[maven] Maven project.build.directory

In Maven, what does the project.build.directory refer to? I am a bit confused, does it reference the source code directory or the target directory in the Maven project?

This question is related to maven

The answer is


You can find those maven properties in the super pom.

You find the jar here:

${M2_HOME}/lib/maven-model-builder-3.0.3.jar

Open the jar with 7-zip or some other archiver (or use the jar tool).

Navigate to

org/apache/maven/model

There you'll find the pom-4.0.0.xml.

It contains all those "short cuts":

<project>
    ...
    <build>
        <directory>${project.basedir}/target</directory>
        <outputDirectory>${project.build.directory}/classes</outputDirectory>
        <finalName>${project.artifactId}-${project.version}</finalName>
        <testOutputDirectory>${project.build.directory}/test-classes</testOutputDirectory>
        <sourceDirectory>${project.basedir}/src/main/java</sourceDirectory>
        <scriptSourceDirectory>src/main/scripts</scriptSourceDirectory>
        <testSourceDirectory>${project.basedir}/src/test/java</testSourceDirectory>
        <resources>
            <resource>
                <directory>${project.basedir}/src/main/resources</directory>
            </resource>
        </resources>
        <testResources>
            <testResource>
                <directory>${project.basedir}/src/test/resources</directory>
            </testResource>
        </testResources>
        ...
    </build>
    ...
</project>

Update

After some lobbying I am adding a link to the pom-4.0.0.xml. This allows you to see the properties without opening up the local jar file.


You can find the most up to date answer for the value in your project just execute the

mvn3 help:effective-pom

command and find the <build> ... <directory> tag's value in the result aka in the effective-pom. It will show the value of the Super POM unless you have overwritten.


It points to your top level output directory (which by default is target):

https://web.archive.org/web/20150527103929/http://docs.codehaus.org/display/MAVENUSER/MavenPropertiesGuide

EDIT: As has been pointed out, Codehaus is now sadly defunct. You can find details about these properties from Sonatype here:

http://books.sonatype.com/mvnref-book/reference/resource-filtering-sect-properties.html#resource-filtering-sect-project-properties

If you are ever trying to reference output directories in Maven, you should never use a literal value like target/classes. Instead you should use property references to refer to these directories.

    project.build.sourceDirectory
    project.build.scriptSourceDirectory
    project.build.testSourceDirectory
    project.build.outputDirectory
    project.build.testOutputDirectory
    project.build.directory

sourceDirectory, scriptSourceDirectory, and testSourceDirectory provide access to the source directories for the project. outputDirectory and testOutputDirectory provide access to the directories where Maven is going to put bytecode or other build output. directory refers to the directory which contains all of these output directories.


Aside from @Verhás István answer (which I like), I was expecting a one-liner for the question:

${project.reporting.outputDirectory} resolves to target/site in your project.