How to deal with the URISyntaxException

Question

I got this error message    java net URISyntaxException  Illegal character in query at index 31  http   finance yahoo com q h s  IXIC   My Url   http   finance yahoo com q h s  IXIC  When I copied it into a browser address field  it showed the correct page  it s a valid URL  but I can t parse it with this  new URI My Url   I tried   My Url My Url replace             but    It won t be the url I need It doesn t work either   How to handle this    Frank

User · Answer

You have to encode your parameters   Something like this will do   import java net    import java io     public class EncodeParameter         public static void main  String    args   throws URISyntaxException                                            UnsupportedEncodingException               String myQuery     IXIC            URI uri   new URI  String format                               http   finance yahoo com q h s  s                               URLEncoder encode  myQuery    UTF8                  System out println  uri               http   java sun com javase 6 docs api java net URLEncoder html

User · Answer

Use   encoding for the   character  viz  http   finance yahoo com q h s  5EIXIC

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Coudn t imagine nothing better for  http   server ru 8080 template get type mail amp format html amp key ecm task assignment amp label                            amp descr          amp objectid 2231 that   public static boolean checkForExternal String str        int length   str length        for  int i   0  i  lt  length  i              if  str charAt i   gt  0x7F                return true                      return false     private static final Pattern COLON   Pattern compile   3A   Pattern LITERAL   private static final Pattern SLASH   Pattern compile   2F   Pattern LITERAL   private static final Pattern QUEST MARK   Pattern compile   3F   Pattern LITERAL   private static final Pattern EQUAL   Pattern compile   3D   Pattern LITERAL   private static final Pattern AMP   Pattern compile   26   Pattern LITERAL    public static String encodeUrl String url        if  checkForExternal url             try               String value   URLEncoder encode url   UTF-8                value   COLON matcher value  replaceAll                   value   SLASH matcher value  replaceAll                   value   QUEST MARK matcher value  replaceAll                   value   EQUAL matcher value  replaceAll                   return AMP matcher value  replaceAll   amp               catch  UnsupportedEncodingException e                throw LOGGER getIllegalStateException e                   else           return url

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I had this exception in the case of a test for checking some actual accessed URLs by users   And the URLs are sometime contains an illegal-character and hang by this error   So I make a function to encode only the characters in the URL string like this    String encodeIllegalChar String uriStr String enc    throws URISyntaxException UnsupportedEncodingException     String  uriStr   uriStr    int retryCount   17    while true        try         new URI  uriStr          break        catch URISyntaxException e          String reason   e getReason           if reason    null                          reason contains  in path                reason contains  in query                reason contains  in fragment                                 throw e                  if 0  gt  retryCount--            throw e                  String input   e getInput           int idx   e getIndex           String illChar   String valueOf input charAt idx            uriStr   input replace illChar URLEncoder encode illChar enc                 return  uriStr      test   String q          amp      lt  gt          String url    http   test com  q     q         q  String eic   encodeIllegalChar url  UTF-8    System out println String format    original  s  url    System out println String format     encoded  s  eic    System out println String format     uri-obj  s  new URI eic     System out println String format  re-decoded  s  URLDecoder decode eic

User · Answer

Rather than encoding the URL beforehand you can do the following String link    quot http   example com quot   URL url   null  URI uri   null   try      url   new URL link     catch MalformedURLException e       e printStackTrace       try     uri   new URI url toString      catch URISyntaxException e      try           uri   new URI url getProtocol    url getUserInfo    url getHost                          url getPort    url getPath    url getQuery                           url getRef          catch URISyntaxException e1           e1 printStackTrace           try      url   uri toURL     catch MalfomedURLException e       e printStackTrace       String encodedLink   url toString

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If you re using RestangularV2 to post to a spring controller in java you can get this exception if you use RestangularV2 one   instead of RestangularV2 all

User · Answer

A space is encoded to  20 in URLs  and to   in forms submitted data  content type application x-www-form-urlencoded   You need the former   Using Guava   dependencies        compile  com google guava guava 28 1-jre      You can use UrlEscapers   String encodedString   UrlEscapers urlFragmentEscaper   escape inputString     Don t use String replace  this would only encode the space  Use a library instead

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Replace spaces in URL with   like If url contains dimension1 Incontinence Liners then replace it with dimension1 Incontinence Liners

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You need to encode the URI to replace illegal characters with legal encoded characters   If you first make a URL  so you don t have to do the parsing yourself  and then make a URI using the five-argument constructor  then the constructor will do the encoding for you    import java net     public class Test     public static void main String   args        String myURL    http   finance yahoo com q h s  IXIC       try         URL url   new URL myURL         String nullFragment   null        URI uri   new URI url getProtocol    url getHost    url getPath    url getQuery    nullFragment         System out println  URI     uri toString       is OK          catch  MalformedURLException e          System out println  URL     myURL     is a malformed URL          catch  URISyntaxException e          System out println  URI     myURL     is a malformed URL

User · Answer

A general solution requires parsing the URL into a RFC 2396 compliant URI  note that this is an old version of the URI standard  which java net URI uses    I have written a Java URL parsing library that makes this possible  galimatias  With this library  you can achieve your desired behaviour with this code   String urlString         URLParsingSettings settings   URLParsingSettings create      withStandard URLParsingSettings Standard RFC 2396   URL url   URL parse settings  urlString     Note that galimatias is in a very early stage and some features are experimental  but it is already quite solid for this use case

[java] How to deal with the URISyntaxException

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