I would like to access the result of the following shell command,
youtube-dl -g "www.youtube.com/..."
to print its output direct url to a file, from within a python program. This is what I have tried:
import youtube-dl
fromurl="www.youtube.com/..."
geturl=youtube-dl.magiclyextracturlfromurl(fromurl)
Is that possible?
I tried to understand the mechanism in the source but got lost: youtube_dl/__init__.py, youtube_dl/youtube_DL.py, info_extractors ...
This question is related to
python
youtube-dl
For simple code, may be i think
import os
os.system('youtube-dl [OPTIONS] URL [URL...]')
Above is just running command line inside python.
Other is mentioned in the documentation Using youtube-dl on python Here is the way
from __future__ import unicode_literals
import youtube_dl
ydl_opts = {}
with youtube_dl.YoutubeDL(ydl_opts) as ydl:
ydl.download(['https://www.youtube.com/watch?v=BaW_jenozKc'])
If youtube-dl is a terminal program, you can use the subprocess module to access the data you want.
Check out this link for more details: Calling an external command in Python
I would like this
from subprocess import call
command = "youtube-dl https://www.youtube.com/watch?v=NG3WygJmiVs -c"
call(command.split(), shell=False)
Here is a way.
We set-up options' string, in a list, just as we set-up command line arguments. In this case opts=['-g', 'videoID']. Then, invoke youtube_dl.main(opts). In this way, we write our custom .py module, import youtube_dl and then invoke the main() function.
Source: Stackoverflow.com