Determine Whether Integer Is Between Two Other Integers

Question

How do I determine whether a given integer is between two other integers  e g  greater than equal to 10000 and less than equal to 30000   I m using 2 3 IDLE and what I ve attempted so far is not working  if number  gt   10000 and number  gt   30000      print   quot you have to pay 5  taxes quot

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if number  gt   10000 and number  lt   30000      print   you have to pay 5  taxes

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Your operator is incorrect   Should be if number  gt   10000 and number  lt   30000    Additionally  Python has a shorthand for this sort of thing  if 10000  lt   number  lt   30000

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You want the output to print the given statement if and only if the number falls between 10 000 and 30 000   Code should be   if number  gt   10000 and number  lt   30000      print  you have to pay 5  taxes

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gt  gt  gt  r   range 1  4   gt  gt  gt  1 in r True  gt  gt  gt  2 in r True  gt  gt  gt  3 in r True  gt  gt  gt  4 in r False  gt  gt  gt  5 in r False  gt  gt  gt  0 in r False

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Suppose there are 3 non-negative integers  a  b  and c  Mathematically speaking  if we want to determine if c is between a and b  inclusively  one can use this formula       c - a     b - c     0   or in Python    gt  print  c - a     b - c   gt   0  True

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There are two ways to compare three integers and check whether b is between a and c  if a  lt  b  lt  c      pass  and if a  lt  b and b  lt  c      pass  The first one looks like more readable  but the second one runs faster  Let s compare using dis dis   gt  gt  gt  dis dis  a  lt  b and b  lt  c     1           0 LOAD NAME                0  a                2 LOAD NAME                1  b                4 COMPARE OP               0   lt                 6 JUMP IF FALSE OR POP    14               8 LOAD NAME                1  b               10 LOAD NAME                2  c               12 COMPARE OP               0   lt            gt  gt    14 RETURN VALUE  gt  gt  gt  dis dis  a  lt  b  lt  c     1           0 LOAD NAME                0  a                2 LOAD NAME                1  b                4 DUP TOP               6 ROT THREE               8 COMPARE OP               0   lt                10 JUMP IF FALSE OR POP    18              12 LOAD NAME                2  c               14 COMPARE OP               0   lt                16 RETURN VALUE          gt  gt    18 ROT TWO              20 POP TOP              22 RETURN VALUE  gt  gt  gt   and using timeit     python3 -m timeit  quot 1  lt  2 and 2  lt  3 quot  10000000 loops  best of 3  0 0366 usec per loop     python3 -m timeit  quot 1  lt  2  lt  3 quot  10000000 loops  best of 3  0 0396 usec per loop  also  you may use range  as suggested before  however it is much more slower

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if 10000  lt   number  lt   30000      pass  For details  see the docs

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The trouble with comparisons is that they can be difficult to debug when you put a  gt   where there should be a  lt                                  v---------- should be  lt  if number  gt   10000 and number  gt   30000      print   you have to pay 5  taxes     Python lets you just write what you mean in words  if number in xrange 10000  30001     ok you have to remember 30000   1 here      In Python3  you need to use range instead of xrange   edit  People seem to be more concerned with microbench marks and how cool chaining operations  My answer is about defensive  less attack surface for bugs  programming   As a result of a claim in the comments  I ve added the micro benchmark here for Python3 5 2    python3 5 -m timeit  5 in range 10000  30000   1000000 loops  best of 3  0 266 usec per loop   python3 5 -m timeit  10000  lt   5  lt  30000  10000000 loops  best of 3  0 0327 usec per loop   If you are worried about performance  you could compute the range once    python3 5 -m timeit -s  R range 10000  30000    5 in R  10000000 loops  best of 3  0 0551 usec per loop

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Define the range between the numbers   r   range 1 10    Then use it   if num in r      print  All right

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Your code snippet   if number  gt   10000 and number  gt   30000      print   you have to pay 5  taxes     actually checks if number is larger than both 10000 and 30000   Assuming you want to check that the number is in the range 10000 - 30000  you could use the Python interval comparison   if 10000  lt   number  lt   30000      print   you have to pay 5  taxes     This Python feature is further described in the Python documentation

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The condition should be   if number    10000 and number  lt   30000       print  5  tax payable     reason for using number    10000 is that if number s value is 50000 and if we use number  gt   10000 the condition will pass  which is not what you want

[python] Determine Whether Integer Is Between Two Other Integers?

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