How to remove a character at the end of each line in unix

Question

I would like to remove comma   at the end of each line in my file  How can I do it other than using substring function in awk  please suggest me Thanks  Sample Input          SUPPLIER PROC ID BIGINT NOT NULL          BTCH NBR INTEGER NOT NULL          RX BTCH SUPPLIER SEQ NBR INTEGER NOT NULL          CORRN ID INTEGER NOT NULL          RX CNT BYTEINT NOT NULL          DATA TYP CD BYTEINT NOT NULL          DATA PD CD BYTEINT NOT NULL          CYC DT DATE NOT NULL          BASE DT DATE NOT NULL          DATA LOAD DT DATE NOT NULL          DATA DT DATE NOT NULL          SUPPLIER DATA SRC CD BYTEINT NOT NULL          RX CHNL CD BYTEINT NOT NULL          MP IMS ID INTEGER NOT NULL          MP LOC ID NUMERIC 3 0           MP IMS ID ACTN CD BYTEINT NOT NULL          NPI ID BIGINT

User · Answer

Try doing this    awk   print substr  0  1  length  0 -1    file txt   This is more generic than just removing the final comma but any last character  If you d want to only remove the last comma with awk    awk   gsub           print   file txt

User · Answer

You can use sed   sed  s       file  gt  file nocomma   and to remove whatever last character   sed  s       file  gt  file nolast

User · Answer

alternative commands that does same job   tr -d       lt  infile awk  gsub           infile

User · Answer

This Perl code removes commas at the end of the line   perl -pe  s       file  gt  file nocomma   This variation still works if there is whitespace after the comma   perl -lpe  s   s      file  gt  file nocomma   This variation edits the file in-place   perl -i -lpe  s   s      file   This variation edits the file in-place  and makes a backup file bak   perl -i bak -lpe  s   s      file

User · Answer

An awk code based on RS   awk  1  RS    n  file   or   awk  BEGIN RS    n  1  file   This last example will be valid for any char before newline   awk  1  RS    n  file   Note  dot   matches any character except line breaks   Explanation  awk allows us to use different record  line  regex separators  we just need to include the comma before the line break  or dot for any char  in the one used for the input  the RS   Note   what that 1 means   Short answer  It s just a shortcut to avoid using the print statement  In awk when a condition gets matched the default action is to print the input line  example     echo  test   awk  1  test   That s because 1 will be always true  so this expression is equivalent to     echo  test  awk  1  1  test   echo  test  awk   if  1  1  print    test   Documentation    Check Record Splitting with Standard awk and Output Separators

[unix] How to remove a character at the end of each line in unix

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