How do I split a string breaking at a particular character

Question

I have this string   john smith 123 Street Apt 4 New York NY 12345    Using JavaScript  what is the fastest way to parse this into  var name    john smith   var street   123 Street     etc

User · Answer

You ll want to look into JavaScript s substr or split  as this is not really a task suited for jQuery

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You can use split to split the text   As an alternative  you can also use match as follow   x000D   x000D  var str    john smith 123 Street Apt 4 New York NY 12345   x000D  matches   str match        g   x000D   x000D  console log matches   x000D  document write matches   x000D   x000D   x000D    The regex       will match all the characters except   and return the matches in an array  You can then extract the matches from it

User · Answer

Something like   var divided   str split         var name divided 0   var street   divided 1     Is probably going to be easiest

User · Answer

Even though this is not the simplest way  you could do this   var addressString     john smith 123 Street Apt 4 New York NY 12345        keys    name address1 address2 city state zipcode  split           address           clean up the string with the first replace     abuse  the second replace to map the keys to the matches addressString replace        g  replace        g  function match       address  keys unshift       match          address will contain the mapped result address         address1   123 Street      address2   Apt 4      city   New York      name   john smith      state   NY      zipcode   12345        Update for ES2015  using destructuring  const  address1  address2  city  name  state  zipcode    addressString match        g       The variables defined above now contain the appropriate information   console log address1  address2  city  name  state  zipcode      - gt  john smith 123 Street Apt 4 New York NY 12345

User · Answer

Use this code --  function myFunction     var str    How are you doing today    var res   str split

User · Answer

You can use split to split the text   As an alternative  you can also use match as follow   x000D   x000D  var str    john smith 123 Street Apt 4 New York NY 12345   x000D  matches   str match        g   x000D   x000D  console log matches   x000D  document write matches   x000D   x000D   x000D    The regex       will match all the characters except   and return the matches in an array  You can then extract the matches from it

User · Answer

Use this code --  function myFunction     var str    How are you doing today    var res   str split

User · Answer

If Spliter  is found then only   Split it   else return the same string   function SplitTheString ResultStr        if  ResultStr    null            var SplitChars                if  ResultStr indexOf SplitChars   gt   0                var DtlStr   ResultStr split SplitChars               var name    DtlStr 0               var street   DtlStr 1

User · Answer

You don t need jQuery   var s    john smith 123 Street Apt 4 New York NY 12345   var fields   s split       var name   fields 0   var street   fields 1

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If Spliter  is found then only   Split it   else return the same string   function SplitTheString ResultStr        if  ResultStr    null            var SplitChars                if  ResultStr indexOf SplitChars   gt   0                var DtlStr   ResultStr split SplitChars               var name    DtlStr 0               var street   DtlStr 1

User · Answer

Zach had this one right   using his method you could also make a seemingly  multi-dimensional  array   I created a quick example at JSFiddle http   jsfiddle net LcnvJ 2      array 0  0  will produce brian    array 0  1  will produce james     array 1  0  will produce kevin    array 1  1  will produce haley  var array           array 0     brian james doug  split           array 1     kevin haley steph  split

User · Answer

Something like   var divided   str split         var name divided 0   var street   divided 1     Is probably going to be easiest

User · Answer

You don t need jQuery   var s    john smith 123 Street Apt 4 New York NY 12345   var fields   s split       var name   fields 0   var street   fields 1

User · Answer

Something like   var divided   str split         var name divided 0   var street   divided 1     Is probably going to be easiest

User · Answer

JavaScript  Convert String to Array JavaScript Split   x000D   x000D      var str    This-javascript-tutorial-string-split-method-examples-tutsmake   x000D    x000D      var result   str split  -     x000D        x000D      console log result   x000D        x000D      document getElementById  show   innerHTML   result   x000D   lt html gt  x000D   lt head gt  x000D   lt title gt How do you split a string  breaking at a particular character in javascript  lt  title gt  x000D   lt  head gt  x000D   lt body gt  x000D    x000D   lt p id  show  gt  lt  p gt   x000D    x000D   lt  body gt  x000D   lt  html gt  x000D   x000D   x000D    https   www tutsmake com javascript-convert-string-to-array-javascript

User · Answer

Since the splitting on commas question is duplicated to this question  adding this here   If you want to split on a character and also handle extra whitespace that might follow that character  which often happens with commas  you can use replace then split  like this   var items   string replace    s         split

User · Answer

Try in Plain Javascript    basic url http   localhost 58227 ExternalApproval html Status 1   var ar   url statu    window location href split  quot   quot

