[android] Android Volley - BasicNetwork.performRequest: Unexpected response code 400

Problem statement:

I am trying to access an REST API that will return a JSON object for various HTTP status codes (400, 403, 200 etc) using Volley.

For any HTTP status other than 200, it seems the 'Unexpected response code 400' is a problem. Does anyone have a way to bypass this 'error'?

Code:

protected void getLogin() {   
    final String mURL = "https://somesite.com/api/login";

    EditText username = (EditText) findViewById(R.id.username);
    EditText password = (EditText) findViewById(R.id.password);

    // Post params to be sent to the server
    HashMap<String, String> params = new HashMap<String, String>();
    params.put("username", username.getText().toString());
    params.put("password", password.getText().toString());

    JsonObjectRequest req = new JsonObjectRequest(mURL, new JSONObject(
            params), new Response.Listener<JSONObject>() {
        @Override
        public void onResponse(JSONObject response) {

            try {
                JSONObject obj = response
                        .getJSONObject("some_json_obj");

                Log.w("myApp",
                        "status code..." + obj.getString("name"));

                // VolleyLog.v("Response:%n %s", response.toString(4));

            } catch (JSONException e) {
                e.printStackTrace();
            }
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            Log.w("error in response", "Error: " + error.getMessage());
        }
    });

    // add the request object to the queue to be executed
    AppController.getInstance().addToRequestQueue(req);
}

You mean that want to get status codes?

VolleyError has a member variable type of NetworkResponse and it is public.

You can access error.networkResponse.statusCode for http error code.

I hope it is helpful for you.

@Override
public Map<String, String> getHeaders() throws AuthFailureError {
    HashMap<String, String> headers = new HashMap<String, String>();
    headers.put("Content-Type", "application/json; charset=utf-8");
    return headers;
}

You need to add Content-Type to the header.

change

public static final String URL = "http://api-Location";

to

public static final String URL = "https://api-Location"

it's happen because i'm using 000webhostapp app

Me too got the same error but in my case I was calling url with blank spaces.

Then, I fixed it by parsing like below.

String url = "Your URL Link";

url = url.replaceAll(" ", "%20");

StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
                            new com.android.volley.Response.Listener<String>() {
                                @Override
                                public void onResponse(String response) {
                                ...
                                ...
                                ...

What I did was append an extra '/' to my url, e.g.:

String url = "http://www.google.com" 

to

String url = "http://www.google.com/"

in my case, I was not writing reg_url with :8080 . String reg_url = "http://192.168.29.163:8080/register.php";

Just to update all, after some deliberations, I have decided to use Async Http Client instead to solve my earlier problem. The library allows a cleaner approach (to me) to manipulate HTTP responses especially in cases where JSON objects are returned in all scenarios/HTTP statuses.

protected void getLogin() {

    EditText username = (EditText) findViewById(R.id.username); 
    EditText password = (EditText) findViewById(R.id.password); 

    RequestParams params = new RequestParams();
    params.put("username", username.getText().toString());
    params.put("password", password.getText().toString());

    RestClient.post(getHost() + "api/v1/auth/login", params,
            new JsonHttpResponseHandler() {

        @Override
        public void onSuccess(int statusCode, Header[] headers,
                JSONObject response) {

            try {

                //process JSONObject obj 
                Log.w("myapp","success status code..." + statusCode);

            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }

        @Override
        public void onFailure(int statusCode, Header[] headers,
                Throwable throwable, JSONObject errorResponse) {
            Log.w("myapp", "failure status code..." + statusCode);


            try {
                //process JSONObject obj
                Log.w("myapp", "error ..."  + errorResponse.getString("message").toString());
            } catch (JSONException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
        }
    });
}

Try this ...

 StringRequest sr = new StringRequest(type,url, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {

            // valid response
        }
    }, new Response.ErrorListener() {
        @Override
        public void onErrorResponse(VolleyError error) {
            // error
        }
    }){

@Override
    protected Map<String,String> getParams(){
        Map<String,String> params = new HashMap<String, String>();
            params.put("username", username);
            params.put("password", password);
            params.put("grant_type", "password");
        return params;
    }

    @Override
    public Map<String, String> getHeaders() throws AuthFailureError {
        Map<String,String> params = new HashMap<String, String>();
        // Removed this line if you dont need it or Use application/json
        // params.put("Content-Type", "application/x-www-form-urlencoded");
        return params;
    }