How do I list all cron jobs for all users

Question

Is there a command or an existing script that will let me view all of a  NIX system s scheduled cron jobs at once  I d like it to include all of the user crontabs  as well as  etc crontab  and whatever s in  etc cron d  It would also be nice to see the specific commands run by run-parts in  etc crontab   Ideally  I d like the output in a nice column form and ordered in some meaningful way   I could then merge these listings from multiple servers to view the overall  schedule of events    I was about to write such a script myself  but if someone s already gone to the trouble

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Under Ubuntu or debian  you can view crontab by  var spool cron crontabs  and then a file for each user is in there  That s only for user-specific crontab s of course   For Redhat 6 7 and Centos  the crontab is under  var spool cron

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While many of the answers produce useful results  I think the hustle of maintaining a complex script for this task is not worth it  This is mainly because most distros use different cron daemons  Watch and learn  kids  amp  elders     cat  jaroslav bin ls-crons     bin bash getent passwd   awk -F     print  1      xargs -I  sh -c  crontab -l -u     sed  quot     d      d  s       quot   2 gt  dev null echo cat  etc crontab  etc anacrontab 2 gt  dev null   sed      d      d   echo run-parts --list  etc cron hourly  run-parts --list  etc cron daily  run-parts --list  etc cron weekly  run-parts --list  etc cron monthly   Run like this   sudo ls-cron  Sample output  Gentoo    sudo  jaroslav bin ls-crons  jaroslav   5          mv   java error in PHPSTORM    tmp 2 gt  dev null jaroslav 5   24         bin Find-home-files jaroslav   7       cp  T fortrabbit ssh-config fapps tsv  home jaroslav reference fortrabbit fapps jaroslav   8 1       make -C  T fortrabbit ssh-config discover-apps    gt  dev null jaroslav   7            getmail -r jazzoslav -r fortrabbit 2 gt  dev null jaroslav   1             home jaroslav bin checkmail jaroslav      9-18       getmail -r fortrabbit 2 gt  dev null  SHELL  bin bash PATH  sbin  bin  usr sbin  usr bin MAILTO root HOME   SHELL  bin sh PATH  sbin  bin  usr sbin  usr bin MAILTO root RANDOM DELAY 45 START HOURS RANGE 3-22 1   5   cron daily      nice run-parts  etc cron daily 7   25  cron weekly     nice run-parts  etc cron weekly  monthly 45 cron monthly        nice run-parts  etc cron monthly   etc cron hourly 0anacron  etc cron daily logrotate  etc cron daily man-db  etc cron daily mlocate  etc cron weekly mdadm  etc cron weekly pfl  Sample output  Ubuntu  SHELL  bin sh PATH  usr local sbin  usr local bin  sbin  bin  usr sbin  usr bin 17              root    cd    amp  amp  run-parts --report  etc cron hourly 25 6            root    test -x  usr sbin anacron      cd    amp  amp  run-parts --report  etc cron daily   47 6        7   root    test -x  usr sbin anacron      cd    amp  amp  run-parts --report  etc cron weekly   52 6    1       root    test -x  usr sbin anacron      cd    amp  amp  run-parts --report  etc cron monthly     etc cron hourly btrfs-quota-cleanup  etc cron hourly ntpdate-debian  etc cron daily apport  etc cron daily apt-compat  etc cron daily apt-show-versions  etc cron daily aptitude  etc cron daily bsdmainutils  etc cron daily dpkg  etc cron daily logrotate  etc cron daily man-db  etc cron daily mlocate  etc cron daily passwd  etc cron daily popularity-contest  etc cron daily ubuntu-advantage-tools  etc cron daily update-notifier-common  etc cron daily upstart  etc cron weekly apt-xapian-index  etc cron weekly man-db  etc cron weekly update-notifier-common   Pics Ubuntu   Gentoo

