2014-07-28
How do I find the month, year and day with moment.js given the date format above?
var check = moment(n.entry.date_entered).format("YYYY/MM/DD");
var month = check.getUTCMonth();
var day = check.entry.date_entered.getUTCDate();
var year = check.entry.date_entered.getUTCFullYear();
This question is related to
javascript
momentjs
Just try with:
var check = moment(n.entry.date_entered, 'YYYY/MM/DD');
var month = check.format('M');
var day = check.format('D');
var year = check.format('YYYY');
I am getting day, month and year using dedicated functions moment().date(), moment().month() and moment().year() of momentjs.
let day = moment('2014-07-28', 'YYYY/MM/DD').date();_x000D_
let month = 1 + moment('2014-07-28', 'YYYY/MM/DD').month();_x000D_
let year = moment('2014-07-28', 'YYYY/MM/DD').year();_x000D_
_x000D_
console.log(day);_x000D_
console.log(month);_x000D_
console.log(year);<script src="https://cdnjs.cloudflare.com/ajax/libs/moment.js/2.22.1/moment.min.js"></script>I don't know why there are 48 upvotes for @Chris Schmitz answer which is not 100% correct.
Month is in form of array and starts from 0 so to get exact value we should use 1 + moment().month()
I know this has already been answered, but I stumbled across this question and went down the path of using format, which works, but it returns them as strings when I wanted integers.
I just realized that moment comes with date, month and year methods that return the actual integers for each method.
moment().date()
moment().month() // jan=0, dec=11
moment().year()
If you are looking for answer in string values , try this
var check = moment('date/utc format');
day = check.format('dddd') // => ('Monday' , 'Tuesday' ----)
month = check.format('MMMM') // => ('January','February.....)
year = check.format('YYYY') // => ('2012','2013' ...)
Here's an example that you could use :
var myDateVariable= moment("01/01/2019").format("dddd Do MMMM YYYY")
dddd : Full day Name
Do : day of the Month
MMMM : Full Month name
YYYY : 4 digits Year
For more informations :
Source: Stackoverflow.com