[vue.js] How to VueJS router-link active style

My page currently has Navigation.vue component. I want to make the each navigation hover and active. The 'hover' works but 'active' doesn't.

This is how Navigation.vue file looks like :

<template>
    <div>
        <nav class="navbar navbar-expand-lg fixed-top row">

                    <router-link tag="li" class="col" class-active="active" to="/" exact>TIME</router-link>
                    <router-link tag="li" class="col" class-active="active" to="/CNN" exact>CNN</router-link>
                    <router-link tag="li" class="col" class-active="active" to="/TechCrunch" exact>TechCrunch</router-link>
                    <router-link tag="li" class="col" class-active="active" to="/BBCSport" exact>BBC Sport</router-link>
        </nav>
    </div>
</template>

And the following is the style.

<style>

   nav li:hover,
   nav li:active{
      background-color: indianred;
      cursor: pointer;
    }

</style>

This is how hover looks like now and expected exactly same on active. This is how hover looks like now and expected exactly same on active.

I would appreciate if you give me an advice for styling router-link active works. Thanks.

This question is related to vue.js vue-router routerlink

The answer is


Just add to @Bert's solution to make it more clear:

    const routes = [
  { path: '/foo', component: Foo },
  { path: '/bar', component: Bar }
]

const router = new VueRouter({
  routes,
  linkExactActiveClass: "active" // active class for *exact* links.
})

As one can see, this line should be removed:

linkActiveClass: "active", // active class for non-exact links.

this way, ONLY the current link is hi-lighted. This should apply to most of the cases.

David


As mentioned above by @Ricky vue-router automatically applies two active classes, .router-link-active and .router-link-exact-active, to the component.

So, to change active link css use:

.router-link-exact-active{
 //your desired design when link is clicked
font-weight: 700;
}

Let's make things simple, you don't need to read the document about a "custom tag" (as a 16 years web developer, I have enough this kind of tags, such as in struts, webwork, jsp, rails and now it's vuejs)

just press F12, and you will see the source code like:

    <div>
        <a href="#/topologies" class="luelue">page1</a> 
        <a href="#/" aria-current="page" class="router-link-exact-active router-link-active">page2</a> 
        <a href="#/databases" class="">page3</a>
    </div>

so just add styles for the .router-link-active or router-link-exact-active

if you want more details, check the router-link api:

https://router.vuejs.org/en/api/#router-link


When you are creating the router, you can specify the linkExactActiveClass as a property to set the class that will be used for the active router link.

const routes = [
  { path: '/foo', component: Foo },
  { path: '/bar', component: Bar }
]

const router = new VueRouter({
  routes,
  linkActiveClass: "active", // active class for non-exact links.
  linkExactActiveClass: "active" // active class for *exact* links.
})

This is documented here.


https://router.vuejs.org/en/api/router-link.html add attribute active-class="active" eg:

<ul class="nav navbar-nav">
    <router-link tag="li" active-class="active" to="/" exact><a>Home</a></router-link>
    <router-link tag="li" active-class="active" to="/about"><a>About</a></router-link>
    <router-link tag="li" active-class="active" to="/permission-list"><a>Permisison</a></router-link>
</ul>