Bash If Else statement in one line

Question

I am trying to check if a process  assume it is called some process  is running on a server  If it is  then echo 1  otherwise echo 0   This is the command that I am using but it only works partially  more info below   Note that I need to write the script in one line   ps aux   grep some proces s   gt   tmp test txt  amp  amp  if      -eq 0    then echo 1  else echo 0  fi   Note  The  s  in some proces s  is to prevent grep from returning itself   If some process is running  then  1  gets echoed  which is fine  However  if some process is not running  nothing gets echoed

User · Answer

amp  amp  means  and if successful   by placing your if statement on the right-hand side of it  you ensure that it will only run if grep returns 0  To fix it  use   instead      ps aux   grep some proces s   gt   tmp test txt   if      -eq 0    then echo 1  else echo 0  fi    or just use a line-break

User · Answer

You can make full use of the  amp  amp  and    operators like this   ps aux   grep some proces s   gt   tmp test txt  amp  amp  echo 1    echo 0   For excluding grep itself  you could also do something like   ps aux   grep some proces   grep -vw grep  gt   tmp test txt  amp  amp  echo 1    echo 0

User · Answer

There is no need to explicitly check      Just do   ps aux   grep some proces s   gt   tmp test txt  amp  amp  echo 1    echo 0    Note that this relies on echo not failing  which is certainly not guaranteed   A more reliable way to write this is   if ps aux   grep some proces s   gt   tmp test txt  then echo 1  else echo 0  fi

User · Answer

Use grep -vc to ignore grep in the ps output and count the lines simultaneously   if      ps aux   grep process   grep -vc grep    gt  0      then echo 1  else echo 0   fi

User · Answer

pgrep -q some process  amp  amp  echo 1    echo 0   more oneliners here

[bash] Bash: If/Else statement in one line

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