[typescript] In Typescript, How to check if a string is Numeric

In Typescript, this shows an error saying isNaN accepts only numeric values

isNaN('9BX46B6A')

and this returns false because parseFloat('9BX46B6A') evaluates to 9

isNaN(parseFloat('9BX46B6A'))

I can still run with the error showing up in Visual Studio, but I would like to do it the right way.

Currently, I have written this modified function -

static isNaNModified = (inputStr: string) => {
    var numericRepr = parseFloat(inputStr);
    return isNaN(numericRepr) || numericRepr.toString().length != inputStr.length;
}

Update 2

This method is no longer available in rxjs v6

I'm solved it by using the isNumeric operator from rxjs library (importing rxjs/util/isNumeric

Update

import { isNumeric } from 'rxjs/util/isNumeric';

. . .

var val = "5700";
if (isNumeric(val)){
   alert("it is number !");
}

function isNumber(value: string | number): boolean
{
   return ((value != null) &&
           (value !== '') &&
           !isNaN(Number(value.toString())));
}

Simple answer: (watch for blank & null)

isNaN(+'111') = false;
isNaN(+'111r') = true;
isNaN(+'r') = true;
isNaN(+'') = false;   
isNaN(null) = false;   

https://codepen.io/CQCoder/pen/zYGEjxd?editors=1111

Whether a string can be parsed as a number is a runtime concern. Typescript does not support this use case as it is focused on compile time (not runtime) safety.

My simple solution here is:

const isNumeric = (val: string) : boolean => {
   return !isNaN(Number(val));
}

// isNumberic("2") => true
// isNumeric("hi") => false;

I would choose an existing and already tested solution. For example this from rxjs in typescript:

function isNumeric(val: any): val is number | string {
  // parseFloat NaNs numeric-cast false positives (null|true|false|"")
  // ...but misinterprets leading-number strings, particularly hex literals ("0x...")
  // subtraction forces infinities to NaN
  // adding 1 corrects loss of precision from parseFloat (#15100)
  return !isArray(val) && (val - parseFloat(val) + 1) >= 0;
}

rxjs/isNumeric.ts

Without rxjs isArray() function and with simplefied typings:

function isNumeric(val: any): boolean {
  return !(val instanceof Array) && (val - parseFloat(val) + 1) >= 0;
}

You should always test such functions with your use cases. If you have special value types, this function may not be your solution. You can test the function here.

Results are:

enum         : CardTypes.Debit   : true
decimal      : 10                : true
hexaDecimal  : 0xf10b            : true
binary       : 0b110100          : true
octal        : 0o410             : true
stringNumber : '10'              : true

string       : 'Hello'           : false
undefined    : undefined         : false
null         : null              : false
function     : () => {}          : false
array        : [80, 85, 75]      : false
turple       : ['Kunal', 2018]   : false
object       : {}                : false

As you can see, you have to be careful, if you use this function with enums.

Most of the time the value that we want to check is string or number, so here is function that i use:

const isNumber = (n: string | number): boolean => 
    !isNaN(parseFloat(String(n))) && isFinite(Number(n));

Codesandbox tests.

const willBeTrue = [0.1, '1', '-1', 1, -1, 0, -0, '0', "-0", 2e2, 1e23, 1.1, -0.1, '0.1', '2e2', '1e23', '-0.1', ' 898', '080']

const willBeFalse = ['9BX46B6A', "+''", '', '-0,1', [], '123a', 'a', 'NaN', 1e10000, undefined, null, NaN, Infinity, () => {}]

You can use the Number.isFinite() function:

Number.isFinite(Infinity);  // false
Number.isFinite(NaN);       // false
Number.isFinite(-Infinity); // false
Number.isFinite('0');       // false
Number.isFinite(null);      // false

Number.isFinite(0);         // true
Number.isFinite(2e64);      // true

Note: there's a significant difference between the global function isFinite() and the latter Number.isFinite(). In the case of the former, string coercion is performed - so isFinite('0') === true whilst Number.isFinite('0') === false.

Also, note that this is not available in IE!

if var sum=0; var x;

then, what about this? sum+=(x|0);

For full numbers (non-floats) in Angular you can use:

if (Number.isInteger(yourVariable)) { ... }