How do I get the month and day with leading 0 s in SQL e g 9 09

Question

DECLARE  day CHAR 2   SET  day   DATEPART DAY  GETDATE     PRINT  day   If today was the 9th of December  the above would print  9    I want to print  09   How do I go about doing this

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Try this     SELECT CONVERT varchar 2   GETDATE    101

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For SQL Server 2012 and up   with leading zeroes    SELECT FORMAT GETDATE    MM      without   SELECT    MONTH GETDATE

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SQL Server 2012   for both month and day    SELECT FORMAT GetDate    MMdd     If you decide you want the year too  use    SELECT FORMAT GetDate    yyyyMMdd

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select     right  0000    cast datepart year  GETDATE    as varchar 4    4     -           right  00    cast datepart month  GETDATE    as varchar 2    2     -           right  00    cast datepart day  getdate    as varchar 2    2  as YearMonthDay

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DECLARE  day CHAR 2   SET  day   right  0   cast day getdate   as nvarchar 2   2   print  day

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Leading 0 day  SELECT FORMAT GetDate     dd

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Use SQL Server s date styles to pre-format your date values   SELECT     CONVERT varchar 2   GETDATE    101  AS monthLeadingZero  -- Date Style 101   mm dd yyyy      CONVERT varchar 2   GETDATE    103  AS dayLeadingZero   -- Date Style 103   dd mm yyyy

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Pad it with 00 and take the right 2   DECLARE  day CHAR 2   SET  day   RIGHT  00    CONVERT NVARCHAR 2   DATEPART DAY  GETDATE      2   print  day

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Select Replicate  0  2 - DataLength Convert VarChar 2  DatePart DAY  GetDate        Convert VarChar 2  DatePart DAY  GetDate      Far neater  he says after removing tongue from cheek   Usually when you have to start doing this sort of thing in SQL  you need switch from can I  to should I

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Roll your own method  This is a generic approach for left padding anything  The concept is to use REPLICATE to create a version which is nothing but the padded value  Then concatenate it with the actual value  using a isnull coalesce call if the data is NULLable  You now have a string that is double the target size to exactly the target length or somewhere in between  Now simply sheer off the N right-most characters and you have a left padded string   SELECT RIGHT REPLICATE  0   2    CAST DATEPART DAY   2012-12-09   AS varchar 2    2  AS leftpadded day   Go native  The CONVERT function offers various methods for obtaining pre-formatted dates  Format 103 specifies dd which means leading zero preserved so all that one needs to do is slice out the first 2 characters   SELECT CONVERT char 2   CAST  2012-12-09  AS datetime   103  AS convert day

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SELECT RIGHT  0                  CONVERT VARCHAR 2   Month  column name     2   FROM   table

[sql] How do I get the month and day with leading 0's in SQL? (e.g. 9 => 09)

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