How to convert an integer to a character array using C

Question

I want to convert an integer number to a character array in C  Input  int num   221234   The result is equivalent to  char arr 6   arr 0     2   arr 1     2   arr 2     1   arr 3     2   arr 4     3   arr 5     4    How can I do this

User · Answer

You may give a shot at using itoa  Another alternative is to use sprintf

User · Answer

Make use of the log10 function to determine the number of digits and do like below  char   toArray int number        int n   log10 number    1      int i      char  numberArray   calloc n  sizeof char        for  i   n-1  i  gt   0  --i  number    10                numberArray i     number   10     0             return numberArray     Or the other option is sprintf yourCharArray  quot  ld quot   intNumber

User · Answer

Use itoa  as is shown here  char buf 5      Convert 123 to string  buf  itoa 123  buf  10    buf will be a string array as you documented  You might need to increase the size of the buffer

User · Answer

sprintf  will work fine  if your first argument is a pointer to a character  a pointer to a character is an array in  c    you ll have to make sure you have enough space for all the digits and a terminating   0   For example  If an integer uses 32 bits  it has up to 10 decimal digits  So your code should look like   int i  char s 11        sprintf s   ld   i

User · Answer

The easy way is by using sprintf   I know others have suggested itoa  but a  it isn t part of the standard library  and b  sprintf gives you formatting options that itoa doesn t

[c] How to convert an integer to a character array using C

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