I know this question is asked by many people already
for my research, here's some questions asked before
But after all, still can't solve our problems,
we just want to delete "ALL" nodes and "ALL" relationships
suppose delete "ALL" can see there are left 0 nodes 0 properties and 0 relationships
This is the screenshot i took after executing the delete "ALL" suggested by forum
My question still the same, how do delete all nodes and all relationships in neo4j
This question is related to
neo4j
nosql
relationship
Probably you will want to delete Constraints and Indexes
It will do the trick..
Match (n)-[r]-()
Delete n,r;
you are probably doing it correct, only the dashboard shows just the higher ID taken, and thus the number of "active" nodes, relationships, although there are none. it is just informative.
to be sure you have an empty graph, run this command:
START n=node(*) return count(n);
START r=rel(*) return count(r);
if both give you 0, your deletion was succesfull.
for a big database you should either remove the database from the disk (after you stop the engine first I guess) or use in Cypher something like:
MATCH (n)
OPTIONAL MATCH (n)-[r]-()
WITH n,r LIMIT 50000
DELETE n,r
RETURN count(n) as deletedNodesCount
see https://zoomicon.wordpress.com/2015/04/18/howto-delete-all-nodes-and-relationships-from-neo4j-graph-database/ for some more info I've gathered on this from various answers
if the name of node is for example : abcd then below query will work :
MATCH (n:abcd)
DETACH DELETE n
This will only delete the node with label "abcd" and all its relation-ships.
Neo4j cannot delete nodes that have a relation. You have to delete the relations before you can delete the nodes.
But, it is simple way to delete "ALL" nodes and "ALL" relationships with a simple chyper. This is the code:
MATCH (n) DETACH DELETE n
--> DETACH DELETE will remove all of the nodes and relations by Match
Source: Stackoverflow.com