C scanf to array

Question

I m absolutely new to C  and right now I am trying master the basics and have a problem reading data from scanf straight into an array   Right now the code looks like this   int main         int array 11       printf  Write down your ID number  n        scanf   d   array       if  array 0  1                printf   nThis person is a male               else if  array 0  2                printf   nThis person is a female               return 0      As you can see  the program s aim is to ask for an ID  and determine from the first number whether the given the person is male 1  or female 2   However it seems I can t get it to work  because the array is not filled properly  this is checked via a printf array  right after scanf  that results in random numbers   Running the program like this will give the result that the person is a male  no matter what number you read in   So trivial it may seem  I couldn t figure out the problem

User · Answer

Use   scanf   d    amp array 0      and use    for comparision instead of

User · Answer

The  d conversion specifier will only convert one decimal integer  It doesn t know that you re passing an array  it can t modify its behavior based on that  The conversion specifier specifies the conversion   There is no specifier for arrays  you have to do it explicitly  Here s an example with four conversions   if scanf   d  d  d  d    amp array 0    amp array 1    amp array 2    amp array 3      4    printf  got four numbers n      Note that this requires whitespace between the input numbers   If the id is a single 11-digit number  it s best to treat as a string   char id 12    if scanf   11s   id     1         inspect the  character  in id 0   compare with  1  or  2  for instance

User · Answer

int main       int array 11     printf  Write down your ID number  n      for int i 0 i lt id length i      scanf   d    amp array i      if  array 0   1          printf   nThis person is a male           else if  array 0   2          printf   nThis person is a female           return 0

User · Answer

if  array 0  1  should be if  array 0   1    The same with else if  array 0  2    Note that the expression of the assignment returns the assigned value  in this case if  array 0  1  will be always true  that s why the code below the if-statement will be always executed if you don t change the   to        is the assignment operator  you want to compare  not to assign  So you need      Another thing  if you want only one integer  why are you using array  You might want also to scanf   d    amp array 0

[c] C: scanf to array

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