[angular] Angular: How to update queryParams without changing route

I am trying to update (add, remove) queryParams from a component. In angularJS, it used to be possible thanks to :

$location.search('f', 'filters[]'); // setter
$location.search()['filters[]'];    // getter

I have an app with a list that the user can filter, order, etc and I would like to set in the queryParams of the url all the filters activated so he can copy/paste the url or share it with someone else.

However, I don't want my page to be reloaded each time a filter is selected.

Is this doable with the new router?

I ended up combining urlTree with location.go

const urlTree = this.router.createUrlTree([], {
       relativeTo: this.route,
       queryParams: {
           newParam: myNewParam,
       },
       queryParamsHandling: 'merge',
    });

    this.location.go(urlTree.toString());

Not sure if toString can cause problems, but unfortunately location.go, seems to be string based.

First, we need to import the router module from angular router and declare its alias name

import { Router } from '@angular/router'; ---> import
class AbcComponent implements OnInit(){
constructor(
    private router: Router ---> decalre alias name
  ) { }
}

1. You can change query params by using "router.navigate" function and pass the query parameters

this.router.navigate([], { queryParams: {_id: "abc", day: "1", name: "dfd"} 
});

It will update query params in the current i.e activated route

2. The below will redirect to abc page with _id, day and name as query params

   this.router.navigate(['/abc'], { queryParams: {_id: "abc", day: "1", name: "dfd"} });

   It will update query params in the "abc" route along with three query paramters

For fetching query params:-

    import { ActivatedRoute } from '@angular/router'; //import activated routed

    export class ABC implements OnInit {

    constructor(
        private route: ActivatedRoute //declare its alias name
      ) {}

    ngOnInit(){
       console.log(this.route.snapshot.queryParamMap.get('_id')); //this will fetch the query params
    }

If you want to change query params without change the route. see below example might help you: current route is : /search & Target route is(without reload page) : /search?query=love

    submit(value: string) {
      this.router.navigate( ['.'],  { queryParams: { query: value } })
        .then(_ => this.search(q));
    }
    search(keyword:any) { 
    //do some activity using }

please note : you can use this.router.navigate( ['search'] instead of this.router.navigate( ['.']

Better yet - just HTML:

<a [routerLink]="[]" [queryParams]="{key: 'value'}">Your Query Params Link</a>

Note the empty array instead of just doing routerLink="" or [routerLink]="''"

You can navigate to the current route with new query params, which will not reload your page, but will update query params.

Something like (in the component):

constructor(private router: Router) { }

public myMethodChangingQueryParams() {
  const queryParams: Params = { myParam: 'myNewValue' };

  this.router.navigate(
    [], 
    {
      relativeTo: activatedRoute,
      queryParams: queryParams, 
      queryParamsHandling: 'merge', // remove to replace all query params by provided
    });
}

Note, that whereas it won't reload the page, it will push a new entry to the browser's history. If you want to replace it in the history instead of adding new value there, you could use { queryParams: queryParams, replaceUrl: true }.

EDIT: As already pointed out in the comments, [] and the relativeTo property was missing in my original example, so it could have changed the route as well, not just query params. The proper this.router.navigate usage will be in this case:

this.router.navigate(
  [], 
  {
    relativeTo: this.activatedRoute,
    queryParams: { myParam: 'myNewValue' },
    queryParamsHandling: 'merge'
  });

Setting the new parameter value to null will remove the param from the URL.

The answer with most vote partially worked for me. The browser url stayed the same but my routerLinkActive was not longer working after navigation.

My solution was to use lotation.go:

import { Component } from "@angular/core";
import { Location } from "@angular/common";
import { HttpParams } from "@angular/common/http";

export class whateverComponent {
  constructor(private readonly location: Location, private readonly router: Router) {}

  addQueryString() {
    const params = new HttpParams();
    params.append("param1", "value1");
    params.append("param2", "value2");
    this.location.go(this.router.url.split("?")[0], params.toString());
  }
}

I used HttpParams to build the query string since I was already using it to send information with httpClient. but you can just build it yourself.

and the this._router.url.split("?")[0], is to remove all previous query string from current url.

@Radoslaw Roszkowiak's answer is almost right except that relativeTo: this.route is required as below:

constructor(
  private router: Router,
  private route: ActivatedRoute,
) {}

changeQuery() {
  this.router.navigate(['.'], { relativeTo: this.route, queryParams: { ... }});
}

Try

this.router.navigate([], { 
  queryParams: {
    query: value
  }
});

will work for same route navigation other than single quotes.

In Angular 5 you can easily obtain and modify a copy of the urlTree by parsing the current url. This will include query params and fragments.

  let urlTree = this.router.parseUrl(this.router.url);
  urlTree.queryParams['newParamKey'] = 'newValue';

  this.router.navigateByUrl(urlTree); 

The "correct way" to modify a query parameter is probably with the createUrlTree like below which creates a new UrlTree from the current while letting us modify it using NavigationExtras.

import { Router } from '@angular/router';

constructor(private router: Router) { }

appendAQueryParam() {

  const urlTree = this.router.createUrlTree([], {
    queryParams: { newParamKey: 'newValue' },
    queryParamsHandling: "merge",
    preserveFragment: true });

  this.router.navigateByUrl(urlTree); 
}

In order to remove a query parameter this way you can set it to undefined or null.