Remove char at specific index - python

Question

I have a string that has two  0   str  in it and I want to remove only the  0   str  at index 4  I have tried calling  replace but obviously that removes all  0   and I cannot find a function that will remove the char at position 4 for me   Anyone have a hint for me

User · Answer

Try this code   s   input    a   int input     b   s replace s a      print b

User · Answer

This is my generic solution for any string  s and any index i   def remove at i  s       return s  i    s i 1

User · Answer

rem   lambda x  unwanted      join   c for i  c in enumerate x  if i    unwanted   rem  1230004   4   123004

User · Answer

Slicing works  and is the preferred approach   but just an alternative if more operations are needed  but then converting to a list wouldn t hurt anyway     gt  gt  gt  a    123456789   gt  gt  gt  b   bytearray a   gt  gt  gt  del b 3   gt  gt  gt  b bytearray b 12356789    gt  gt  gt  str b   12356789

User · Answer

Use slicing  rebuilding the string minus the index you want to remove   newstr   oldstr  4    oldstr 5

User · Answer

def remove char input string  index       first part   input string  index      second part - input string index 1       return first part   second part  s    aababc  index   1 remove char s index  ababc   zero-based indexing

User · Answer

as a sidenote  replace doesn t have to move all zeros  If you just want to remove the first specify count to 1    asd0asd0  replace  0     1    Out    asdasd0

User · Answer

Another option  using list comprehension and join      join   str i  for i in xrange len  str   if i     4

[python] Remove char at specific index - python

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