I have this string
'john smith~123 Street~Apt 4~New York~NY~12345'
Using JavaScript, what is the fastest way to parse this into
var name = "john smith";
var street= "123 Street";
//etc...
This question is related to
javascript
string-split
well, easiest way would be something like:
var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
JavaScript: Convert String to Array JavaScript Split
var str = "This-javascript-tutorial-string-split-method-examples-tutsmake."_x000D_
_x000D_
var result = str.split('-'); _x000D_
_x000D_
console.log(result);_x000D_
_x000D_
document.getElementById("show").innerHTML = result; <html>_x000D_
<head>_x000D_
<title>How do you split a string, breaking at a particular character in javascript?</title>_x000D_
</head>_x000D_
<body>_x000D_
_x000D_
<p id="show"></p> _x000D_
_x000D_
</body>_x000D_
</html>https://www.tutsmake.com/javascript-convert-string-to-array-javascript/
//basic url=http://localhost:58227/ExternalApproval.html?Status=1
var ar= [url,statu] = window.location.href.split("=");
You don't need jQuery.
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
Use this code --
function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");
}
split() method in JavaScript is used to convert a string to an array.
It takes one optional argument, as a character, on which to split. In your case (~).
If splitOn is skipped, it will simply put string as it is on 0th position of an array.
If splitOn is just a “”, then it will convert array of single characters.
So in your case:
var arr = input.split('~');
will get the name at arr[0] and the street at arr[1].
You can read for a more detailed explanation at Split on in JavaScript
This isn't as good as the destructuring answer, but seeing as this question was asked 12 years ago, I decided to give it an answer that also would have worked 12 years ago.
function Record(s) {
var keys = ["name", "address", "address2", "city", "state", "zip"], values = s.split("~"), i
for (i = 0; i<keys.length; i++) {
this[keys[i]] = values[i]
}
}
var record = new Record('john smith~123 Street~Apt 4~New York~NY~12345')
record.name // contains john smith
record.address // contains 123 Street
record.address2 // contains Apt 4
record.city // contains New York
record.state // contains NY
record.zip // contains zip
You don't need jQuery.
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
Since the splitting on commas question is duplicated to this question, adding this here.
If you want to split on a character and also handle extra whitespace that might follow that character, which often happens with commas, you can use replace then split, like this:
var items = string.replace(/,\s+/, ",").split(',')
If Spliter is found then only
Split it
else return the same string
function SplitTheString(ResultStr) { if (ResultStr != null) { var SplitChars = '~'; if (ResultStr.indexOf(SplitChars) >= 0) { var DtlStr = ResultStr.split(SplitChars); var name = DtlStr[0]; var street = DtlStr[1]; } } }
According to ECMAScript6 ES6, the clean way is destructuring arrays:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
_x000D_
const [name, street, unit, city, state, zip] = input.split('~');_x000D_
_x000D_
console.log(name); // john smith_x000D_
console.log(street); // 123 Street_x000D_
console.log(unit); // Apt 4_x000D_
console.log(city); // New York_x000D_
console.log(state); // NY_x000D_
console.log(zip); // 12345You may have extra items in the input string. In this case, you can use rest operator to get an array for the rest or just ignore them:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
_x000D_
const [name, street, ...others] = input.split('~');_x000D_
_x000D_
console.log(name); // john smith_x000D_
console.log(street); // 123 Street_x000D_
console.log(others); // ["Apt 4", "New York", "NY", "12345"]I supposed a read-only reference for values and used the const declaration.
Enjoy ES6!
