How to call a function after delay in Kotlin

Question

As the title  is there any way to call a function after delay  1 second for example  in Kotlin

User · Answer

val timer   Timer   timer schedule timerTask   nextScreen      3000

User · Answer

Many Ways 1  Using Handler class Handler   postDelayed       TODO  quot Do something quot          2000   2  Using Timer class Timer   schedule object   TimerTask         override fun run             TODO  quot Do something quot            2000      Shorter  Timer   schedule timerTask       TODO  quot Do something quot      2000       Shortest  Timer   schedule 2000        TODO  quot Do something quot      3  Using Executors class Executors newSingleThreadScheduledExecutor   schedule       TODO  quot Do something quot      2  TimeUnit SECONDS

User · Answer

You can use Schedule  inline fun Timer schedule      delay  Long       crossinline action  TimerTask    - gt  Unit    TimerTask  source    example  thanks  Nguyen Minh Binh - found it here  http   jamie mccrindle org 2013 02 exploring-kotlin-standard-library-part-3 html   import java util Timer import kotlin concurrent schedule  Timer  SettingUp   false  schedule 500        doSomething

User · Answer

If you are in a fragment with viewModel scope you can use Kotlin coroutines      myViewModel viewModelScope launch           delay 2000             DoSomething

User · Answer

If you are looking for generic usage  here is my suggestion   Create a class named as Run   class Run       companion object           fun after delay  Long  process     - gt  Unit                Handler   postDelayed                   process                  delay                      And use like this   Run after 1000           print something useful etc

User · Answer

If you re using more recent Android APIs the Handler empty constructor has been deprecated and you should include a Looper  You can easily get one through Looper getMainLooper        Handler Looper getMainLooper    postDelayed             Your code        2000    millis

User · Answer

A simple example to show a toast after 3 seconds    fun onBtnClick         val handler   Handler       handler postDelayed   showToast      3000     fun showToast        Toast makeText context   Its toast    Toast LENGTH SHORT  show

User · Answer

There is also an option to use Handler - gt  postDelayed   Handler   postDelayed                         doSomethingHere                      1000

User · Answer

I recommended using SingleThread because you do not have to kill it after using  Also   stop    method is deprecated in Kotlin language    private fun mDoThisJob         Executors newSingleThreadScheduledExecutor   scheduleAtFixedRate             TODO  You can write your periodical job here            1  1  TimeUnit SECONDS      Moreover  you can use it for periodical job  It is very useful  If you would like to do job for each second  you can set because parameters of it      Executors newSingleThreadScheduledExecutor   scheduleAtFixedRate Runnable command  long initialDelay  long period  TimeUnit unit     TimeUnit values are  NANOSECONDS  MICROSECONDS  MILLISECONDS  SECONDS  MINUTES  HOURS  DAYS    canerkaseler

User · Answer

You have to import the following two libraries   import java util   import kotlin concurrent schedule   and after that use it in this way   Timer   schedule 10000         do something

User · Answer

You could launch a coroutine  delay it and then call the function      GlobalScope   launch      delay 1000     yourFn        If you are outside of a class or object prepend GlobalScope to let the coroutine run there  otherwise it is recommended to implement the CoroutineScope in the surrounding class  which allows to cancel all coroutines associated to that scope if necessary

[android] How to call a function after delay in Kotlin?

Examples related to android

Examples related to kotlin