Count Vowels in String Python

Question

I m trying to count how many occurrences there are of specific characters in a string  but the output is wrong   Here is my code   inputString   str input  Please type a sentence      a    a  A    A  e    e  E    E  i    i  I    I  o    o  O    O  u    u  U    U  acount   0 ecount   0 icount   0 ocount   0 ucount   0  if A or a in stri        acount   acount   1  if E or e in stri        ecount   ecount   1  if I or i in stri       icount   icount   1  if o or O in stri        ocount   ocount   1  if u or U in stri        ucount   ucount   1  print acount  ecount  icount  ocount  ucount    If I enter the letter A the output would be  1 1 1 1 1

User · Answer

You could use regex and dict comprehension:

import re
s = "aeiouuaaieeeeeeee"

The regex function findall() returns a list containing all matches

Here x is the key and the lenght of the list returned by the regex is the count of each vowel in this string, note that regex will find any character you introduce into the "aeiou" string.

foo = {x: len(re.findall(f"{x}", s)) for x in "aeiou"}
print(foo)

returns:

{'a': 3, 'e': 9, 'i': 2, 'o': 1, 'u': 2}

User · Answer

string1  I love my India   vowel  aeiou   for i in vowel    print i    quot - gt  quot    str string1 count i

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def vowels        numOfVowels 0     user input  enter the sentence         for vowel in user          if vowel in  aeiouAEIOU               numOfVowels numOfVowels 1     return numOfVowels print  The number of vowels are    str vowels

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data   str input  Please type a sentence      vowels    aeiou  for v in vowels      print v  data lower   count v

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from collections import Counter  count   Counter   inputString   str input  quot Please type a sentence   quot     for i in inputString      if i in  quot aeiouAEIOU quot             count update i            print count

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count   0 s    azcbobobEgghakl  s   s lower   for i in range 0  len s        if s i      a or s i      e or s i      i or s i      o or s i      u           count    1 print  Number of vowels    str count

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count   0   string   raw input  Type a sentence and I will count the vowels    lower    for char in string       if char in  aeiou            count    1  print count

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1    usr bin python   2    3 a   raw input  Enter the statement       4    5             To count number of words in the statement              6    7 words   len a split         8 print  Number of words in the statement are   r   words    9   10             To count vowels in the statement             11   12 print   n   Below is the vowel s count in the statement    n   13 vowels    aeiou   14   15 for key in vowels   16     print  key       a lower   count key   17

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def count vowel        cnt   0     s    abcdiasdeokiomnguu      s len   len s      s len   s len - 1     while s len  gt   0          if s s len  in   aeiou                cnt    1         s len -  1     print  numofVowels      str cnt      return cnt  def main        print count vowel     main

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gt  gt  gt  string    aswdrtio   gt  gt  gt   string lower   count x  for x in  aeiou    1  0  1  1  0

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I wrote a code used to count vowels  You may use this to count any character of your choosing  I hope this helps   coded in Python 3 6 0   while True   phrase   input  Enter phrase you wish to count vowels     if phrase     end    This will to be used to end the loop      quit    You may use break command if you don t wish to quit lower   str lower phrase   Will make string lower case convert   list lower   Convert sting into a list a   convert count  a    This will count letter for the letter a e   convert count  e   i   convert count  i   o   convert count  o   u   convert count  u    vowel   a   e   i   o   u  Used to find total sum of vowels  print   Total vowels      vowel  print   a      a  print   e      e  print   i      i  print   o      o  print   u      u

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count   0 name raw input  Enter your name    for letter in name      if letter in   A   E   I   O   U   a   e   i   o   u            count count   1 print  You have   count   vowels in your name

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Suppose   S    Combination   import re print re findall  a e i o u   S    Prints    o    i    a    i    o       For your case in a sentence  Case1     txt    blah blah blah       import re txt   re sub    r t n d                                  txt  txt   re sub   s 2          txt  txt   txt strip   words   txt split       for w in words      print w  len re findall  a e i o u   w        Case2   import re   from nltk tokenize import word tokenize  for w in work tokenize txt           print w  len re findall  a e i o u   w

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def countvowels string       num vowels 0     for char in string          if char in  aeiouAEIOU              num vowels   num vowels 1     return num vowels    remember the spacing s