Even though this is not the simplest way, you could do this:
var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
keys = "name address1 address2 city state zipcode".split(" "),
address = {};
// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
address[ keys.unshift() ] = match;
});
// address will contain the mapped result
address = {
address1: "123 Street"
address2: "Apt 4"
city: "New York"
name: "john smith"
state: "NY"
zipcode: "12345"
}
Update for ES2015, using destructuring
const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);
// The variables defined above now contain the appropriate information:
console.log(address1, address2, city, name, state, zipcode);
// -> john smith 123 Street Apt 4 New York NY 12345
well, easiest way would be something like:
var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
Use this code --
function myFunction() {
var str = "How are you doing today?";
var res = str.split("/");
}
This isn't as good as the destructuring answer, but seeing as this question was asked 12 years ago, I decided to give it an answer that also would have worked 12 years ago.
function Record(s) {
var keys = ["name", "address", "address2", "city", "state", "zip"], values = s.split("~"), i
for (i = 0; i<keys.length; i++) {
this[keys[i]] = values[i]
}
}
var record = new Record('john smith~123 Street~Apt 4~New York~NY~12345')
record.name // contains john smith
record.address // contains 123 Street
record.address2 // contains Apt 4
record.city // contains New York
record.state // contains NY
record.zip // contains zip
This string.split("~")[0]; gets things done.
source: String.prototype.split()
Another functional approach using curry and function composition.
So the first thing would be the split function. We want to make this "john smith~123 Street~Apt 4~New York~NY~12345" into this ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]
const split = (separator) => (text) => text.split(separator);
const splitByTilde = split('~');
So now we can use our specialized splitByTilde function. Example:
splitByTilde("john smith~123 Street~Apt 4~New York~NY~12345") // ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]
To get the first element we can use the list[0] operator. Let's build a first function:
const first = (list) => list[0];
The algorithm is: split by the colon and then get the first element of the given list. So we can compose those functions to build our final getName function. Building a compose function with reduce:
const compose = (...fns) => (value) => fns.reduceRight((acc, fn) => fn(acc), value);
And now using it to compose splitByTilde and first functions.
const getName = compose(first, splitByTilde);
let string = 'john smith~123 Street~Apt 4~New York~NY~12345';
getName(string); // "john smith"
Something like:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
Since the splitting on commas question is duplicated to this question, adding this here.
If you want to split on a character and also handle extra whitespace that might follow that character, which often happens with commas, you can use replace then split, like this:
var items = string.replace(/,\s+/, ",").split(',')
well, easiest way would be something like:
var address = theEncodedString.split(/~/)
var name = address[0], street = address[1]
split() method in JavaScript is used to convert a string to an array.
It takes one optional argument, as a character, on which to split. In your case (~).
If splitOn is skipped, it will simply put string as it is on 0th position of an array.
If splitOn is just a “”, then it will convert array of single characters.
So in your case:
var arr = input.split('~');
will get the name at arr[0] and the street at arr[1].
You can read for a more detailed explanation at Split on in JavaScript
You can use split to split the text.
As an alternative, you can also use match as follow
var str = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
matches = str.match(/[^~]+/g);_x000D_
_x000D_
console.log(matches);_x000D_
document.write(matches);The regex [^~]+ will match all the characters except ~ and return the matches in an array. You can then extract the matches from it.
You don't need jQuery.
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
If Spliter is found then only
Split it
else return the same string
function SplitTheString(ResultStr) { if (ResultStr != null) { var SplitChars = '~'; if (ResultStr.indexOf(SplitChars) >= 0) { var DtlStr = ResultStr.split(SplitChars); var name = DtlStr[0]; var street = DtlStr[1]; } } }
According to ECMAScript6 ES6, the clean way is destructuring arrays:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
_x000D_
const [name, street, unit, city, state, zip] = input.split('~');_x000D_
_x000D_
console.log(name); // john smith_x000D_
console.log(street); // 123 Street_x000D_
console.log(unit); // Apt 4_x000D_
console.log(city); // New York_x000D_
console.log(state); // NY_x000D_
console.log(zip); // 12345You may have extra items in the input string. In this case, you can use rest operator to get an array for the rest or just ignore them:
const input = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
_x000D_
const [name, street, ...others] = input.split('~');_x000D_
_x000D_
console.log(name); // john smith_x000D_
console.log(street); // 123 Street_x000D_
console.log(others); // ["Apt 4", "New York", "NY", "12345"]I supposed a read-only reference for values and used the const declaration.
Enjoy ES6!
