Can Flask have optional URL parameters

Question

Is it possible to directly declare a flask URL optional parameter   Currently I m proceeding the following way    user route    lt userId gt     user route    lt userId gt   lt username gt    def show userId  username None       pass   How can I directly say that username is optional

User · Answer

user route    lt userId gt        NEED     AFTER LINK  user route    lt userId gt   lt username gt    def show userId  username None       pass   https   flask palletsprojects com en 1 1 x quickstart  unique-urls-redirection-behavior

User · Answer

Almost the same as Audrius cooked up some months ago  but you might find it a bit more readable with the defaults in the function head - the way you are used to with python    app route    lt user id gt     app route    lt user id gt   lt username gt    def show user id  username  Anonymous        return user id         username

User · Answer

If you are using Flask-Restful like me  it is also possible this way   api add resource UserAPI     lt userId gt       lt userId gt   lt username gt    endpoint    user     a then in your Resource class   class UserAPI Resource      def get self  userId  username None       pass

User · Answer

You can write as you show in example  but than you get build-error   For fix this    print app url map    in you root  py you see something like     lt Rule    lt userId gt   lt username gt    HEAD  POST  OPTIONS  GET  - gt  user show 0 gt   and   lt Rule    lt userId gt    HEAD  POST  OPTIONS  GET  - gt   show 1 gt    than in template you can    url for   show 0   args     and    url for   show 1   args

User · Answer

I know this post is really old but I worked on a package that does this called flask optional routes  The code is located at  https   github com sudouser2010 flask optional routes    from flask import Flask  from flask optional routes import OptionalRoutes   app   Flask   name    optional   OptionalRoutes app    optional routes    lt user id gt   lt user name gt      def foobar user id  user name None       return  it worked    if   name         main         app run host  0 0 0 0   port 5000

User · Answer

Another way is to write   user route    lt user id gt    defaults   username   None    user route    lt user id gt   lt username gt    def show user id  username       pass   But I guess that you want to write a single route and mark username as optional   If that s the case  I don t think it s possible

User · Answer

app route      defaults   path         app route    lt  path path  gt    def catch all path       return  You want path   s    path   http   flask pocoo org snippets 57

User · Answer

Since Flask 0 10 you can t add  multiple routes to one endpoint  But you can add fake endpoint   user route    lt userId gt    def show userId      return show with username userId    user route    lt userId gt   lt username gt    def show with username userId username None      pass

User · Answer

user route    lt user id gt    defaults   username   default value    user route    lt user id gt   lt username gt    def show user id  username           pass

User · Answer

I think you can use Blueprint and that s will make ur code look better and neatly   example   from flask import Blueprint  bp   Blueprint   name     example     bp route   example   methods   POST    def example self      print  example

User · Answer

Almost the same as skornos  but with variable declarations for a more explicit answer  It can work with Flask-RESTful extension   from flask import Flask from flask restful import Resource  Api  app   Flask   name    api   Api app   class UserAPI Resource       def show userId  username None       pass  api add resource UserAPI     lt userId gt       lt userId gt   lt username gt    endpoint  user    if   name         main         app run     The add resource method allows pass multiples URLs  Each one will be routed to your Resource

[python] Can Flask have optional URL parameters?

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