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Simplest Answer   inputString   str input  Please type a sentence       vowel count   0  inputString  inputString lower    vowel count  inputString count  a   vowel count  inputString count  e   vowel count  inputString count  i   vowel count  inputString count  o   vowel count  inputString count  u    print vowel count

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Another solution with list comprehension  vowels     quot a quot    quot e quot    quot i quot    quot o quot    quot u quot    def vowel counter str     return len  char for char in str if char in vowels    print vowel counter  quot abracadabra quot      5

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This works for me and also counts the consonants as well  think of it as a bonus  however  if you really don t want the consonant count all you have to do is delete the last for loop and the last variable at the top   Her is the python code   data   input  Please give me a string     data   data lower   vowels     a   e   i   o   u   consonants     b   c   d   f   g   h   j   k   l   m   n   p   q   r   s   t   v   w   x   y   z   vowelCount   0 consonantCount   0   for string in data      for i in vowels          if string    i              vowelCount    1     for i in consonants          if string    i              consonantCount    1  print  Your string contains  s vowels and  s consonants     vowelCount  consonantCount

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What you want can be done quite simply like so    gt  gt  gt  mystr   input  Please type a sentence     Please type a sentence  abcdE  gt  gt  gt  print  map mystr lower   count   aeiou    1 1 0 0 0  gt  gt  gt    In case you don t know them  here is a reference on map and one on the

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vowels    aioue  text   input  Please enter your text     count   0  for i in text      if i in vowels          count    1  print  There are   count   vowels in your text

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gt  gt  gt  sentence   input  Sentence     Sentence  this is a sentence  gt  gt  gt  counts    i 0 for i in  aeiouAEIOU    gt  gt  gt  for char in sentence        if char in counts          counts char     1       gt  gt  gt  for k v in counts items          print k  v       a 1 e 3 u 0 U 0 O 0 i 2 E 0 o 0 A 0 I 0

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For anyone who looking the most simple solution  here s the one  vowel     a    e    i    o    u   Sentence   input  Enter a phrase     count   0 for letter in Sentence      if letter in vowel          count    1 print count

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sentence   input  Enter a sentence     upper    create two lists vowels     A   E   I    O    U   num    0 0 0 0 0    loop through every char for i in range len sentence     for every char  loop through vowels   for v in range len vowels         if char matches vowels  increase num       if sentence i     vowels v           num v     1  for i in range len vowels      print vowels i       num i

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from collections import defaultdict   def count vowels word       vowels    aeiouAEIOU      count   defaultdict int      init counter     for char in word          if char in vowels              count char     1     return count   A pythonic way to count vowels in a word  not like in java or c    actually no need to preprocess the word string  no need for str strip   or str lower    But if you d like to count vowels case-insensitively  then before go into the for-loop  use str lower

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vowels     a   e   i   o   u    def checkForVowels some string      will save all counted vowel variables as key value   amountOfVowels        for i in vowels        check for lower vowel variables     if i in some string        amountOfVowels i    some string count i       check for upper vowel variables     elif i upper   in some string        amountOfVowels i upper      some string count i upper      return amountOfVowels  print checkForVowels  sOmE string      You can test this code here   https   repl it repls BlueSlateblueDecagons  So have fun hope helped a lil bit

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Use a Counter   gt  gt  gt  from collections import Counter  gt  gt  gt  c   Counter  gallahad    gt  gt  gt  print c Counter   a   3   l   2   h   1   g   1   d   1    gt  gt  gt  c  a        count of  a  characters 3   Counter is only available in Python 2 7   A solution that should work on Python 2 5 would utilize defaultdict   gt  gt  gt  from collections import defaultdict  gt  gt  gt  d   defaultdict int   gt  gt  gt  for c in s          d c    d c    1       gt  gt  gt  print dict d    a   3   h   1   l   2   g   1   d   1

User · Answer

if A or a in stri means if A or  a in stri  which is if True or  a in stri  which is always True  and same for each of your if statements   What you wanted to say is if A in stri or a in stri   This is your mistake  Not the only one - you are not really counting vowels  since you only check if string contains them once   The other issue is that your code is far from being the best way of doing it  please see  for example  this  Count vowels from raw input  You ll find a few nice solutions there  which can easily be adopted for your particular case  I think if you go in detail through the first answer  you ll be able to rewrite your code in a correct way

[python] Count Vowels in String Python

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