Replace multiple characters in one replace call

Question

Very simple little question  but I don t quite understand how to do it    I need to replace every instance of     with a space  and every instance of     with nothing empty    var string     Please send an information pack to the following address     I ve tried this   string replace         replace             I don t really like chaining commands like this  Is there another way to do it in one

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x000D   x000D  String prototype replaceAll function obj keydata  key     const keys keydata split  key    return Object entries obj  reduce  a  key val    gt  a replace new RegExp    keys 0    key   keys 1     g   val  this     const data  hids dv sdc sd  yathin   ok   console log data replaceAll  yathin 12 ok  hi     key     x000D   x000D   x000D   String prototype replaceAll function keydata obj   const keys keydata split  key    return Object entries obj  reduce  a  key val    gt  a replace   keys 0    key   keys 1   val  this    const data  hids dv sdc sd   yathin    ok   console log data replaceAll    key    yathin 12 ok  hi

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Please try    replace multi string  var str    http   www abc xyz com   str   str replace  http  www  com g         str is     abc xyz  replace multi chars  var str    a b c d e f g h   str   str replace       g          str is  abcdefgh     Good luck

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Here is a  safe HTML  function using a  reduce  multiple replacement function  this function applies each replacement to the entire string  so dependencies among replacements are significant       Test  document write SafeHTML   lt div gt  n      x lt  div gt       function SafeHTML str            const replacements                amp     amp amp                lt     amp lt                gt     amp gt                    amp quot                    amp apos                    amp grave                n    lt br gt                    amp nbsp                   return replaceManyStr replacements str            HTMLToSafeHTML  function replaceManyStr replacements str            return replacements reduce  accum t    gt  accum replace new RegExp Object keys t  0   g   t Object keys t  0    str

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You can also pass a RegExp object to the replace method like  var regexUnderscore   new RegExp       g      indicates global match var regexHash   new RegExp       g     string replace regexHash      replace regexUnderscore          Javascript RegExp

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I don t know if how much this will help but I wanted to remove  lt b gt  and  lt  b gt  from my string   so I used   mystring replace   lt b gt        replace   lt  b gt          so basically if you want a limited number of character to be reduced and don t waste time this will be useful

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yourstring     Please send an information pack to the following address     replace     with    and replace     with a space  var newstring1   yourstring split      join      var newstring2   newstring1 split      join         newstring2 is your result

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You can just try this    str replace       g   replacechar      this will replace   - and   with your replacechar

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Chaining is cool  why dismiss it   Anyway  here is another option in one replace   string replace      g function match   return  match                   The replace will choose    if match           if not    Update  For a more generic solution  you could store your replacement strings in an object   var replaceChars                       string replace      g function match   return replaceChars match

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Use the OR operator       var str     this  is      a test        str replace      g         result   this is a test    You could also use a character class   str replace       g        Fiddle  If you want to replace the hash with one thing and the underscore with another  then you will just have to chain  However  you could add a prototype   String prototype allReplace   function obj        var retStr   this      for  var x in obj            retStr   retStr replace new RegExp x   g    obj x              return retStr      console log  aabbaabbcc  allReplace   a    h    b    o         console log  hhoohhoocc     Why not chain  though  I see nothing wrong with that

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Here s a simple way to do it without RegEx You can prototype and or cache things as desired      Example  translate   faded    abcdef    123456    returns  61454  function translate  s  sFrom  sTo        for   var out       i   0  i  lt  s length  i              out    sTo charAt  sFrom indexOf  s charAt i                return out

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If you want to replace multiple characters you can call the String prototype replace   with the replacement argument being a function that gets called for each match  All you need is an object representing the character mapping which you will use in that function   For example  if you want a replaced with x  b with y and c with z  you can do something like this   var chars     a   x   b   y   c   z    var s    234abc567bbbbac   s   s replace   abc  g  m   gt  chars m    console log s     Output  234xyz567yyyyxz

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You could also try this    function replaceStr str  find  replace        for  var i   0  i  lt  find length  i              str   str replace new RegExp find i    gi    replace i              return str     var text     here is the one    var find              var replace             text   replaceStr text  find  replace   console log text     find refers to the text to be found and replace to the text to be replaced with  This will be replacing case insensitive characters  To do otherway just change the Regex flags as required  Eg  for case sensitive replace     new RegExp find i    g

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Here is another version using String Prototype  Enjoy   String prototype replaceAll   function obj        let finalString           let word   this      for  let each of word           for  const o in obj               const value   obj o               if  each    o                   each   value                                  finalString    each             return finalString       abc  replaceAll   a   x    b   y        xyc

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For replacing with nothing  tckmn s answer is the best  If you need to replace with specific strings corresponding to the matches  here s a variation on Voicu s and Christophe s answers that avoids duplicating what s being matched  so that you don t have to remember to add new matches in two places  const replacements               quot   quot              quot               quot              ---             --      const replacement regex   new RegExp Object    keys replacements       escape any regex literals found in the replacement keys     map e   gt  e replace                     g       amp        join         g    return text replace replacement regex  e   gt  replacements e

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Specify the  g  global  flag on the regular expression to replace all matches instead of just the first   string replace    g       replace    g        To replace one character with one thing and a different character with something else  you can t really get around needing two separate calls to replace   You can abstract it into a function as Doorknob did  though I would probably have it take an object with old new as key value pairs instead of a flat array

[javascript] Replace multiple characters in one replace call

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