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This string split      0   gets things done   source  String prototype split      Another functional approach using curry and function composition   So the first thing would be the split function  We want to make this  john smith 123 Street Apt 4 New York NY 12345  into this   john smith    123 Street    Apt 4    New York    NY    12345    const split    separator    gt   text    gt  text split separator   const splitByTilde   split         So now we can use our specialized splitByTilde function  Example   splitByTilde  john smith 123 Street Apt 4 New York NY 12345        john smith    123 Street    Apt 4    New York    NY    12345     To get the first element we can use the list 0  operator  Let s build a first function   const first    list    gt  list 0     The algorithm is  split by the colon and then get the first element of the given list  So we can compose those functions to build our final getName function  Building a compose function with reduce   const compose       fns    gt   value    gt  fns reduceRight  acc  fn    gt  fn acc   value     And now using it to compose splitByTilde and first functions   const getName   compose first  splitByTilde    let string    john smith 123 Street Apt 4 New York NY 12345   getName string       john smith

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This isn t as good as the destructuring answer  but seeing as this question was asked 12 years ago  I decided to give it an answer that also would have worked 12 years ago  function Record s        var keys     quot name quot    quot address quot    quot address2 quot    quot city quot    quot state quot    quot zip quot    values   s split  quot   quot    i     for  i   0  i lt keys length  i              this keys i     values i           var record   new Record  john smith 123 Street Apt 4 New York NY 12345    record name    contains john smith record address    contains 123 Street record address2    contains Apt 4 record city    contains New York record state    contains NY record zip    contains zip

User · Answer

With JavaScript   s String prototype split function   var input    john smith 123 Street Apt 4 New York NY 12345    var fields   input split        var name   fields 0   var street   fields 1      etc

User · Answer

With JavaScript   s String prototype split function   var input    john smith 123 Street Apt 4 New York NY 12345    var fields   input split        var name   fields 0   var street   fields 1      etc

User · Answer

You don t need jQuery   var s    john smith 123 Street Apt 4 New York NY 12345   var fields   s split       var name   fields 0   var street   fields 1

User · Answer

Try in Plain Javascript    basic url http   localhost 58227 ExternalApproval html Status 1   var ar   url statu    window location href split  quot   quot

User · Answer

Even though this is not the simplest way  you could do this   var addressString     john smith 123 Street Apt 4 New York NY 12345        keys    name address1 address2 city state zipcode  split           address           clean up the string with the first replace     abuse  the second replace to map the keys to the matches addressString replace        g  replace        g  function match       address  keys unshift       match          address will contain the mapped result address         address1   123 Street      address2   Apt 4      city   New York      name   john smith      state   NY      zipcode   12345        Update for ES2015  using destructuring  const  address1  address2  city  name  state  zipcode    addressString match        g       The variables defined above now contain the appropriate information   console log address1  address2  city  name  state  zipcode      - gt  john smith 123 Street Apt 4 New York NY 12345

User · Answer

JavaScript  Convert String to Array JavaScript Split   x000D   x000D      var str    This-javascript-tutorial-string-split-method-examples-tutsmake   x000D    x000D      var result   str split  -     x000D        x000D      console log result   x000D        x000D      document getElementById  show   innerHTML   result   x000D   lt html gt  x000D   lt head gt  x000D   lt title gt How do you split a string  breaking at a particular character in javascript  lt  title gt  x000D   lt  head gt  x000D   lt body gt  x000D    x000D   lt p id  show  gt  lt  p gt   x000D    x000D   lt  body gt  x000D   lt  html gt  x000D   x000D   x000D    https   www tutsmake com javascript-convert-string-to-array-javascript

User · Answer

With JavaScript   s String prototype split function   var input    john smith 123 Street Apt 4 New York NY 12345    var fields   input split        var name   fields 0   var street   fields 1      etc

User · Answer

Since the splitting on commas question is duplicated to this question  adding this here   If you want to split on a character and also handle extra whitespace that might follow that character  which often happens with commas  you can use replace then split  like this   var items   string replace    s         split

User · Answer

well  easiest way would be something like   var address   theEncodedString split      var name   address 0   street   address 1

User · Answer

According to ECMAScript6 ES6  the clean way is destructuring arrays    x000D   x000D  const input    john smith 123 Street Apt 4 New York NY 12345   x000D   x000D  const  name  street  unit  city  state  zip    input split       x000D   x000D  console log name      john smith x000D  console log street      123 Street x000D  console log unit      Apt 4 x000D  console log city      New York x000D  console log state      NY x000D  console log zip      12345 x000D   x000D   x000D    You may have extra items in the input string  In this case  you can use rest operator to get an array for the rest or just ignore them     x000D   x000D  const input    john smith 123 Street Apt 4 New York NY 12345   x000D   x000D  const  name  street     others    input split       x000D   x000D  console log name      john smith x000D  console log street      123 Street x000D  console log others        Apt 4    New York    NY    12345   x000D   x000D   x000D    I supposed a read-only reference for values and used the const declaration   Enjoy ES6