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On Solaris  for a particular known user name   crontab -l username   All other  Nix will need -u modifier   crontab -u username -l   To get all user s jobs at once on Solaris  much like other posts above   for user in   cut -f1 -d   etc passwd   do crontab -l  user 2 gt  dev null  done

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I ended up writing a script  I m trying to teach myself the finer points of bash scripting  so that s why you don t see something like Perl here   It s not exactly a simple affair  but it does most of what I need  It uses Kyle s suggestion for looking up individual users  crontabs  but also deals with  etc crontab  including the scripts launched by run-parts in  etc cron hourly   etc cron daily  etc   and the jobs in the  etc cron d directory  It takes all of those and merges them into a display something like the following   mi     h    d  m  w  user      command 09 39                root        -d  var lib php5    amp  amp  find  var lib php5  -type f -cmin     usr lib php5 maxlifetime  -print0   xargs -r -0 rm 47       8           root      rsync -axE --delete --ignore-errors    mirror   gt  dev null 17     1             root       etc cron daily apt 17     1             root       etc cron daily aptitude 17     1             root       etc cron daily find 17     1             root       etc cron daily logrotate 17     1             root       etc cron daily man-db 17     1             root       etc cron daily ntp 17     1             root       etc cron daily standard 17     1             root       etc cron daily sysklogd 27     2          7  root       etc cron weekly man-db 27     2          7  root       etc cron weekly sysklogd 13     3             archiver   usr local bin offsite-backup 2 gt  amp 1 32     3    1        root       etc cron monthly standard 36     4             yukon      home yukon bin do-daily-stuff 5      5             archiver   usr local bin update-logs  gt  dev null   Note that it shows the user  and more-or-less sorts by hour and minute so that I can see the daily schedule   So far  I ve tested it on Ubuntu  Debian  and Red Hat AS      bin bash    System-wide crontab file and cron job directory  Change these for your system  CRONTAB   etc crontab  CRONDIR   etc cron d     Single tab character  Annoyingly necessary  tab   echo -en   t      Given a stream of crontab lines  exclude non-cron job lines  replace   whitespace characters with a single space  and remove any spaces from the   beginning of each line  function clean cron lines         while read line   do         echo    line                 egrep --invert-match       s    s    alnum                       sed --regexp-extended  s  s    g                sed --regexp-extended  s           done       Given a stream of cleaned crontab lines  echo any that don t include the   run-parts command  and for those that do  show each job file in the run-parts   directory as if it were scheduled explicitly  function lookup run parts         while read line   do         match   echo    line     egrep -o  run-parts  - 1 2  S     S             if    -z    match        then             echo    line           else             cron fields   echo    line     cut -f1-6 -d                 cron job dir   echo     match     awk   print  NF                 if    -d    cron job dir        then                 for cron job file in    cron job dir       do        lt not a comment gt                         -f    cron job file       amp  amp  echo    cron fields    cron job file                   done             fi         fi     done       Temporary file for crontab lines  temp   mktemp     exit 1    Add all of the jobs from the system-wide crontab file  cat    CRONTAB     clean cron lines   lookup run parts  gt    temp       Add all of the jobs from the system-wide cron directory  cat    CRONDIR       clean cron lines  gt  gt    temp          lt not a comment gt     Add each user s crontab  if it exists   Insert the user s name between the   five time fields and the command  while read user   do     crontab -l -u    user   2 gt  dev null           clean cron lines           sed --regexp-extended  s     S     5         1  user   3    gt  gt    temp   done  lt   lt  cut --fields 1 --delimiter    etc passwd     Output the collected crontab lines  Replace the single spaces between the   fields with tab characters  sort the lines by hour and minute  insert the   header line  and format the results as a table  cat    temp         sed --regexp-extended  s    S      S      S      S      S      S           1 t 2 t 3 t 4 t 5 t 6 t 7         sort --numeric-sort --field-separator    tab   --key 2 1       sed  1i mi th td tm tw tuser tcommand        column -s   tab   -t  rm --force    temp

