A stupid way I know is:
git diff commit-number1 commit-number2
any better way?
I mean I want to know the commit1 itself, I don't want to add the commit2 before it as parameter.
This question is related to
git
I found out that "git show --stat" is the best out of all here, gives you a brief summary of the commit, what files did you add and modify without giving you whole bunch of stuff, especially if you changed a lot files.
git show <commit>
To show what a commit did with stats:
git show <commit> --stat
To show commit log with differences introduced for each commit in a range:
git log -p <commit1> <commit2>
<commit>?Each commit has a unique id we reference here as <commit>. The unique id is an SHA-1 hash – a checksum of the content you’re storing plus a header. #TMI
If you don't know your <commit>:
git log to view the commit history
Find the commit you care about.
The answers by Bomber and Jakub (Thanks!) are correct and work for me in different situations.
For a quick glance at what was in the commit, I use
git show <replace this with your commit-id>
But I like to view a graphical Diff when studying something in detail and have set up a P4diff as my git diff and then use
git diff <replace this with your commit-id>^!
Does
$ git log -p
do what you need?
Check out the chapter on Git Log in the Git Community Book for more examples. (Or look at the the documentation.)
Update: As others (Jakub and Bombe) already pointed out: although the above works, git show is actually the command that is intended to do exactly what was asked for.
This is one way I know of. With git, there always seems to be more than one way to do it.
git log -p commit1 commit2
Source: Stackoverflow.com