YearMonth
For completeness, and more elegant in my opinion, see this use of YearMonth
class.
YearMonth month = YearMonth.from(date);
LocalDate start = month.atDay(1);
LocalDate end = month.atEndOfMonth();
For the first & last day of the current month, this becomes:
LocalDate start = YearMonth.now().atDay(1);
LocalDate end = YearMonth.now().atEndOfMonth();
Just here to show my implementation for @herman solution
ZoneId americaLaPazZone = ZoneId.of("UTC-04:00");
static Date firstDateOfMonth(Date date) {
LocalDate localDate = convertToLocalDateWithTimezone(date);
YearMonth baseMonth = YearMonth.from(localDate);
LocalDateTime initialDate = baseMonth.atDay(firstDayOfMonth).atStartOfDay();
return Date.from(initialDate.atZone(americaLaPazZone).toInstant());
}
static Date lastDateOfMonth(Date date) {
LocalDate localDate = convertToLocalDateWithTimezone(date);
YearMonth baseMonth = YearMonth.from(localDate);
LocalDateTime lastDate = baseMonth.atEndOfMonth().atTime(23, 59, 59);
return Date.from(lastDate.atZone(americaLaPazZone).toInstant());
}
static LocalDate convertToLocalDateWithTimezone(Date date) {
return LocalDateTime.from(date.toInstant().atZone(americaLaPazZone)).toLocalDate();
}
Just use withDayOfMonth
, and lengthOfMonth()
:
LocalDate initial = LocalDate.of(2014, 2, 13);
LocalDate start = initial.withDayOfMonth(1);
LocalDate end = initial.withDayOfMonth(initial.lengthOfMonth());
You can try this to avoid indicating custom date and if there is need to display start and end dates of current month:
LocalDate start = LocalDate.now().minusDays(LocalDate.now().getDayOfMonth()-1);
LocalDate end = LocalDate.now().minusDays(LocalDate.now().getDayOfMonth()).plusMonths(1);
System.out.println("Start of month: " + start);
System.out.println("End of month: " + end);
Result:
> Start of month: 2019-12-01
> End of month: 2019-12-30
Try this:
LocalDate initial = LocalDate.of(2014, 2, 13);
LocalDate start = initial.withDayOfMonth(1);
LocalDate end = initial.withDayOfMonth(initial.getMonthOfYear().getLastDayOfMonth(false));
System.out.println(start);
System.out.println(end);
you can find the desire output but need to take care of parameter true/false for getLastDayOfMonth method
that parameter denotes leap year
LocalDate monthstart = LocalDate.of(year,month,1);
LocalDate monthend = monthstart.plusDays(monthstart.lengthOfMonth()-1);
if you want to do it only with the LocalDate-class:
LocalDate initial = LocalDate.of(2014, 2, 13);
LocalDate start = LocalDate.of(initial.getYear(), initial.getMonthValue(),1);
// Idea: the last day is the same as the first day of next month minus one day.
LocalDate end = LocalDate.of(initial.getYear(), initial.getMonthValue(), 1).plusMonths(1).minusDays(1);
The API was designed to support a solution that matches closely to business requirements
import static java.time.temporal.TemporalAdjusters.*;
LocalDate initial = LocalDate.of(2014, 2, 13);
LocalDate start = initial.with(firstDayOfMonth());
LocalDate end = initial.with(lastDayOfMonth());
However, Jon's solutions are also fine.
If anyone comes looking for first day of previous month and last day of previous month:
public static LocalDate firstDayOfPreviousMonth(LocalDate date) {
return date.minusMonths(1).withDayOfMonth(1);
}
public static LocalDate lastDayOfPreviousMonth(LocalDate date) {
return date.withDayOfMonth(1).minusDays(1);
}
Jon Skeets answer is right and has deserved my upvote, just adding this slightly different solution for completeness:
import static java.time.temporal.TemporalAdjusters.lastDayOfMonth;
LocalDate initial = LocalDate.of(2014, 2, 13);
LocalDate start = initial.withDayOfMonth(1);
LocalDate end = initial.with(lastDayOfMonth());
Source: Stackoverflow.com