Check if a number is odd or even in python

Question

I m trying to make a program which checks if a word is a palindrome and I ve gotten so far and it works with words that have an even amount of numbers  I know how to make it do something if the amount of letters is odd but I just don t know how to find out if a number is odd  Is there any simple way to find if a number is odd or even   Just for reference  this is my code   a   0  while a    0      print   n  n    100      print  Please enter a word to check if it is a palindrome         word   input             wordLength   int len word       finalWordLength   int wordLength   2      firstHalf   word  finalWordLength      secondHalf   word finalWordLength   1       secondHalf   secondHalf   -1      print firstHalf      print secondHalf       if firstHalf    secondHalf          print  This is a palindrom       else          print  This is not a palindrom         print  Press enter to restart       input     Thanks

User · Accepted Answer

if num   2    0      pass   Even  else      pass   Odd   The   sign is like division only it checks for the remainder  so if the number divided by 2 has a remainder of 0 it s even otherwise odd   Or reverse them for a little speed improvement  since any number above 0 is also considered  True  you can skip needing to do any equality check   if num   2      pass   Odd else      pass   Even

User · Answer

Use the modulo operator       if wordLength   2    0      print  wordLength is even  else      print  wordLength is odd      For your problem  the simplest is to check if the word is equal to its reversed brother  You can do that with word   -1   which create the list from word by taking every character from the end to the start   def is palindrome word       return word    word   -1

User · Answer

The middle letter of an odd-length word is irrelevant in determining whether the word is a palindrome  Just ignore it   Hint  all you need is a slight tweak to the following line to make this work for all word lengths   secondHalf   word finalWordLength   1     P S  If you insist on handling the two cases separately  if len word    2      would tell you that the word has an odd number of characters

User · Answer

Similarly to other languages  the fastest  quot modulo 2 quot   odd even  operation is done using the bitwise and operator  if x  amp  1      return  odd  else      return  even   Using Bitwise AND operator  The idea is to check whether the last bit of the number is set or not  If last bit is set then the number is odd  otherwise even  If a number is odd  amp   bitwise AND  of the Number by 1 will be 1  because the last bit would already be set  Otherwise it will give 0 as output

User · Answer

One of the simplest ways is to use de modulus operator    If n   2    0  then your number is even   Hope it helps

User · Answer

It shouldn t matter if the word has an even or odd amount fo letters   def is palindrome word       if word    word   -1           return True     else          return False

[python] Check if a number is odd or even in python

Examples related to python