[sql] How can I select multiple columns from a subquery (in SQL Server) that should have one record (select top 1) for each record in the main query?

I Know I can select a column from a subquery using this syntax:

SELECT A.SalesOrderID, A.OrderDate,
       (
       SELECT TOP 1 B.Foo
       FROM B
       WHERE A.SalesOrderID = B.SalesOrderID
       ) AS FooFromB
FROM A
WHERE A.Date BETWEEN '2000-1-4' AND '2010-1-4'

But what is the correct syntax to use multiple columns from a subquery (in my case a select top 1 subquery)? Thank you very much.

select t1.*, sq.*
from table1 t1,
   (select a,b,c from table2 ...) sq
where ...

SELECT a.salesorderid, a.orderdate, s.orderdate, s.salesorderid
FROM A a
OUTER APPLY (SELECT top(1) *
             FROM B b WHERE a.salesorderid = b.salesorderid) as s
WHERE A.Date BETWEEN '2000-1-4' AND '2010-1-4'

i think that is what you want.

SELECT 
      A.SalesOrderID, 
      A.OrderDate, 
      FooFromB.*

FROM A,
     (SELECT TOP 1 B.Foo
      FROM B
      WHERE A.SalesOrderID = B.SalesOrderID
      ) AS FooFromB

WHERE A.Date BETWEEN '2000-1-4' AND '2010-1-4'

Here's generally how to select multiple columns from a subquery:

SELECT
     A.SalesOrderID,
     A.OrderDate,
     SQ.Max_Foo,
     SQ.Max_Foo2
FROM
     A
LEFT OUTER JOIN
     (
     SELECT
          B.SalesOrderID,
          MAX(B.Foo) AS Max_Foo,
          MAX(B.Foo2) AS Max_Foo2
     FROM
          B
     GROUP BY
          B.SalesOrderID
     ) AS SQ ON SQ.SalesOrderID = A.SalesOrderID

If what you're ultimately trying to do is get the values from the row with the highest value for Foo (rather than the max of Foo and the max of Foo2 - which is NOT the same thing) then the following will usually work better than a subquery:

SELECT
     A.SalesOrderID,
     A.OrderDate,
     B1.Foo,
     B1.Foo2
FROM
     A
LEFT OUTER JOIN B AS B1 ON
     B1.SalesOrderID = A.SalesOrderID
LEFT OUTER JOIN B AS B2 ON
     B2.SalesOrderID = A.SalesOrderID AND
     B2.Foo > B1.Foo
WHERE
     B2.SalesOrderID IS NULL

You're basically saying, give me the row from B where I can't find any other row from B with the same SalesOrderID and a greater Foo.

You'll have to make a join:

SELECT A.SalesOrderID, B.Foo
FROM A
JOIN B bo ON bo.id = (
     SELECT TOP 1 id
     FROM B bi
     WHERE bi.SalesOrderID = a.SalesOrderID
     ORDER BY bi.whatever
     )
WHERE A.Date BETWEEN '2000-1-4' AND '2010-1-4'

, assuming that b.id is a PRIMARY KEY on B

In MS SQL 2005 and higher you may use this syntax:

SELECT SalesOrderID, Foo
FROM (
  SELECT A.SalesOrderId, B.Foo,
         ROW_NUMBER() OVER (PARTITION BY B.SalesOrderId ORDER BY B.whatever) AS rn
  FROM A
  JOIN B ON B.SalesOrderID = A.SalesOrderID
  WHERE A.Date BETWEEN '2000-1-4' AND '2010-1-4'
) i
WHERE rn

This will select exactly one record from B for each SalesOrderId.