[vb.net] HTTP GET in VB.NET

What is the best way to issue a http get in VB.net? I want to get the result of a request like http://api.hostip.info/?ip=68.180.206.184

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

You should try the HttpWebRequest class.

You should try the HttpWebRequest class.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

You should try the HttpWebRequest class.

You should try the HttpWebRequest class.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
    Dim requestUrl As String = "your api"
    Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
    Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
    Dim dataStream As Stream = response.GetResponseStream()
    Dim reader As New StreamReader(dataStream)
    Dim responseFromServer As String = reader.ReadToEnd()
    Dim result = responseFromServer
    reader.Close()
    response.Close()
    Return result
End Function

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
    Dim requestUrl As String = "your api"
    Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
    Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
    Dim dataStream As Stream = response.GetResponseStream()
    Dim reader As New StreamReader(dataStream)
    Dim responseFromServer As String = reader.ReadToEnd()
    Dim result = responseFromServer
    reader.Close()
    response.Close()
    Return result
End Function