Something like:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
Zach had this one right.. using his method you could also make a seemingly "multi-dimensional" array.. I created a quick example at JSFiddle http://jsfiddle.net/LcnvJ/2/
// array[0][0] will produce brian
// array[0][1] will produce james
// array[1][0] will produce kevin
// array[1][1] will produce haley
var array = [];
array[0] = "brian,james,doug".split(",");
array[1] = "kevin,haley,steph".split(",");
Something like:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
You can use split to split the text.
As an alternative, you can also use match as follow
var str = 'john smith~123 Street~Apt 4~New York~NY~12345';_x000D_
matches = str.match(/[^~]+/g);_x000D_
_x000D_
console.log(matches);_x000D_
document.write(matches);The regex [^~]+ will match all the characters except ~ and return the matches in an array. You can then extract the matches from it.
Even though this is not the simplest way, you could do this:
var addressString = "~john smith~123 Street~Apt 4~New York~NY~12345~",
keys = "name address1 address2 city state zipcode".split(" "),
address = {};
// clean up the string with the first replace
// "abuse" the second replace to map the keys to the matches
addressString.replace(/^~|~$/g).replace(/[^~]+/g, function(match){
address[ keys.unshift() ] = match;
});
// address will contain the mapped result
address = {
address1: "123 Street"
address2: "Apt 4"
city: "New York"
name: "john smith"
state: "NY"
zipcode: "12345"
}
Update for ES2015, using destructuring
const [address1, address2, city, name, state, zipcode] = addressString.match(/[^~]+/g);
// The variables defined above now contain the appropriate information:
console.log(address1, address2, city, name, state, zipcode);
// -> john smith 123 Street Apt 4 New York NY 12345
JavaScript: Convert String to Array JavaScript Split
var str = "This-javascript-tutorial-string-split-method-examples-tutsmake."_x000D_
_x000D_
var result = str.split('-'); _x000D_
_x000D_
console.log(result);_x000D_
_x000D_
document.getElementById("show").innerHTML = result; <html>_x000D_
<head>_x000D_
<title>How do you split a string, breaking at a particular character in javascript?</title>_x000D_
</head>_x000D_
<body>_x000D_
_x000D_
<p id="show"></p> _x000D_
_x000D_
</body>_x000D_
</html>https://www.tutsmake.com/javascript-convert-string-to-array-javascript/
Something like:
var divided = str.split("/~/");
var name=divided[0];
var street = divided[1];
Is probably going to be easiest
Zach had this one right.. using his method you could also make a seemingly "multi-dimensional" array.. I created a quick example at JSFiddle http://jsfiddle.net/LcnvJ/2/
// array[0][0] will produce brian
// array[0][1] will produce james
// array[1][0] will produce kevin
// array[1][1] will produce haley
var array = [];
array[0] = "brian,james,doug".split(",");
array[1] = "kevin,haley,steph".split(",");
This string.split("~")[0]; gets things done.
source: String.prototype.split()
Another functional approach using curry and function composition.
So the first thing would be the split function. We want to make this "john smith~123 Street~Apt 4~New York~NY~12345" into this ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]
const split = (separator) => (text) => text.split(separator);
const splitByTilde = split('~');
So now we can use our specialized splitByTilde function. Example:
splitByTilde("john smith~123 Street~Apt 4~New York~NY~12345") // ["john smith", "123 Street", "Apt 4", "New York", "NY", "12345"]
To get the first element we can use the list[0] operator. Let's build a first function:
const first = (list) => list[0];
The algorithm is: split by the colon and then get the first element of the given list. So we can compose those functions to build our final getName function. Building a compose function with reduce:
const compose = (...fns) => (value) => fns.reduceRight((acc, fn) => fn(acc), value);
And now using it to compose splitByTilde and first functions.
const getName = compose(first, splitByTilde);
let string = 'john smith~123 Street~Apt 4~New York~NY~12345';
getName(string); // "john smith"
You don't need jQuery.
var s = 'john smith~123 Street~Apt 4~New York~NY~12345';
var fields = s.split(/~/);
var name = fields[0];
var street = fields[1];
Source: Stackoverflow.com