ValueError invalid literal for int with base 10

Question

I wrote a program to solve y   a x and then project it on a graph  The problem is that whenever a  lt  1 I get the error       ValueError  invalid literal for int    with base 10    Any suggestions    Here s the traceback   Traceback  most recent call last       File  C  Users kasutaja Desktop EksponentfunktsioonTEST - koopia py   line 13  in  lt module gt      if int a   lt  0   ValueError  invalid literal for int   with base 10   0 3     The problem arises every time I put a number that is smaller than one  but larger than 0  For this example it was 0 3    This is my code      y   a x  import time import math import sys import os import subprocess import matplotlib pyplot as plt print   y   a x   print      a   input   Enter  a     print      if int a   lt  0      print    a  is negative  no solution   elif int a     1      print    a  is equal with 1  no solution   else      fig   plt figure        x    -2 -1 75 -1 5 -1 25 -1 -0 75 -0 5 -0 25 0 0 25 0 5 0 75 1 1 25 1 5 1 75 2      y    int a    -2  int a    -1 75  int a    -1 5  int a    -1 25               int a    -1  int a    -0 75  int a    -0 5  int a    -0 25               int a    0  int a    0 25  int a    0 5  int a    0 75               int a   1 int a    1 25  int a    1 5  int a    1 75   int a    2         ax   fig add subplot 1 1 1      ax set title  y   a  x       ax plot x y      ax spines  left   set position  zero       ax spines  right   set color  none       ax spines  bottom   set position  zero       ax spines  top   set color  none       ax spines  left   set smart bounds True      ax spines  bottom   set smart bounds True      ax xaxis set ticks position  bottom       ax yaxis set ticks position  left         plt savefig  graph png       subprocess Popen  explorer  C   Users  kasutaja  desktop  graph png     def restart program         python   sys executable     os execl python  python    sys argv   if   name         main         answer   input  Restart program         if answer strip   in  YES yes Yes y Y  split            restart program       else          os remove  C   Users  kasutaja  desktop  graph png

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As Lattyware said  there is a difference between Python2  amp  Python3 that leads to this error   With Python2  int str 5 2   gives you 2  With Python3  the same gives you  ValueError  invalid literal for int   with base 10   2 5   If you need to convert some string that could contain float instead of int  you should always use the following ugly formula   int float myStr     As float  3 0   and float  3   give you 3 0  but int  3 0   gives you the error

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I am creating a program that reads a   file and if the first line of the file   is not blank  it reads the next four   lines  Calculations are performed on   those lines and then the next line is   read    Something like this should work   for line in infile      next lines          if line strip            for i in xrange 4               try                  next lines append infile next                except StopIteration                  break       Do your calculation with  4 lines  here

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You ve got a problem with this line   while file to read           This does not find an empty string   It finds a string consisting of one space   Presumably this is not what you are looking for   Listen to everyone else s advice   This is not very idiomatic python code  and would be much clearer if you iterate over the file directly  but I think this problem is worth noting as well

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readings    infile readline        print readings     while readings    0          global count         readings   int readings    There s a problem with that code  readings is a new line read from the file - it s a string  Therefore you should not compare it to 0  Further  you can t just convert it to an integer unless you re sure it s indeed one  For example  empty lines will produce errors here  as you ve surely found out    And why do you need the global count  That s most certainly bad design in Python

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This seems like readings is sometimes an empty string and obviously an error crops up  You can add an extra check to your while loop before the int readings  command like   while readings    0   readings            global count     readings   int readings

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Answer  Your traceback is telling you that int   takes integers  you are trying to give a decimal  so you need to use float    a   float a   This should work as expected   gt  gt  gt  int input  quot Type a number   quot    Type a number  0 3 Traceback  most recent call last     File  quot  lt stdin gt  quot   line 1  in  lt module gt  ValueError  invalid literal for int   with base 10   0 3   gt  gt  gt  float input  quot Type a number   quot    Type a number  0 3 0 3  Computers store numbers in a variety of different ways  Python has two main ones  Integers  which store whole numbers  Z   and floating point numbers  which store real numbers  R   You need to use the right one based on what you require   As a note  Python is pretty good at abstracting this away from you  most other language also have double precision floating point numbers  for instance  but you don t need to worry about that  Since 3 0  Python will also automatically convert integers to floats if you divide them  so it s actually very easy to work with   Previous guess at answer before we had the traceback  Your problem is that whatever you are typing is can t be converted into a number  This could be caused by a lot of things  for example   gt  gt  gt  int input  quot Type a number   quot    Type a number  -1 -1  gt  gt  gt  int input  quot Type a number   quot    Type a number  - 1 Traceback  most recent call last     File  quot  lt stdin gt  quot   line 1  in  lt module gt  ValueError  invalid literal for int   with base 10   - 1   Adding a space between the - and 1 will cause the string not to be parsed correctly into a number  This is  of course  just an example  and you will have to tell us what input you are giving for us to be able to say for sure what the issue is  Advice on  code style  y    int a    -2  int a    -1 75  int a    -1 5  int a    -1 25               int a    -1  int a    -0 75  int a    -0 5  int a    -0 25               int a    0  int a    0 25  int a    0 5  int a    0 75               int a   1 int a    1 25  int a    1 5  int a    1 75   int a    2    This is an example of a really bad coding habit  Where you are copying something again and again something is wrong  Firstly  you use int a  a ton of times  wherever you do this  you should instead assign the value to a variable  and use that instead  avoiding typing  and forcing the computer to calculate  the value again and again  a   int a   In this example I assign the value back to a  overwriting the old value with the new one we want to use  y    a  i for i in x   This code produces the same result as the monster above  without the masses of writing out the same thing again and again  It s a simple list comprehension  This also means that if you edit x  you don t need to do anything to y  it will naturally update to suit  Also note that PEP-8  the Python style guide  suggests strongly that you don t leave spaces between an identifier and the brackets when making a function call