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The following strips away comments  empty lines  and errors from users with no crontab  All you re left with is a clear list of users and their jobs    Note the use of sudo in the 2nd line  If you re already root  remove that   for USER in   cut -f1 -d   etc passwd   do   USERTAB    sudo crontab -u   USER  -l 2 gt  amp 1       FILTERED    echo   USERTAB   grep -vE        no crontab for cannot use this program        if   test -z   FILTERED   then    echo    ------   tput bold  USER  tput sgr0  ------      echo   FILTERED      echo        fi     done   Example output      ------ root ------ 0   6        usr local bin disk-space-notify sh 45 3        opt mysql-backups mysql-backups sh 5 7        usr local bin certbot-auto renew --quiet --no-self-upgrade    ------ sammy ------ 55         wget -O - -q -t 1 https   www example com cron php  gt   dev null   I use this on Ubuntu  12 thru 16  and Red Hat  5 thru 7

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you can write for all user list    sudo crontab -u userName -l      You can also go to   cd  etc cron daily  ls -l cat filename   this file will list the schedules  cd  etc cron d  ls -l cat filename

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Depends on your linux version but I use    tail -n 1000  var spool cron     as root  Very simple and very short   Gives me output like      gt   var spool cron root  lt    15 2        bla     gt   var spool cron my user  lt      10 1        path to script

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Depends on your version of cron   Using Vixie cron on FreeBSD  I can do something like this    cd  var cron tabs  amp  amp  grep -vH          if I want it more tab deliminated  I might do something like this    cd  var cron tabs  amp  amp  grep -vH        sed  s               Where that s a literal tab in the sed replacement portion   It may be more system independent to loop through the users in  etc passwd and do crontab -l -u  user for each of them

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getent passwd   cut -d  -f1   perl -e while  lt  gt   chomp  l    crontab -u    -l 2 gt  dev null  print     n l n  if  l     This avoids messing with passwd directly  skips users that have no cron entries and for those who have them it prints out the username as well as their crontab   Mostly dropping this here though so i can find it later in case i ever need to search for it again

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This will show all crontab entries from all users   sed  s                crontab -u  1 -l 2 gt   amp 1    etc passwd   grep -v  no crontab for    sh

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This script outputs the Crontab to a file and also lists all users confirming those which have no crontab entry   for user in   cut -f1 -d   etc passwd   do    echo  user  gt  gt  crontab bak   echo     gt  gt  crontab bak   crontab -u  user -l  gt  gt  crontab bak 2 gt  gt   gt  crontab bak done

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Thanks for this very useful script  I had some tiny problems running it on old systems  Red Hat Enterprise 3  which handle differently egrep and tabs in strings   and other systems with nothing in  etc cron d   the script then ended with an error   So here is a patch to make it work in such cases    2a3 4  gt   See   http   stackoverflow com questions 134906 how-do-i-list-all-cron-jobs-for-all-users  gt  27c29 30  lt          match   echo    line     egrep -o  run-parts  - 1 2  S     S    ---  gt           match   echo    line     egrep -o  run-parts  - 1 2  S     S     gt          match   echo    line     egrep -o  run-parts     51c54 57  lt  cat    CRONDIR       clean cron lines  gt  gt    temp          lt not a comment gt  ---  gt  sys cron num   ls  etc cron d   wc -l   awk   print  1     gt  if     sys cron num     0    then  gt        cat    CRONDIR       clean cron lines  gt  gt    temp          lt not a comment gt   gt  fi 67c73  lt      sed  1i mi th td tm tw tuser tcommand    ---  gt      sed  1i mi  tab h  tab d  tab m  tab w  tab user  tab command      I m not really sure the changes in the first egrep are a good idea  but well  this script has been tested on RHEL3 4 5 and Debian5 without any problem  Hope this helps

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To get list from ROOT user   for user in   cut -f1 -d   etc passwd   do echo  user  sudo crontab -u  user -l  done

