions in this case    I fixed it by checking for null on the returned value of find on the JSONArray and handling exceptions appropriately   Thought this might help

User · Answer

Well  to all who actually can t find the error anywhere in your code  neither  undefined as it says in local storage nor null   simply just comment out your code and write another one that actually removes the item in local storage   after that  u can comment or delet the current code and   reset again the previous one by  simply uncommenting it out  if u dint delet t    if u did u can write it again      LocalStorage setItem  Previous     removeprevious        LocalStorage removeItem  Previous        Console log LocalStorage getItem  Previous       Console will show null and that it   reset your code again if t doesn t work  dude you got errors   sorry for my English

User · Answer

Just incase u didnt understand   e g is that lets say i have a JSON STRING   NOT YET A JSON OBJECT OR ARRAY   so if in javascript u parse the string as   var body      id   1     deleted at   null     open order          id   16       status    open    var jsonBody   JSON parse body open order     HERE THE ERROR NOW APPEARS BECAUSE THE STRING IS NOT A JSON OBJECT YET        TODO SO var jsonBody JSON parse body   PASS THE BODY FIRST THEN LATER USE THE jsonBody to get the open order  var OpenOrder jsonBody open order    Great answers above

User · Answer

In my case it was trying to call JSON parse   on an AJAX variable before the XHRResponse came back   EG   var response     get URL that returns a valid JSON string   var data   JSON parse response responseText     I replaced that with an example out of the jQuery site for   get    lt script type  text javascript  gt       var jqxhr     get   https   jira atlassian com rest api 2 project   function               alert   success                           done function       insert code to assign the projects from Jira to a div                  jqxhr   jqxhr responseJSON                  console log jqxhr                   var div   document getElementById  products                    for  i   0  i  lt  jqxhr length  i                          console log jqxhr i  name                       div innerHTML      lt b gt Product      jqxhr i  name     lt  b gt  lt BR  gt Key      jqxhr i  key     lt BR  gt                                      console log div               alert   second success                             fail function                 alert   error                             always function                 alert   finished                               Perform other work here                 Set another completion function for the request above         jqxhr always function               alert   second finished                  lt  script gt

[json] uncaught syntaxerror unexpected token U JSON

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