[sql] How to do join on multiple criteria, returning all combinations of both criteria

I am willing to bet that this is a really simple answer as I am a noob to SQL.

table 1 has column 1 (criteria 1) column 2 (criteria 2) column 3 (metric 1)

table 2 has column 1 (criteria 1) column 2 (criteria 2) column 3 (metric 2 specific to table2.criteria2)

There can be anywhere from 1 - 5 values of criteria 2 for each criteria 1 on the table.

when I use the join statement here (assuming I identify table 1 as One prior to this):

Select WeddingTable, TableSeat, TableSeatID, Name, Two.Meal
FROM table1 as One
inner join table2 as Two
on One.WeddingTable = Two.WeddingTable and One.TableSeat = Two.TableSeat

I only get one of the criteria 1/criteria 2 combinations even when I know for a fact that there are 3 or 4. How do I get all combinations?

Take the situation where there is a wedding where table 1 is basically a seating chart, and table 2 is the meal option that each table/seat has chosen. Table 1 has the convenient TableSeatID, but Table 2 does not have a comparable ID.

Sample Data:

The results needs to show all 4 lines, being all 3 seats at WeddingTable 001 and the one seat at WeddingTable 002.

Desired Results:

It sounds like you want to list all the metrics?

SELECT Criteria1, Criteria2, Metric1 As Metric
FROM Table1
UNION ALL
SELECT Criteria1, Criteria2, Metric2 As Metric
FROM Table2
ORDER BY 1, 2

If you only want one Criteria1+Criteria2 combination, group them:

SELECT Criteria1, Criteia2, SUM(Metric) AS Metric
FROM (
    SELECT Criteria1, Criteria2, Metric1 As Metric
    FROM Table1
    UNION ALL
    SELECT Criteria1, Criteria2, Metric2 As Metric
    FROM Table2
)
ORDER BY Criteria1, Criteria2

SELECT  aa.*,
        bb.meal
FROM    table1 aa
        INNER JOIN table2 bb
            ON aa.tableseat = bb.tableseat AND
                aa.weddingtable = bb.weddingtable
        INNER JOIN
        (
            SELECT  a.tableSeat
            FROM    table1 a
                    INNER JOIN table2 b
                        ON a.tableseat = b.tableseat AND
                            a.weddingtable = b.weddingtable
            WHERE b.meal IN ('chicken', 'steak')
            GROUP by a.tableSeat
            HAVING COUNT(DISTINCT b.Meal) = 2
        ) c ON aa.tableseat = c.tableSeat

• SEE SQLFiddle Demo

create table a1
(weddingTable INT(3),
 tableSeat INT(3),
 tableSeatID INT(6),
 Name varchar(10));

insert into a1
 (weddingTable, tableSeat, tableSeatID, Name)
 values (001,001,001001,'Bob'),
 (001,002,001002,'Joe'),
 (001,003,001003,'Dan'),
 (002,001,002001,'Mark');

create table a2
 (weddingTable int(3),
 tableSeat int(3),
 Meal varchar(10));

insert into a2
(weddingTable, tableSeat, Meal)
values 
(001,001,'Chicken'),
(001,002,'Steak'),
(001,003,'Salmon'),
(002,001,'Steak');

select x.*, y.Meal

from a1 as x
JOIN a2 as y ON (x.weddingTable = y.weddingTable) AND (x.tableSeat = y. tableSeat);