open resource with relative path in Java

Question

In my Java app I need to get some files and directories  This is the program structure    main java   package1 guiclass java   package1 resources resourcesloader java   package1 resources repository modules    - gt  this is the dir I need to get   package1 resources repository SSL-Key cert jks    - gt  this is the file I need to get  guiclass loads the resourcesloader class which will load my resources  directory and file   As to the file  I tried resourcesloader class getClass   getResource  quot repository SSL-Key cert jks quot   toString    in order to get the real path  but this way does not work  I have no idea which path to use for the directory

User · Answer

resourcesloader class getClass     Can be broken down to   Class lt resourcesloader gt  clazz   resourceloader class  Class lt Class gt  classClass   clazz getClass      Which means you re trying to load the resource using a bootstrap class   Instead you probably want something like   resourcesloader class getResource  repository SSL-Key cert jks   toString     If only javac warned about calling static methods on non-static contexts

User · Answer

Doe the following work   resourcesloader class getClass   getResource   package1 resources repository SSL-Key cert jks     Is there a reason you can t specify the full path including the package

User · Answer

GianCarlo  You can try calling System property user dir that will give you root of your java project and then do append this path to your relative path for example   String root   System getProperty  user dir    String filepath     path to yourfile txt      in case of Windows     path   to  yourfile txt String abspath   root filepath        using above path read your file into byte    File file   new File abspath   FileInputStream fis   new FileInputStream file   byte   filebytes   new byte  int file length     fis read filebytes

User · Answer

Use this   resourcesloader class getClassLoader   getResource   path to file     getPath

User · Answer

I made a small modification on  jonathan cone s one liner   by adding  getFile     to avoid null pointer exception  and setting the path to data directory  Here s what worked for me    String realmID   new java util Scanner new java io File RandomDataGenerator class getClassLoader   getResource  data aa-qa-id csv   getFile   toString     next

User · Answer

In Order to obtain real path to the file you can try this   URL fileUrl   Resourceloader class getResource  resources repository SSL-Key cert jks    String pathToClass   fileUrl getPath        Resourceloader is classname here   resources repository SSL-Key cert jks  is relative path to the file  If you had your guiclass in   package1 java with rest of folder structure remaining  you would take     resources repository SSL-Key cert jks  as relative path because of rules defining relative path   This way you can read your file with BufferedReader  DO NOT USE THE STRING to identify the path to the file  because if you have spaces or some characters from not english alphabet in your path  you will get problems and the file will not be found   BufferedReader bufferedReader   new BufferedReader                          new InputStreamReader fileUrl openStream

User · Answer

Supply the path relative to the classloader  not the class you re getting the loader from   For instance   resourcesloader class getClassLoader   getResource  package1 resources repository SSL-Key cert jks   toString

User · Answer

Going with the two answers as mentioned above  The first one  resourcesloader class getClassLoader   getResource  package1 resources repository SSL-Key cert jks   toString    resourcesloader class getResource  repository SSL-Key cert jks   toString     Should be one and same thing

User · Answer

I had problems with using the getClass   getResource  filename txt   method  Upon reading the Java docs instructions  if your resource is not in the same package as the class you are trying to access the resource from  then you have to give it relative path starting with      The recommended strategy is to put your resource files under a  resources  folder in the root directory  So for example if you have the structure   src main com mycompany myapp   then you can add a resources folder as recommended by maven in   src main resources   furthermore you can add subfolders in the resources folder  src main resources textfiles   and say that your file is called myfile txt so you have   src main resources textfiles myfile txt   Now here is where the stupid path problem comes in  Say you have a class in your com mycompany myapp package  and you want to access the myfile txt file from your resource folder  Some say you need to give the     main resources textfiles myfile txt  path   or     resources textfiles myfile txt    both of these are wrong  After I ran mvn clean compile  the files and folders are copied in the   myapp target classes    folder  But the resources folder is not there  just the folders in the resources folder  So you have   myapp target classes textfiles myfile txt  myapp target classes com mycompany myapp     so the correct path to give to the getClass   getResource     method is     textfiles myfile txt    here it is   getClass   getResource   textfiles myfile txt     This will no longer return null  but will return your class  I hope this helps somebody  It is strange to me  that the  resources  folder is not copied as well  but only the subfolders and files directly in the  resources  folder  It would seem logical to me that the  resources  folder would also be found under  myapp target classes

User · Answer

In the hopes of providing additional information for those who don t pick this up as quickly as others  I d like to provide my scenario as it has a slightly different setup  My project was setup with the following directory structure  using Eclipse     Project    src                    application source code     org        myproject          MyClass java   test                   unit tests   res                    resources     images               PNG images for icons       my-image png     xml                  XSD files for validating XML files with JAXB       my-schema xsd     conf                 default  conf file for Log4j       log4j conf   lib                    libraries added to build-path via project settings   I was having issues loading my resources from the res directory  I wanted all my resources separate from my source code  simply for managment organization purposes   So  what I had to do was add the res directory to the build-path and then access the resource via   static final ClassLoader loader   MyClass class getClassLoader        in some function loader getResource  images my-image png    loader getResource  xml my-schema xsd    loader getResource  conf log4j conf      NOTE  The   is omitted from the beginning of the resource string because I am using  ClassLoader getResource String  instead of Class getResource String

User · Answer

For those using eclipse   maven  Say you try to access the file images pic jpg in src main resources  Doing it this way     ClassLoader loader   MyClass class getClassLoader    File file   new File loader getResource  images pic jpg   getFile       is perfectly correct  but may result in a null pointer exception  Seems like eclipse doesn t recognize the folders in the maven directory structure as source folders right away  By removing and the src main resources folder from the project s source folders list and putting it back  project properties java build path  source remove add Folder   I was able to solve this

User · Answer

When you use  getResource  on a Class  a relative path is resolved based on the package the Class is in  When you use  getResource  on a ClassLoader  a relative path is resolved based on the root folder   If you use an absolute path  both  getResource  methods will start at the root folder

[java] open resource with relative path in Java

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