[reactjs] What's the difference between "super()" and "super(props)" in React when using es6 classes?

In this example, you are extending the React.Component class, and per the ES2015 spec, a child class constructor cannot make use of this until super() has been called; also, ES2015 class constructors have to call super() if they are subclasses.

class MyComponent extends React.Component {
  constructor() {
    console.log(this); // Reference Error
  }

  render() {
    return <div>Hello {this.props.name}</div>;
  }
}

By contrast:

class MyComponent extends React.Component {
  constructor() {
    super();
    console.log(this); // this logged to console
  }

  render() {
    return <div>Hello {this.props.name}</div>;
  }
}

More detail as per this excellent stack overflow answer

You may see examples of components created by extending the React.Component class that do not call super() but you'll notice these don't have a constructor, hence why it is not necessary.

class MyOtherComponent extends React.Component {
  render() {
    return <div>Hi {this.props.name}</div>;
  }
}

One point of confusion I've seen from some developers I've spoken to is that the components that have no constructor and therefore do not call super() anywhere, still have this.props available in the render() method. Remember that this rule and this need to create a this binding for the constructor only applies to the constructor.

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