User · Answer

According to ECMAScript6 ES6  the clean way is destructuring arrays    x000D   x000D  const input    john smith 123 Street Apt 4 New York NY 12345   x000D   x000D  const  name  street  unit  city  state  zip    input split       x000D   x000D  console log name      john smith x000D  console log street      123 Street x000D  console log unit      Apt 4 x000D  console log city      New York x000D  console log state      NY x000D  console log zip      12345 x000D   x000D   x000D    You may have extra items in the input string  In this case  you can use rest operator to get an array for the rest or just ignore them     x000D   x000D  const input    john smith 123 Street Apt 4 New York NY 12345   x000D   x000D  const  name  street     others    input split       x000D   x000D  console log name      john smith x000D  console log street      123 Street x000D  console log others        Apt 4    New York    NY    12345   x000D   x000D   x000D    I supposed a read-only reference for values and used the const declaration   Enjoy ES6

User · Answer

Something like   var divided   str split         var name divided 0   var street   divided 1     Is probably going to be easiest

User · Answer

Zach had this one right   using his method you could also make a seemingly  multi-dimensional  array   I created a quick example at JSFiddle http   jsfiddle net LcnvJ 2      array 0  0  will produce brian    array 0  1  will produce james     array 1  0  will produce kevin    array 1  1  will produce haley  var array           array 0     brian james doug  split           array 1     kevin haley steph  split

User · Answer

well  easiest way would be something like   var address   theEncodedString split      var name   address 0   street   address 1

User · Answer

well  easiest way would be something like   var address   theEncodedString split      var name   address 0   street   address 1

User · Answer

well  easiest way would be something like   var address   theEncodedString split      var name   address 0   street   address 1

User · Answer

This isn t as good as the destructuring answer  but seeing as this question was asked 12 years ago  I decided to give it an answer that also would have worked 12 years ago  function Record s        var keys     quot name quot    quot address quot    quot address2 quot    quot city quot    quot state quot    quot zip quot    values   s split  quot   quot    i     for  i   0  i lt keys length  i              this keys i     values i           var record   new Record  john smith 123 Street Apt 4 New York NY 12345    record name    contains john smith record address    contains 123 Street record address2    contains Apt 4 record city    contains New York record state    contains NY record zip    contains zip

User · Answer

You ll want to look into JavaScript s substr or split  as this is not really a task suited for jQuery

User · Answer

split   method in JavaScript is used to convert a string to an array  It takes one optional argument  as a character  on which to split  In your case      If splitOn is skipped  it will simply put string as it is on 0th position of an array  If splitOn is just a         then it will convert array of single characters  So in your case  var arr   input split        will get the name at arr 0  and the street at arr 1   You can read for a more detailed explanation at Split on in JavaScript

User · Answer

This string split      0   gets things done   source  String prototype split      Another functional approach using curry and function composition   So the first thing would be the split function  We want to make this  john smith 123 Street Apt 4 New York NY 12345  into this   john smith    123 Street    Apt 4    New York    NY    12345    const split    separator    gt   text    gt  text split separator   const splitByTilde   split         So now we can use our specialized splitByTilde function  Example   splitByTilde  john smith 123 Street Apt 4 New York NY 12345        john smith    123 Street    Apt 4    New York    NY    12345     To get the first element we can use the list 0  operator  Let s build a first function   const first    list    gt  list 0     The algorithm is  split by the colon and then get the first element of the given list  So we can compose those functions to build our final getName function  Building a compose function with reduce   const compose       fns    gt   value    gt  fns reduceRight  acc  fn    gt  fn acc   value     And now using it to compose splitByTilde and first functions   const getName   compose first  splitByTilde    let string    john smith 123 Street Apt 4 New York NY 12345   getName string       john smith

User · Answer

You ll want to look into JavaScript s substr or split  as this is not really a task suited for jQuery

User · Answer

split   method in JavaScript is used to convert a string to an array  It takes one optional argument  as a character  on which to split  In your case      If splitOn is skipped  it will simply put string as it is on 0th position of an array  If splitOn is just a         then it will convert array of single characters  So in your case  var arr   input split        will get the name at arr 0  and the street at arr 1   You can read for a more detailed explanation at Split on in JavaScript

User · Answer

You don t need jQuery   var s    john smith 123 Street Apt 4 New York NY 12345   var fields   s split       var name   fields 0   var street   fields 1

User · Answer

You ll want to look into JavaScript s substr or split  as this is not really a task suited for jQuery

User · Answer

With JavaScript   s String prototype split function   var input    john smith 123 Street Apt 4 New York NY 12345    var fields   input split        var name   fields 0   var street   fields 1      etc

[javascript] How do I split a string, breaking at a particular character?

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