Convert int to char in java

Question

Below is a code snippet   int a   1  char b    char  a  System out println b     But what I get is empty output   int a    1   char b    char  a  System out println b     I will get 1 as my output    Can somebody explain this  And if I want to convert an int to a char as in the first snippet  what should I do

User · Answer

look at the following program for complete conversion concept

class typetest{
    public static void main(String args[]){
        byte a=1,b=2;
        char c=1,d='b';
        short e=3,f=4;
        int g=5,h=6;
        float i;
        double k=10.34,l=12.45;
        System.out.println("value of char variable c="+c);
        // if we assign an integer value in char cariable it's possible as above
        // but it's not possible to assign int value from an int variable in char variable 
        // (d=g assignment gives error as incompatible type conversion)
        g=b;
        System.out.println("char to int conversion is possible");
        k=g;
        System.out.println("int to double conversion is possible");
        i=h;
        System.out.println("int to float is possible and value of i = "+i);
        l=i;
        System.out.println("float to double is possible");
    }
}

hope ,it will help at least something

User · Answer

int a   1  char b    char  a  System out println b     hola  well i went through the same problem but what i did was the following code   int a   1 char b   Integer toString a  charAt 0   System out println b     With this you get the decimal value as a char type  I used charAt   with index 0 because the only value into that String is  a  and as you know  the position of  a  into that String start at 0   Sorry if my english isn t well explained  hope it helps you

User · Answer

int a   1  char b    char   a   48     In ASCII  every char have their own number  And char  0  is 48 for decimal   1  is 49  and so on  So if  char b    2   int a   b   50

User · Answer

First  convert the int  or another type  to String  int a   1  String value   String valueOf a    Then  convert that String to char  char newValue   value charAt 0    You can avoid empty output in this way    System out println newValue

User · Answer

If you want to convert a character to its corresponding integer  you can do something like this   int a    int   a   char b    char  a  System out println b     This happens because in ASCII there are some items that can not be printed normally   For example  numbers 97 to 122 are integers corresponding to the lowercase letters a to z

User · Answer

My answer is similar to jh314 s answer but I ll explain a little deeper   What you should do in this case is   int a   1  char b    char  a    0    System out println b     Here  we used  0  because chars are actually represented by ASCII values   0  is a char and represented by the value of 48    We typed  a    0   and in order to add these up  Java converted  0  to its ASCII value which is 48 and a is 1 so the sum is 49  Then what we did is    char  49    We casted int to char  ASCII equivalent of 49 is  1   You can convert any digit to char this way and is smarter and better way than using  toString   method and then subtracting the digit by  charAt   method

User · Answer

if you want to print ascii characters based on their ascii code and do not want to go beyond that  like unicode characters   you can define your variable as a byte  and then use the  char  convert  i e    public static void main String   args        byte b   65      for  byte i b  i lt  b 25  i              System out print  char i                  BTW  the ascii code for the letter  A  is 65

User · Answer

There is one method by which int can be converted to char and even without using ASCII values  Example  int i   2  char ch   Integer toString i  charAt 0   System out println ch    Explanation   First the integer is converted to string and then by using String function charAt    character is extracted from the string  As the integer only has one single digit  the index 0 is given to charAt   function

User · Answer

Make sure the integer value is ASCII value of an alphabet character   If not then make it   for e g  if int i 1   then add 64 to it so that it becomes 65   ASCII value of  A  Then use  char x    char i   print x      A  will be printed

User · Answer

you may want it to be printed as  1  or as  a   In case you want  1  as input then   int a   1  char b    char  a    0    System out println b    In case you want  a  as input then   int a   1  char b    char  a-1    a    System out println b    java turns the ascii value to char

User · Answer

int a   1  char b    char  a  System out println b    will print out the char with Unicode code point 1  start-of-heading char  which isn t printable  see this table  C0 Controls and Basic Latin  same as ASCII  int a    1   char b    char  a  System out println b    will print out the char with Unicode code point 49  one corresponding to  1   If you want to convert a digit  0-9   you can add 48 to it and cast  or something like Character forDigit a  10    If you want to convert an int seen as a Unicode code point  you can use Character toChars 48  for example

User · Answer

If we are talking about class types - not primitives  the following trick has to be done   Integer someInt  Character someChar   someChar    char Integer parseInt String valueOf someInt

User · Answer

Whenever you type cast integer to char it will return the ascii value of that int  once go through the ascii table for better understanding        int a 68      char b  char a       System out println b    it will return ascii value of 68        output- D

User · Answer

In java a char is an int   Your first snippet prints out the character corresponding to the value of 1 in the default character encoding scheme  which is probably Unicode    The Unicode character U 0001 is a non-printing character  which is why you don t see any output   If you want to print out the character  1   you can look up the value of  1  in the encoding scheme you are using   In Unicode this is 49  the same as ASCII    But this will only work for digits 0-9   You might be better off using a String rather than a char  and using Java s built-in toString   method   int a   1  String b   toString a   System out println b     This will work whatever your system encoding is  and will work for multi-digit numbers

User · Answer

Nobody has answered the real  question  here  you ARE converting int to char correctly  in the ASCII table a decimal value of 01 is  start of heading   a non-printing character  Try looking up an ASCII table and converting an int value between 33 and 7E  that will give you characters to look at

User · Answer

It seems like you are looking for the Character forDigit method   final int RADIX   10  int i   4  char ch   Character forDigit i  RADIX   System out println ch      Prints  4    There is also a method that can convert from a char back to an int   int i2   Character digit ch  RADIX   System out println i2      Prints  4    Note that by changing the RADIX you can also support hexadecimal  radix 16  and any radix up to 36  or Character MAX RADIX as it is also known as

User · Answer

public class String Store In Array        public static void main String   args                 System out println   Q 37 Can you store string in array of integers  Try it              String str  I am Akash           int arr   new int str length             char chArr   str toCharArray              char  ch          for int i 0 i lt str length   i                           arr i  chArr i                     System out println   nI have stored it in array by using ASCII value            for int i 0 i lt arr length i                           System out print     arr i                      System out println   nI have stored it in array by using ASCII value to original content            for int i 0 i lt arr length i                           ch  char arr i                System out print     ch

[java] Convert int to char in java

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