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A small refinement of Kyle Burton s answer with improved output formatting      bin bash for user in   cut -f1 -d   etc passwd  do echo  user  amp  amp  crontab -u  user -l echo     done

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Building on top of  Kyle      for user in   tail -n  11  etc passwd   cut -f1 -d    do echo  user  crontab -u  user -l  done   to avoid the comments usually at the top of  etc passwd   And on macosx      for user in   dscl   -list  users   cut -f1 -d    do echo  user  crontab -u  user -l  done

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With apologies and thanks to yukondude   I ve tried to summarise the timing settings for easy reading  though it s not a perfect job  and I don t touch  every Friday  or  only on Mondays  stuff   This is version 10 - it now    runs much much faster has optional progress characters so you could improve the speed further  uses a divider line to separate header and output  outputs in a compact format when all timing intervals uencountered can be summarised  Accepts Jan   Dec descriptors for months-of-the-year Accepts Mon   Sun descriptors for days-of-the-week tries to handle debian-style dummying-up of anacron when it is missing  tries to deal with crontab lines which run a file after pre-testing executability using    -x        tries to deal with crontab lines which run a file after pre-testing executability using  command -v  allows the use of interval spans and lists  supports run-parts usage in user-specific  var spool crontab files    I am now publishing the script in full here    https   gist github com myshkin-uk d667116d3e2d689f23f18f6cd3c71107

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If you check a cluster using NIS  the only way to see if a user has a crontab entry ist according to Matt s answer  var spool cron tabs   grep -v     -R   var spool cron tabs

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for user in   cut -f1 -d   etc passwd    do      echo  user  crontab -u  user -l   done

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Since it is a matter of looping through a file   etc passwd  and performing an action  I am missing the proper approach on How can I read a file  data stream  variable  line-by-line  and or field-by-field     while IFS     read -r user   do    echo  crontab for user   user       crontab -u   user  -l done  lt   etc passwd   This reads  etc passwd line by line using   as field delimiter  By saying read -r user    we make  user hold the first field and   the rest  it is just a junk variable to ignore fields    This way  we can then call crontab -u using the variable  user  which we quote for safety  what if it contains spaces  It is unlikely in such file  but you can never know

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You would have to run this as root  but   for user in   cut -f1 -d   etc passwd   do crontab -u  user -l  done   will loop over each user name listing out their crontab   The crontabs are owned by the respective users so you won t be able to see another user s crontab w o being them or root     Edit if you want to know which user a crontab belongs to  use echo  user  for user in   cut -f1 -d   etc passwd   do echo  user  crontab -u  user -l  done

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I like the simple one-liner answer above      for user in   cut -f1 -d   etc passwd   do crontab -u  user -l  done   But Solaris which does not have the -u flag and does not print the user it s checking  you can modify it like so   for user in   cut -f1 -d   etc passwd   do echo User  user  crontab -l  user 2 gt  amp 1   grep -v crontab  done   You will get a list of users without the errors thrown by crontab when an account is not allowed to use cron etc   Be aware that in Solaris  roles can be in  etc passwd too  see  etc user attr

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This script worked for me in CentOS to list all crons in the environment   sudo cat  etc passwd   sed  s                sudo crontab -u  1 -l 2 gt   amp 1     grep -v  no crontab for    sh

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I think a better one liner would be below  For example if you have users in NIS or LDAP they wouldnt be in  etc passwd   This will give you the crontabs of every user that has logged in   for I in  lastlog   grep -v Never   cut -f1 -d      do echo  I   crontab -l -u  I   done

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Under Ubuntu or debian  you can view crontab by  var spool cron crontabs  and then a file for each user is in there  That s only for user-specific crontab s of course   For Redhat 6 7 and Centos  the crontab is under  var spool cron

User · Answer

For me look at  var spool cron crontabs is the best way

[unix] How do I list all cron jobs for all users?

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