[vb.net] HTTP GET in VB.NET

What is the best way to issue a http get in VB.net? I want to get the result of a request like http://api.hostip.info/?ip=68.180.206.184

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
    Dim requestUrl As String = "your api"
    Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
    Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
    Dim dataStream As Stream = response.GetResponseStream()
    Dim reader As New StreamReader(dataStream)
    Dim responseFromServer As String = reader.ReadToEnd()
    Dim result = responseFromServer
    reader.Close()
    response.Close()
    Return result
End Function

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

You should try the HttpWebRequest class.

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

The easiest way is System.Net.WebClient.DownloadFile or DownloadString.

You should try the HttpWebRequest class.

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Public Function getLoginresponce(ByVal email As String, ByVal password As String) As String
    Dim requestUrl As String = "your api"
    Dim request As HttpWebRequest = TryCast(WebRequest.Create(requestUrl), HttpWebRequest)
    Dim response As HttpWebResponse = TryCast(request.GetResponse(), HttpWebResponse)
    Dim dataStream As Stream = response.GetResponseStream()
    Dim reader As New StreamReader(dataStream)
    Dim responseFromServer As String = reader.ReadToEnd()
    Dim result = responseFromServer
    reader.Close()
    response.Close()
    Return result
End Function

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

You can use the HttpWebRequest class to perform a request and retrieve a response from a given URL. You'll use it like:

Try
    Dim fr As System.Net.HttpWebRequest
    Dim targetURI As New Uri("http://whatever.you.want.to.get/file.html")         

    fr = DirectCast(HttpWebRequest.Create(targetURI), System.Net.HttpWebRequest)
    If (fr.GetResponse().ContentLength > 0) Then
        Dim str As New System.IO.StreamReader(fr.GetResponse().GetResponseStream())
        Response.Write(str.ReadToEnd())
        str.Close(); 
    End If   
Catch ex As System.Net.WebException
   'Error in accessing the resource, handle it
End Try

HttpWebRequest is detailed at: http://msdn.microsoft.com/en-us/library/system.net.httpwebrequest.aspx

A second option is to use the WebClient class, this provides an easier to use interface for downloading web resources but is not as flexible as HttpWebRequest:

Sub Main()
    'Address of URL
    Dim URL As String = http://whatever.com
    ' Get HTML data
    Dim client As WebClient = New WebClient()
    Dim data As Stream = client.OpenRead(URL)
    Dim reader As StreamReader = New StreamReader(data)
    Dim str As String = ""
    str = reader.ReadLine()
    Do While str.Length > 0
        Console.WriteLine(str)
        str = reader.ReadLine()
    Loop
End Sub

More info on the webclient can be found at: http://msdn.microsoft.com/en-us/library/system.net.webclient.aspx

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

You should try the HttpWebRequest class.

Try this:

WebRequest request = WebRequest.CreateDefault(RequestUrl);
request.Method = "GET";

WebResponse response;
try { response = request.GetResponse(); }
catch (WebException exc) { response = exc.Response; }

if (response == null)
    throw new HttpException((int)HttpStatusCode.NotFound, "The requested url could not be found.");

using(StreamReader reader = new StreamReader(response.GetResponseStream())) {
    string requestedText = reader.ReadToEnd();

    // do what you want with requestedText
}

Sorry about the C#, I know you asked for VB, but I didn't have time to convert.

Use the WebRequest class

This is to get an image:

Try
    Dim _WebRequest As System.Net.WebRequest = Nothing
    _WebRequest = System.Net.WebRequest.Create(http://api.hostip.info/?ip=68.180.206.184)
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try

Try
    _NormalImage = Image.FromStream(_WebRequest.GetResponse().GetResponseStream())
Catch ex As Exception
    Windows.Forms.MessageBox.Show(ex.Message)
    Exit Sub
End Try