Why dividing two integers doesn t get a float

Question

Can anyone explain why b gets rounded off here when I divide it by an integer although it s a float    include  lt stdio h gt   void main         int a      float b  c  d      a   750      b   a   350      c   750      d   c   350      printf    2f   2f   b  d          output  2 00 2 14     http   codepad org j1pckw0y

User · Answer

Probably the best reason is because 0xfffffffffffffff 15 would give you a horribly wrong answer

User · Answer

Use casting of types   int main         int a      float b  c  d      a   750      b   a    float 350      c   750      d   c    float 350      printf    2f   2f   b  d          output  2 14 2 14     This is another way to solve that    int main             int a          float b  c  d          a   750          b   a   350 0    if you use  a   350  here                            then it is a division of integers                            so the result will be an integer         c   750          d   c   350          printf    2f   2f   b  d              output  2 14 2 14         However  in both cases you are telling the compiler that 350 is a float  and not an integer  Consequently  the result of the division will be a float  and not an integer

User · Answer

Specifically  this is not rounding your result  it s truncating toward zero   So if you divide -3 2  you ll get -1 and not -2   Welcome to integral math   Back before CPUs could do floating point operations or the advent of math co-processors  we did everything with integral math   Even though there were libraries for floating point math  they were too expensive  in CPU instructions  for general purpose  so we used a 16 bit value for the whole portion of a number and another 16 value for the fraction   EDIT  my answer makes me think of the classic old man saying  when I was your age

User · Answer

Dividing two integers will result in an integer  whole number  result    You need to cast one number as a float  or add a decimal to one of the numbers  like a 350 0

User · Answer

a  is an integer  when divided with integer it gives you an integer  Then it is assigned to  b  as an integer and becomes a float   You should do it like this  b   a   350 0

User · Answer

Chapter and verse   6 5 5 Multiplicative operators     6 When integers are divided  the result of the   operator is the algebraic quotient with any fractional part discarded 105  If the quotient a b is representable  the expression  a b  b   a b shall equal a  otherwise  the behavior of both a b and a b is unde ned   105  This is often called       truncation toward zero          Dividing an integer by an integer gives an integer result   1 2 yields 0  assigning this result to a floating-point variable gives 0 0   To get a floating-point result  at least one of the operands must be a floating-point type   b   a   350 0f  should give you the result you want

User · Answer

This is because of implicit conversion  The variables b  c  d are of float type  But the   operator sees two integers it has to divide and hence returns an integer in the result which gets implicitly converted to a float by the addition of a decimal point  If you want float divisions  try making the two operands to the   floats  Like follows    include  lt stdio h gt   int main         int a      float b  c  d      a   750      b   a   350 0f      c   750      d   c   350      printf    2f   2f   b  d          output  2 14 2 14     return 0

[c] Why dividing two integers doesn't get a float?

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