difference between new String and new String in java

Question

I am fresher in java  i have a doubt in java that is  String array  new String         what is the use of     here   what is the difference between String array new String    and  String array new String      when I am writing String array new String 10     got error why  Help me I am confused

User · Answer

1 THE USE OF          It initialize the array with the values       2 The difference between String array new String    and  String array new String          String array new String    and String array new String      both are   invalid statement in java       It will gives you an error that you are trying to assign String array   to String datatype  More specifically error is like this Type   mismatch  cannot convert from String   to String   3 String array new String 10     got error why       Wrong because you are defining an array of length 10   10    then   defining an array of length String 10    0

User · Answer

String array new String    and String array new String      both are invalid statement in java   It will gives you an error that you are trying to assign String array to String datatype  More specifically error is like this Type mismatch  cannot convert from String   to String

User · Answer

String array   new String    and String array   new String        No difference these are just different ways of declaring array  String array new String 10     got error why    This is because you can not declare the size of the array in this format   right way is  String array   new String    a   b

User · Answer

defines the contents of the array  in this case it is empty  These would both have an array of three Strings String   array     quot element1 quot   quot element2 quot   quot element3 quot    String   array   new String     quot element1 quot   quot element2 quot   quot element3 quot     while    on the expression side  right side of    of a statement defines the size of an intended array  e g  this would have an array of 10 locations to place Strings String   array   new String 10       But    String array   new String 10        The line you mentioned above  Was wrong because you are defining an array of length 10   10    then defining an array of length 0       and trying to set them to the same array reference  array  in one statement  Both cannot be set  Additionally The array should be defined as an array of a given type at the start of the statement like String   array   String array      array value   is saying  set an array value to a String  not to an array of Strings

User · Answer

Try this one     String   array1  new String        System out println array1 length     String   array2  new String 0     System out println array2 length     Note  there is no byte code difference between new String      and  new String 0     new String     is array initialization with values   new String 0   is array declaration only allocating memory   new String 10     is not allowed because new String 10   may be here 100 values

User · Answer

TL DR   An array variable has to be typed T    note that T can be an arry type itself -  multidimensional arrays  The length of the array must be determined either by    giving it an explicit size  can be int constant or int expression  see n below  initializing all the values inside the array  length is implicitly calculated from given elements   Any variable that is typed T   has one read-only field  length and an index operator  int  for reading writing data at certain indices    Replies     1  String   array  new String      what is the use of     here     It initializes the array with the values between      In this case 0 elements  so array length    0 and array 0  throws IndexOutOfBoundsException  0      2  what is the diff between String array new String    and String array new String        The first won t compile for two reasons while the second won t compile for one reason  The common reason is that the type of the variable array has to be an array type  String   not just String  Ignoring that  probably just a typo  the difference is   new String        size not known  compile error new String        size is known  it has 0 elements  listed inside    new String 0      size is known  it has 0 elements  explicitly sized      3  when am writing String array new String 10     got error why      Again  ignoring the missing    before array  In this case you re over-eager to tell Java what to do and you re giving conflicting data  First you tell Java that you want 10 elements for the array to hold and then you re saying you want the array to be empty via     Just make up your mind and use one of those - Java thinks      help me i am confused   Examples  String   noStrings   new String 0   String   noStrings   new String        String   oneString   new String      atIndex0     String   oneString   new String 1   String   oneString   new String     null       same as previous String   threeStrings   new String      atIndex0    atIndex1    atIndex2     String   threeStrings   new String      atIndex0   null   atIndex2        you can skip an index String   threeStrings   new String 3   String   threeStrings   new String     null  null  null       same as previous int   twoNumbers   new int 2   int   twoNumbers   new int     0  0       same as above int   twoNumbers   new int     1  2       twoNumbers length    2  amp  amp  twoNumbers 0     1  amp  amp  twoNumbers 1     2 int n   2  int   nNumbers   new int n      same as  2  and   0  0   int   nNumbers   new int 2 n      same as new int 4  if n    2    Here   same as  means it will construct the same array

User · Answer

You have a choice  when you create an object array  as opposed to an array of primitives      One option is to specify a size for the array  in which case it will just contain lots of nulls   String   array   new String 10      Array of size 10  filled with nulls    The other option is to specify what will be in the array   String   array   new String     Larry    Curly    Moe        Array of size 3  filled with stooges    But you can t mix the two syntaxes   Pick one or the other

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