How to count the number of letters in a string without the spaces

Question

This is my solution resulting in an error  Returns 0  PS  I d still love a fix to my code     from collections import Counter import string   def count letters word       global count     wordsList   string split word      count   Counter       for words in wordsList          for letters in set words               return count letters   word    The grey old fox is an idiot  print count letters word

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For another one-liner solution   def count letters word    return len filter lambda x  x not in      word     This works by using the filter function  which lets you pick the elements of a list  that return true when passed to a boolean-valued function that you pass as the first argument   I m using a lambda function to make a quick  throwaway function for that purpose    gt  gt  gt  count letters  This is a test   11   You could easily extend this to exclude any selection of characters you like   def count letters word  exclude    return len filter lambda x  x not in exclude  word     gt  gt  gt  count letters   This is a test    aeiou    7   Edit   However  you wanted to get your own code to work  so here are some thoughts   The first problem is that you weren t setting a list for the Counter object to count   However  since you re looking for the total number of letters  you need to join the words back together again rather than counting each word individually   Looping to add up the number of each letter isn t really necessary because you can pull out the list of values and use  sum  to add them   Here s a version that s as close to your code as I could make it  without the loop   from collections import Counter import string  def count letters word      wordsList   string split word     count   Counter    join wordsList      return sum dict count  values     word    The grey old fox is an idiot  print count letters word    Edit   In response to a comment asking why not to use a for loop  it s because it s not necessary  and in many cases using the many implicit ways to perform repetitive tasks in Python can be faster  simpler to read  and more memory-efficient   For example  I could have written  joined words      for curr word in wordsList      joined words extend curr word  count   Counter joined words    but in doing this I wind up allocating an extra array and executing a loop through the Python interpreter that my solution   count   Counter    join wordsList     would execute in a chunk of optimized  compiled C code   My solution isn t the only way to simplify that loop  but it s one way

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I found this is working perfectly   str    count a character occurance  str   str replace          print  str  print  len str

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OK  if that s what you want  here s what I would do to fix your existing code   from collections import Counter  def count letters words       counter   Counter       for word in words split            counter update word      return sum counter itervalues     words    The grey old fox is an idiot  print count letters words     22   If you don t want to count certain non-whitespace characters  then you ll need to remove them -- inside the for loop if not sooner

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string str input  Enter any sentence      s string split   a 0 b 0  for i in s      a len i      b a b  print b    It works perfectly without counting spaces of a string

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Try using     resp   input  Hello  I am stuck in doors  What is the weather outside    print  You answered in   resp ascii letters   letters      Didn t work for me but should work for some random guys

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Simply solution using the sum function       sum c        for c in word    It s a memory efficient solution because it uses a generator rather than creating a temporary list and then calculating the sum of it   It s worth to mention that c        returns True or False  which is a value of type bool  but bool is a subtype of int  so you can sum up bool values  True corresponds to 1 and False corresponds to 0   You can check for an inheretance using the mro method    gt  gt  gt  bool mro     Method Resolution Order   lt type  bool  gt    lt type  int  gt    lt type  object  gt     Here you see that bool is a subtype of int which is a subtype of object

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def count letters word       return len word  - word count        Alternatively  if you have multiple letters to ignore  you could filter the string   def count letters word       BAD LETTERS           return len  letter for letter in word if letter not in BAD LETTERS

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def count letter string       count   0     for i in range len string            if string i  isalpha                count    1     return count   print count letter  The grey old fox is an idiot

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Counting number of letters in a string using regex   import re s    The grey old fox is an idiot  count   len re findall   a-zA-Z   s

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I managed to condense it into two lines of code   string   input  Enter your string n   print len string  - string count

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MattBryant s answer is a good one  but if you want to exclude more types of letters than just spaces  it will get clunky  Here s a variation on your current code using Counter that will work   from collections import Counter import string  def count letters word  valid letters string ascii letters       count   Counter word    this counts all the letters  including invalid ones     return sum count letter  for letter in valid letters    add up valid letters   Example output    gt  gt  gt  count letters  The grey old fox is an idiot      the period will be ignored 22

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n str input  Enter word     replace           ans 0 for i in n      ans ans 1 print ans

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word display      for letter in word      if letter in known          word display     s s      word display  letter      else          word display     s      word display return word display

[python] How to count the number of letters in a string without the spaces?

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