User · Answer

The following are totally acceptable in python    passing a string representation of an integer into int passing a string representation of a float into float passing a string representation of an integer into float passing a float into int passing an integer into float   But you get a ValueError if you pass a string representation of a float into int  or a string representation of anything but an integer  including empty string   If you do want to pass a string representation of a float to an int  as  katyhuff points out above  you can convert to a float first  then to an integer    gt  gt  gt  int  5   5  gt  gt  gt  float  5 0   5 0  gt  gt  gt  float  5   5 0  gt  gt  gt  int 5 0  5  gt  gt  gt  float 5  5 0  gt  gt  gt  int  5 0   Traceback  most recent call last     File   lt stdin gt    line 1  in  lt module gt  ValueError  invalid literal for int   with base 10   5 0   gt  gt  gt  int float  5 0    5

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I found a work around  Python will convert the number to a float  Simply calling float first then converting that to an int will work  output   int float input

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I recently came across a case where none of these answers worked  I encountered CSV data where there were null bytes mixed in with the data  and those null bytes did not get stripped  So  my numeric string  after stripping  consisted of bytes like this    x00 x31 x00 x0d x00   To counter this  I did   countStr   fields 3  replace   x00       strip   count   int countStr       where fields is a list of csv values resulting from splitting the line

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Pythonic way of iterating over a file and converting to int   for line in open fname      if line strip                line contains eol character s         n   int line             assuming single integer on each line   What you re trying to do is slightly more complicated  but still not straight-forward   h   open fname  for line in h      if line strip             int next h  strip    for   in range 4         list of integers   This way it processes 5 lines at the time  Use h next   instead of next h  prior to Python 2 6   The reason you had ValueError is because int cannot convert an empty string to the integer  In this case you d need to either check the content of the string before conversion  or except an error   try     int     except ValueError     pass        or whatever

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I got into the same issue when trying to use readlines   inside for loop for same file object    My suspicion is firing readling   inside readline   for same file object caused this error   Best solution can be use seek 0  to reset file pointer or Handle condition with setting some flag then create new object for same file by checking set condition

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I had hard time figuring out the actual reason  it happens when we dont read properly from file  you need to open file and read with readlines   method as below   with open   content drive pre-processed-users1 1 tsv   as f      file f readlines     It corrects the formatted output

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Please test this function  split    on a simple file  I was facing the same issue and found that it was because split   was not written properly  exception handling

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your answer is throwing errors because of this line  readings   int readings     Here you are trying to convert a string into int type which is not base-10  you can convert a string into int only if it is base-10 otherwise it will throw ValueError  stating invalid literal for int   with base 10

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The reason is that you are getting an empty string or a string as an argument into int  Check if it is empty or it contains alpha characters  If it contains characters  then simply ignore that part

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So if you have   floatInString    5 0    You can convert it to int with floatInInt   int float floatInString

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This could also happen when you have to map space separated integers to a list but you enter the integers line by line using the  input    Like for example I was solving this problem on HackerRank Bon-Appetit  and the got the following error while compiling   So instead of giving input to the program line by line try to map the space separated integers into a list using the map   method

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I was getting similar errors  turns out that the dataset had blank values which python could not convert to integer

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The reason you are getting this error is that you are trying to convert a space character to an integer  which is totally impossible and restricted And that s why you are getting this error     Check your code and correct it  it will work fine

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Just for the record    gt  gt  gt  int  55063 000000   Traceback  most recent call last     File   lt stdin gt    line 1  in  lt module gt  ValueError  invalid literal for int   with base 10   55063 000000    Got me here      gt  gt  gt  int float  55063 000000    55063 0   Has to be used

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It might be better to validate a right when it is input   try    a   int input  Enter  a      except ValueError    print  PLease input a valid integer     This either casts a to an int so you can be assured that it is an integer for all later uses or it handles the exception and alerts the user

[python] ValueError: invalid literal for int () with base 10

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