I want to check if a variable has one of multiple values. I'm confused about why or
doesn't work in this situation. I was following a tutorial that gave the example if (a or b):
, but when I try to do this it only checks the variable against the first value. What is wrong with my check?
name = raw_input('Please type in your name:')
if len(name) < 5:
print "Your name has fewer than 5 characters"
elif len(name) == 5:
print "Your name has exactly 5 characters"
if name == ("Jesse" or "jesse"):
print "Hey Jesse!"
else:
print "Your name has greater than 5 characters"
This question is related to
python
If you want case-insensitive comparison, use lower
or upper
:
if name.lower() == "jesse":
The or
operator returns the first operand if it is true, otherwise the second operand. So in your case your test is equivalent to if name == "Jesse"
.
The correct application of or
would be:
if (name == "Jesse") or (name == "jesse"):
if name in ("Jesse", "jesse"):
would be the correct way to do it.
Although, if you want to use or
, the statement would be
if name == 'Jesse' or name == 'jesse':
>>> ("Jesse" or "jesse")
'Jesse'
evaluates to 'Jesse'
, so you're essentially not testing for 'jesse'
when you do if name == ("Jesse" or "jesse")
, since it only tests for equality to 'Jesse'
and does not test for 'jesse'
, as you observed.
Source: Stackoverflow.com