[java] How do I print the content of httprequest request?

I've got a bug involving httprequest, which happens sometimes, so I'd like to log HttpGet and HttpPost request's content when that happens.

So, let's say, I create HttpGet like this:

HttpGet g = new HttpGet();
g.setURI(new URI("http://www.google.com"));
g.setHeader("test", "hell yeah");

This is the string representation that I'd like to get:

GET / HTTP/1.1
Host: www.google.com
test: hell yeah

With the post request, I'd also like to get the content string.

What is the easiest way to do it in java for android?

In case someone also want to dump response like me. i avoided to dump response body. following code just dump the StatusCode and Headers.

static private String dumpResponse(HttpServletResponse resp){
    StringBuilder sb = new StringBuilder();

    sb.append("Response Status = [" + resp.getStatus() + "], ");
    String headers = resp.getHeaderNames().stream()
                    .map(headerName -> headerName + " : " + resp.getHeaders(headerName) )
                    .collect(Collectors.joining(", "));

    if (headers.isEmpty()) {
        sb.append("Response headers: NONE,");
    } else {
        sb.append("Response headers: "+headers+",");
    }

    return sb.toString();
}

More details that help in logging

    String client = request.getRemoteAddr();
    logger.info("###### requested client: {} , Session ID : {} , URI :" + request.getMethod() + ":" + request.getRequestURI() + "", client, request.getSession().getId());

    Map params = request.getParameterMap();
    Iterator i = params.keySet().iterator();
    while (i.hasNext()) {
        String key = (String) i.next();
        String value = ((String[]) params.get(key))[0];
        logger.info("###### Request Param Name : {} , Value :  {} ", key, value);
    }

Rewrite @Juned Ahsan solution via stream in one line (headers are treated the same way):

public static String printRequest(HttpServletRequest req) {
    String params = StreamSupport.stream(
            ((Iterable<String>) () -> req.getParameterNames().asIterator()).spliterator(), false)
            .map(pName -> pName + '=' + req.getParameter(pName))
            .collect(Collectors.joining("&"));
    return req.getRequestURI() + '?' + params;
}

See also how to convert an iterator to a stream solution.

This should be more helpful for debug. Answer from @Juned Ahsan will not specify full URL and will not print multiple headers/parameters.

private String httpServletRequestToString(HttpServletRequest request) {
    StringBuilder sb = new StringBuilder();

    sb.append("Request Method = [" + request.getMethod() + "], ");
    sb.append("Request URL Path = [" + request.getRequestURL() + "], ");

    String headers =
        Collections.list(request.getHeaderNames()).stream()
            .map(headerName -> headerName + " : " + Collections.list(request.getHeaders(headerName)) )
            .collect(Collectors.joining(", "));

    if (headers.isEmpty()) {
        sb.append("Request headers: NONE,");
    } else {
        sb.append("Request headers: ["+headers+"],");
    }

    String parameters =
        Collections.list(request.getParameterNames()).stream()
            .map(p -> p + " : " + Arrays.asList( request.getParameterValues(p)) )
            .collect(Collectors.joining(", "));             

    if (parameters.isEmpty()) {
        sb.append("Request parameters: NONE.");
    } else {
        sb.append("Request parameters: [" + parameters + "].");
    }

    return sb.toString();
}

If you want the content string and this string does not have parameters you can use

    String line = null;
    BufferedReader reader = request.getReader();
    while ((line = reader.readLine()) != null){
        System.out.println(line);
    }